Problem 43
Question
Solve each quadratic equation using the method that seems most appropriate. $$(3 x-1)(2 x+9)=0$$
Step-by-Step Solution
Verified Answer
The solutions are \(x = \frac{1}{3}\) and \(x = -\frac{9}{2}\).
1Step 1: Identify the Equation Type
The equation given is \((3x-1)(2x+9) = 0\). This is a factored quadratic equation, meaning the quadratic is already expressed as a product of two binomials.
2Step 2: Apply the Zero Product Property
According to the zero product property, if the product of two expressions is zero, then at least one of the expressions must be zero. Thus, we set each factor in the equation to zero: \(3x - 1 = 0\) and \(2x + 9 = 0\).
3Step 3: Solve the First Equation
Solve \(3x - 1 = 0\) for \(x\):Add 1 to both sides:\[3x = 1\]Divide both sides by 3:\[x = \frac{1}{3}\]
4Step 4: Solve the Second Equation
Solve \(2x + 9 = 0\) for \(x\):Subtract 9 from both sides:\[2x = -9\]Divide both sides by 2:\[x = -\frac{9}{2}\]
5Step 5: Write the Solution
The solutions to the quadratic equation \((3x-1)(2x+9) = 0\) are \(x = \frac{1}{3}\) and \(x = -\frac{9}{2}\).
Key Concepts
Zero Product PropertyFactored Quadratic EquationSolving Quadratic Equations
Zero Product Property
The zero product property is a fundamental concept in algebra that helps solve quadratic equations. It states that if the product of two numbers is zero, then at least one of the numbers must be zero.
This property is particularly useful when dealing with equations that are expressed as a multiplication of factors, like quadratic equations in their factored form.
For example, if you have an equation
This property is particularly useful when dealing with equations that are expressed as a multiplication of factors, like quadratic equations in their factored form.
For example, if you have an equation
- \((a)(b) = 0\),
- \(a = 0\) or
- \(b = 0\).
Factored Quadratic Equation
A factored quadratic equation is one that is expressed as a product of two binomials or factors. Instead of having a standard form like \(ax^2 + bx + c = 0\), it is presented in a product form such as
Factoring is the process used to convert the quadratic into this form. Often, it requires recognizing common factors, using special formulas (like difference of squares), or applying techniques such as grouping. Once factored, solving the equation becomes straightforward. Each binomial can be set to zero, simplifying the solving process.
- \((px + q)(rx + s) = 0\).
Factoring is the process used to convert the quadratic into this form. Often, it requires recognizing common factors, using special formulas (like difference of squares), or applying techniques such as grouping. Once factored, solving the equation becomes straightforward. Each binomial can be set to zero, simplifying the solving process.
Solving Quadratic Equations
Solving quadratic equations involves finding the values of \(x\) that make the equation true. These values are called 'roots' or 'solutions'. Quadratics can be solved by various methods:
You simply set each factor equal to zero and solve for \(x\).
In the original problem, you start with
- Factoring
- Completing the square
- Using the quadratic formula
You simply set each factor equal to zero and solve for \(x\).
In the original problem, you start with
- \((3x-1)(2x+9) = 0\).
- \(3x-1 = 0\)
- \(2x+9 = 0\)
Other exercises in this chapter
Problem 43
Set up an equation and solve each problem. Two positive integers differ by 3 , and their product is 108 . Find the numbers.
View solution Problem 43
Use the quadratic formula to solve each of the quadratic equations. Check your solutions by using the sum and product relationships. $$n^{2}+32 n+252=0$$
View solution Problem 43
Write each of the following in terms of \(i\), perform the indicated operations, and simplify. For example, $$ \begin{aligned} \sqrt{-3} \sqrt{-8} &=(i \sqrt{3}
View solution Problem 44
Solve each inequality. $$2 x^{2}+6 x
View solution