Problem 43
Question
Prove that the linear differential operator of order \(n\) $$ L=D^{n}+a_{1} D^{n-1}+\cdots+a_{n-1} D+a_{n} $$ is a linear transformation from \(C^{n}(I)\) to \(C^{0}(I)\)
Step-by-Step Solution
Verified Answer
To prove that the given linear differential operator L of order n is a linear transformation from \(C^{n}(I)\) to \(C^{0}(I)\), we first show that L is defined on \(C^{n}(I)\) and maps to an element in \(C^{0}(I)\). Next, we demonstrate that L satisfies the addition property, \(L(f+g)=L(f)+L(g)\), and the scalar multiplication property, \(L(\alpha f)=\alpha L(f)\) for any functions \(f,g \in C^{n}(I)\) and scalar \(\alpha\). Since L satisfies both linearity properties, it is a linear transformation from \(C^{n}(I)\) to \(C^{0}(I)\).
1Step 1: Define L on \(C^{n}(I)\)
L is defined by the following nth order linear differential operator:
\[L = D^n + a_1 D^{n-1} + ... + a_{n-1} D + a_n\]
where \(D\) represents the differentiation operator, \(a_{i}\) are constants for \(i=1,\dots,n\), and L is defined on the space of nth-order differentiable functions \(C^{n}(I)\).
2Step 2: Show that L maps to an element in \(C^{0}(I)\)
To show that L maps to an element in \(C^{0}(I)\), consider a function \(f \in C^{n}(I)\). Applying L to this function, we get:
\[L(f) = D^n(f) + a_1 D^{n-1}(f) + ... + a_{n-1} D(f) + a_n f\]
Since L operates on the space of nth-order differentiable functions and differentiation reduces the order of differentiability by 1, it's clear that after applying the operator, the resulting function will be continuous. Therefore, L maps to the space of continuous functions \(C^{0}(I)\).
3Step 3: Prove the linearity properties
To prove the linearity properties, we need to show that L satisfies the addition property and the scalar multiplication property:
1. Addition Property: For any two functions \(f,g \in C^{n}(I)\) and their sum \(h = f + g\), we want to show that \(L(h) = L(f) + L(g)\).
Applying L to the sum of two functions, we get:
\[L(h) = D^n(f + g) + a_1 D^{n-1}(f + g) + ... + a_{n-1} D(f + g) + a_n (f + g)\]
Using the properties of the differentiation operator, we can deduce the following:
\[L(h) = (D^n(f) + D^n(g)) + a_1 (D^{n-1}(f) + D^{n-1}(g)) + ... + a_{n-1} (D(f) + D(g)) + a_n f + a_n g\]
\[L(h) = L(f) + L(g)\]
2. Scalar multiplication property: For any function \(f \in C^{n}(I)\) and a scalar \(\alpha\), we want to show that \(L(\alpha f) = \alpha L(f)\).
Applying L to the product of a scalar and a function, we get:
\[L(\alpha f) = D^n(\alpha f) + a_1 D^{n-1}(\alpha f) + ... + a_{n-1} D(\alpha f) + a_n (\alpha f)\]
Using the properties of the differentiation operator, we can deduce the following:
\[L(\alpha f) = \alpha (D^n(f)) + a_1 \alpha (D^{n-1}(f)) + ... + a_{n-1} \alpha (D(f)) + a_n \alpha f\]
\[L(\alpha f) = \alpha L(f)\]
Since L satisfies both the addition and scalar multiplication properties, it is a linear transformation from \(C^{n}(I)\) to \(C^{0}(I)\).
Key Concepts
Linear TransformationDifferentiationn-th Order Differential EquationContinuity of Functions
Linear Transformation
Linear transformations are functions between vector spaces that preserve vector addition and scalar multiplication. A linear transformation must satisfy two main properties: the addition property and the scalar multiplication property.
- **Addition Property**: For functions or vectors \( f \) and \( g \), a linear transformation \( L \) should have \( L(f + g) = L(f) + L(g) \). This means that when you transform a sum, it's the same as summing the transformations of each function or vector individually.
- **Scalar Multiplication Property**: For any function or vector \( f \) and any scalar \( \alpha \), we should have \( L(\alpha f) = \alpha L(f) \). This means that if you scale a function before transformation, the same scaling should apply to the result after transformation.
These properties ensure that the transformation maintains the structure of the vector space, and for differential operators, it means the operations of differentiation and the combination of derivatives act linearly across applied functions.
- **Addition Property**: For functions or vectors \( f \) and \( g \), a linear transformation \( L \) should have \( L(f + g) = L(f) + L(g) \). This means that when you transform a sum, it's the same as summing the transformations of each function or vector individually.
- **Scalar Multiplication Property**: For any function or vector \( f \) and any scalar \( \alpha \), we should have \( L(\alpha f) = \alpha L(f) \). This means that if you scale a function before transformation, the same scaling should apply to the result after transformation.
These properties ensure that the transformation maintains the structure of the vector space, and for differential operators, it means the operations of differentiation and the combination of derivatives act linearly across applied functions.
Differentiation
Differentiation is a fundamental concept in calculus that represents the rate at which a function is changing at any given point. The differentiation operator, commonly denoted as \( D \), when applied to a function, produces its derivative.
- For a simple function like \( f(x) = x^2 \), its differentiation, \( D(f) \), would result in \( 2x \).
- Higher-order derivatives, like \( D^n(f) \), involve differentiating \( n \) times. For example, the second derivative of \( x^2 \) would result in \( 2 \).
n-th Order Differential Equation
An \( n \)-th order differential equation involves derivatives of a function up to the \( n \)-th degree. Such equations are crucial in modeling various phenomena in engineering and physics, as they represent the relationship between a function and its derivatives over time or space.
- A first-order differential equation involves the first derivative, like \( D(f) = f' \).
- Second-order involves up to the second derivative, like \( D^2(f) = f'' \).
- An \( n \)-th order extends this up to the \( n \) derivative, \( D^n(f) \).
Continuity of Functions
Continuity is a property of a function that indicates its behavior is smooth and unbroken. To say a function is continuous means that for tiny changes in the input, there are tiny changes in the output, without sudden jumps or breaks. This is visually akin to being able to draw the graph of the function without lifting your pencil.
In calculus, a function \( f(x) \) is continuous at a point \( x = a \) if:
In calculus, a function \( f(x) \) is continuous at a point \( x = a \) if:
- \( f(a) \) is defined.
- \( \lim_{x \to a} f(x) = f(a) \).
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