Problem 43
Question
Nickel forms a compound with carbon monoxide, \(\mathrm{Ni}_{x}(\mathrm{CO})_{r}\). To determine its formula, you carefully heat a 0.0973 -g sample in air to convert the nickel to \(0.0426 \mathrm{g}\) of NiO and the CO to \(0.100 \mathrm{g}\) of \(\mathrm{CO}_{2} .\) What is the empirical formula of \(\mathrm{Ni}_{x}(\mathrm{CO})_{y} ?\)
Step-by-Step Solution
Verified Answer
The empirical formula is \( \text{Ni(CO)}_4 \).
1Step 1: Determine Moles of Ni
First, calculate the moles of Ni in the NiO produced. The molar mass of NiO is approximately 74.69 g/mol (Ni: 58.69 g/mol, O: 16 g/mol). Use the formula \( n = \frac{m}{M} \) where \( m \) is mass and \( M \) is molar mass.\[ \text{Moles of NiO} = \frac{0.0426 \text{ g}}{74.69 \text{ g/mol}} \approx 5.70 \times 10^{-4} \text{ mol} \]Since each mol of NiO contains exactly one mol of Ni, the moles of Ni are also approximately \( 5.70 \times 10^{-4} \text{ mol} \).
2Step 2: Determine Moles of CO2
Next, we calculate moles of \( \text{CO}_2 \) produced. The molar mass of \( \text{CO}_2 \) is approximately 44.01 g/mol.\[ \text{Moles of } \text{CO}_2 = \frac{0.100 \text{ g}}{44.01 \text{ g/mol}} \approx 2.27 \times 10^{-3} \text{ mol} \]
3Step 3: Determine Moles of CO
Since \( \text{CO}_2 \) production comes from \( \text{CO} \), and \( \text{CO} \) converts to \( \text{CO}_2 \) in a 1:1 molar ratio (1 mol of \( \text{CO} \) gives 1 mol of \( \text{CO}_2 \)), there are also \( 2.27 \times 10^{-3} \text{ mol} \) of \( \text{CO} \).
4Step 4: Determine Empirical Formula
Use the mole ratio to find the empirical formula of \( \text{Ni}_x(\text{CO})_y \). The ratio of moles is\[ \frac{5.70 \times 10^{-4}}{5.70 \times 10^{-4}} : \frac{2.27 \times 10^{-3}}{5.70 \times 10^{-4}} \approx 1 : 4 \]Thus, the empirical formula is \( \text{Ni(CO)}_4 \).
Key Concepts
Nickel CarbonylChemical ReactionsMole CalculationStoichiometry
Nickel Carbonyl
Nickel carbonyl, known scientifically as tetracarbonylnickel, is a fascinating compound with the formula \( \text{Ni(CO)}_4 \). This compound features nickel, a silvery metal, tightly bonded with carbon monoxide molecules. This arrangement results in a volatile compound often used in nickel refining and purification.
Nickel carbonyl is notable for its ability to form quickly at room temperature, yet decomposes readily when heated. Due to its volatility and toxic nature, handling it requires precise safety measures.
Nickel carbonyl is notable for its ability to form quickly at room temperature, yet decomposes readily when heated. Due to its volatility and toxic nature, handling it requires precise safety measures.
- It exemplifies the concept of organometallic chemistry, where metals form stable bonds with organic ligands like CO.
- The Ni-CO bond is characterized by a overlap between nickel's orbitals and the orbitals of CO, facilitating its unique stability.
- Naturally formed at low temperatures, this compound is used industrially in nickel production.
Chemical Reactions
Chemical reactions describe the transformation of substances into new products with different properties. In the context of nickel carbonyl, a significant chemical reaction occurs when it is heated in air:
The nickel reverts to its oxide form (\( \text{NiO} \)), and the carbon monoxide is converted to carbon dioxide (\( \text{CO}_2 \)). This transformation is an example of an oxidation reaction, a type of chemical reaction where substances combine with oxygen.
The reaction can be succinctly described by the equation:
The nickel reverts to its oxide form (\( \text{NiO} \)), and the carbon monoxide is converted to carbon dioxide (\( \text{CO}_2 \)). This transformation is an example of an oxidation reaction, a type of chemical reaction where substances combine with oxygen.
The reaction can be succinctly described by the equation:
- Conversion of \( \text{Ni(CO)}_4 \) to \( \text{NiO} \) releases carbon monoxide, followed by its oxidation to \( \text{CO}_2 \).
- This two-step process highlights not only the reactivity of nickel carbonyl but the sequential nature of reactions.
Mole Calculation
Mole calculations play a fundamental role in chemistry, allowing us to relate the measured mass of substances to the number of atoms or molecules present in a sample. The mole is a standard unit used to quantify amounts in chemistry, aligning perfectly with Avogadro's number, \( 6.022 \times 10^{23} \) units/mole.
In our problem, mole calculation was key to determining the empirical formula of nickel carbonyl. By knowing the mass of the products, \( \text{NiO} \) and \( \text{CO}_2 \), solutions were calculated by converting these masses into moles:
In our problem, mole calculation was key to determining the empirical formula of nickel carbonyl. By knowing the mass of the products, \( \text{NiO} \) and \( \text{CO}_2 \), solutions were calculated by converting these masses into moles:
- The moles of \( \text{Ni} \) from \( \text{NiO} \) were determined by dividing by NiO's molar mass.
- Similarly, the moles of \( \text{CO} \) were obtained using the mass of \( \text{CO}_2 \) due to their stoichiometric relationship.
Stoichiometry
Stoichiometry is the area of chemistry that quantifies the relationships within chemical reactions. It is founded on the conservation of mass principle, demanding a balanced representation of the reaction, where the number of atoms for every element must be equal on both sides.
In determining the empirical formula of \( \text{Ni(CO)}_4 \), stoichiometry was used to set up the mole ratios of nickel to carbon monoxide. By dividing the moles of each element by the smallest number of moles calculated, a simple ratio was established:
In determining the empirical formula of \( \text{Ni(CO)}_4 \), stoichiometry was used to set up the mole ratios of nickel to carbon monoxide. By dividing the moles of each element by the smallest number of moles calculated, a simple ratio was established:
- For each reaction mass, the same precision allowed us to determine the smallest integer ratio.
- This ratio pinpointed the empirical formula reflecting the smallest whole number of atoms in the compound.
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