Problem 43
Question
(Section 5.3) Find the sum of \(\frac{4}{5}+\frac{3}{8}\).
Step-by-Step Solution
Verified Answer
The sum is \( 1 \frac{7}{40} \).
1Step 1: Identify the Problem
We need to find the sum of two fractions: \( \frac{4}{5} \) and \( \frac{3}{8} \).
2Step 2: Find the Common Denominator
The denominators of the fractions are 5 and 8. The least common multiple of 5 and 8 is 40, which will be our common denominator.
3Step 3: Convert Fractions
Convert each fraction to an equivalent fraction with a denominator of 40.\[ \frac{4}{5} = \frac{4 \times 8}{5 \times 8} = \frac{32}{40} \] \[ \frac{3}{8} = \frac{3 \times 5}{8 \times 5} = \frac{15}{40} \]
4Step 4: Add the Fractions
Now add the two fractions with a common denominator:\[ \frac{32}{40} + \frac{15}{40} = \frac{32+15}{40} = \frac{47}{40} \]
5Step 5: Simplify the Result
The sum \( \frac{47}{40} \) is an improper fraction. We can convert it into a mixed number: \( 1 \frac{7}{40} \).
Key Concepts
Understanding the Least Common MultipleBreaking Down Improper FractionsThe Role and Conversion of Mixed Numbers
Understanding the Least Common Multiple
When working with fractions that have different denominators, it's important to find a common ground where they can coexist. This is where the concept of Least Common Multiple (LCM) comes into play.
The LCM of two numbers is the smallest number that is a multiple of both. To find the LCM of two denominators, like 5 and 8 from our original exercise, list the multiples of each number:
Knowing how to find the LCM is crucial because it allows us to convert fractions into equivalent fractions with the same denominator. This makes it possible to add, subtract, or compare fractions effectively.
The LCM of two numbers is the smallest number that is a multiple of both. To find the LCM of two denominators, like 5 and 8 from our original exercise, list the multiples of each number:
- Multiples of 5: 5, 10, 15, 20, 25, 30, 35, 40...
- Multiples of 8: 8, 16, 24, 32, 40...
Knowing how to find the LCM is crucial because it allows us to convert fractions into equivalent fractions with the same denominator. This makes it possible to add, subtract, or compare fractions effectively.
Breaking Down Improper Fractions
An improper fraction is when the numerator (the top number) is larger than the denominator (the bottom number). For instance, in our solution, we reached an improper fraction: \( \frac{47}{40} \).
Improper fractions are perfectly fine, but often, teachers or textbooks prefer them to be expressed as mixed numbers for ease of understanding. To tackle this, one might convert an improper fraction into a mixed number.
To do this, divide the numerator by the denominator. The quotient becomes the whole number part of the mixed number, while the remainder becomes the numerator of the fraction part.
In our case, dividing 47 by 40 gives 1 with a remainder of 7, hence:
Improper fractions are perfectly fine, but often, teachers or textbooks prefer them to be expressed as mixed numbers for ease of understanding. To tackle this, one might convert an improper fraction into a mixed number.
To do this, divide the numerator by the denominator. The quotient becomes the whole number part of the mixed number, while the remainder becomes the numerator of the fraction part.
In our case, dividing 47 by 40 gives 1 with a remainder of 7, hence:
- The whole number: 1
- The remainder: 7
- Thus, the mixed number is \( 1 \frac{7}{40} \)
The Role and Conversion of Mixed Numbers
Mixed numbers combine whole numbers with fractions. They are an intuitive way to express numbers greater than one, often appearing naturally in real-life situations, like splitting a pizza.
In our exercise, after converting the improper fraction \( \frac{47}{40} \) into \( 1 \frac{7}{40} \), we arrive at a mixed number. This involves:
In our exercise, after converting the improper fraction \( \frac{47}{40} \) into \( 1 \frac{7}{40} \), we arrive at a mixed number. This involves:
- The whole number (1 in this case) represents the full groups of 40 that fit into 47.
- The fraction (\( \frac{7}{40} \)) expresses the part of the group we have beyond our full whole.
Other exercises in this chapter
Problem 43
Find the sum: \(\frac{9}{70}+\frac{5}{21}+\frac{8}{15}\).
View solution Problem 43
Find the sums in the following 27 problems. If possible, use a calculator to check each result. $$ 452+(-124) $$
View solution Problem 44
Determine each value. $$ -(-|90|) $$
View solution Problem 44
Convert \(1602 \frac{1}{5}\) to a decimal.
View solution