Problem 43
Question
Solve the equation by using the quadratic formula. $$ 6 w-13 \sqrt{w}+6=0 $$
Step-by-Step Solution
Verified Answer
The given equation is \(6w - 13\sqrt{w} + 6 = 0\). After expanding, simplifying, and factoring, we get the equation \(w(36w + 169 - 156\sqrt{w}) = 0\). We find one solution, \(w = 0\), but the other solution cannot be found using the quadratic formula without further simplification. So the short answer is \(w = 0\).
1Step 1: Rewrite equation in quadratic form
Before we get started, let's rewrite the equation so that it is in quadratic form. We're given:
\(6w - 13\sqrt{w} + 6 = 0\)
Square both sides of the equation to eliminate the square root term:
\((6w - 13\sqrt{w} + 6)^2 = 0^2\)
Step 2: Expand the equation
2Step 2: Expanding the squared equation
Now let's expand the left-hand side of the equation using the binomial expansion formula:
\((a-b+c)^2 = a^2 - 2ab + 2ac + b^2 - 2bc + c^2\)
So we have:
\((6w)^2 - 2(6w)(13\sqrt{w}) + 2(6w)(6) + (13\sqrt{w})^2 - 2(13\sqrt{w})(6) + 6^2 = 0\)
Step 3: Simplify the expanded equation
3Step 3: Simplify the squared equation
Next, we simplify the equation by calculating the individual terms:
\(36w^2 - 156w\sqrt{w} + 72w + 169w - 156w + 36 = 0\)
Step 4: Gather like terms
4Step 4: Combining like terms
Now we can combine the like terms in the equation:
\(36w^2 + 169w - 156w\sqrt{w} = 0\)
Step 5: Factor out the GCF
5Step 5: Factor out the GCF
Factor out the greatest common factor (GCF) of the terms:
\(w(36w + 169 - 156\sqrt{w}) = 0\)
Step 6: Solve for w
6Step 6: Solving for w
Now we have two possible solutions for the equation:
1) If \(w = 0\), then the equation holds true because:
\(0(36(0) + 169 - 156\sqrt{0}) = 0\)
2) If the term inside the parentheses is equal to 0:
\(36w + 169 - 156\sqrt{w} = 0\)
Since the equation is non-standard quadratic at this point, it can't be solved using the quadratic formula without further simplification. However, we have one solution, \(w = 0\).
Key Concepts
Quadratic FormulaSolving Non-standard QuadraticsBinomial ExpansionGreatest Common Factor
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations of the standard form \(ax^2 + bx + c = 0\). It is expressed as:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Solving Non-standard Quadratics
Non-standard quadratics, such as the equation \(6w - 13\sqrt{w} + 6 = 0\), require extra steps as they do not fit the typical quadratic formula format. The key is to manipulate the equation into a recognizable form.
- First, identify any square root or non-linear components.
- Perform algebraic operations, such as squaring, to simplify.
- Advance through the setup phase to transform it into a standard quadratic format if possible.
Binomial Expansion
Binomial expansion is a technique used to expand expressions raised to a power, significantly aiding in this problem when simplifying terms. The binomial formula expands expressions such as \((a+b)^2\) using:
- \((a+b)^2 = a^2 + 2ab + b^2\)
- For three terms as in \((a-b+c)^2\), use each pair of terms product in the expansion: \(a^2 - 2ab + 2ac + b^2 - 2bc + c^2\).
Greatest Common Factor
The greatest common factor (GCF) is the largest factor that divides two or more numbers. It is essential for simplifying expressions and equations. In this context, it allowed us to simplify the equation further by factoring common elements.
- Identify common factors in the equation's terms.
- Factor out these elements to simplify the problem.
- This step can sometimes offer clear paths to potential solutions.
Other exercises in this chapter
Problem 43
Perform the indicated operations and simplify. \(\frac{\frac{1}{x^{2}}-\frac{1}{y^{2}}}{x+y}\)
View solution Problem 43
Suppose \(\boldsymbol{a}\) and \(\boldsymbol{b}\) are real numbers other than 0 and \(a>b\). State whether the inequality is true or false. $$ a^{3}>b^{3} $$
View solution Problem 43
Write the expression in simplest radical form. $$ \sqrt[3]{-54} $$
View solution Problem 43
Simplify the expression, writing your answer using positive exponents only. $$ \left(a^{2} b^{-3}\right)^{2}\left(a^{-2} b^{2}\right)^{-3} $$
View solution