Problem 43
Question
Let \(A\) and \(B\) be \(4 \times 4\) matrices such that \(\operatorname{det}(A)=5\) and \(\operatorname{det}(B)=3 .\) Compute the determinant of the given matrix. $$B^{-1}(2 A) B^{T}$$
Step-by-Step Solution
Verified Answer
The determinant of the given matrix \(B^{-1}(2 A) B^{T}\) is \(80\).
1Step 1: Identify determinant properties related to the given matrix
We have the given matrix as \(B^{-1}(2 A) B^{T}\). We need to use the properties of determinants mentioned in the analysis section to break down this product and find its determinant.
2Step 2: Apply property 1 - product of determinants
Using property 1, we can write the determinant of the product matrix as:
\(\operatorname{det}(B^{-1}(2 A) B^{T}) = \operatorname{det}(B^{-1}) \operatorname{det}(2A) \operatorname{det}(B^{T})\)
3Step 3: Apply properties 3, 4, and 5
Now, we can apply the other properties of determinants to simplify the expression further:
- Property 5: \(\operatorname{det}(B^{-1}) = \frac{1}{\operatorname{det}(B)} = \frac{1}{3}\)
- Property 3: \(\operatorname{det}(2A) = 2^n \operatorname{det}(A) = 2^4 \cdot 5 = 80\)
- Property 4: \(\operatorname{det}(B^{T}) = \operatorname{det}(B) = 3\)
4Step 4: Multiply the simplified determinants
Now that we have simplified each determinant in the product, we can multiply them together:
\(\operatorname{det}(B^{-1}(2 A) B^{T}) = \frac{1}{3} \cdot 80 \cdot 3 = 80\)
So, the determinant of the given matrix is \(80\).
Key Concepts
Matrix MultiplicationInverse MatrixTranspose MatrixProperties of Determinants
Matrix Multiplication
Matrix multiplication is a fundamental concept in linear algebra. It involves two matrices, let's call them matrix \(A\) and matrix \(B\), combined to form a new matrix. However, multiplying matrices is not as straightforward as multiplying numbers. Here’s a simple way to understand it:
- The number of columns in the first matrix \(A\) must be equal to the number of rows in the second matrix \(B\).
- The resulting matrix has the same number of rows as the first matrix and the same number of columns as the second matrix.
Inverse Matrix
An inverse matrix is like a magical undo button for matrices. If you have matrix \(A\), the inverse of \(A\), denoted as \(A^{-1}\), is such that when you multiply \(A\) by \(A^{-1}\), you get the identity matrix: \[ AA^{-1} = A^{-1}A = I \]
- The identity matrix \(I\) is the version of 1 for matrices. It's a square matrix with ones on the diagonal and zeros elsewhere.
- For a matrix to have an inverse, it must be square, meaning it has the same number of rows and columns, and its determinant must not be zero.
Transpose Matrix
The transpose of a matrix flips it over its diagonal. If you have a matrix \(A\), its transpose is denoted as \(A^T\). This transformation does the following:
- Switches rows with columns.
- The \(i^{th}\) row becomes the \(i^{th}\) column and vice versa.
Properties of Determinants
Determinants are special numbers that can be associated with a square matrix. Here are some key properties:
- The determinant of the identity matrix is always 1.
- If a matrix is multiplied by a scalar, its determinant is multiplied by the scalar raised to the number of rows (or columns). For example, \( \det(kA) = k^n \det(A) \) where \(n\) is the size of the square matrix.
- The determinant of the inverse matrix is the reciprocal of the determinant of the original matrix, \(\det(A^{-1}) = 1/\det(A)\).
- The determinant of a transpose matrix is equal to the determinant of the original matrix, i.e., \(\det(A^T) = \det(A)\).
Other exercises in this chapter
Problem 43
Find (a) \(\operatorname{det}(A),\) (b) the matrix of cofactors \(M_{C},(\mathrm{c})\) adj \((A),\) and, if possible, \((\mathrm{d}) A^{-1}.\) $$A=\left[\begin{
View solution Problem 43
Evaluate the determinant of the given matrix function. \(A(t)=\left[\begin{array}{cc}e^{6 t} & e^{4 t} \\ 6 e^{6 t} & 4 e^{4 t}\end{array}\right]\).
View solution Problem 44
Find (a) \(\operatorname{det}(A),\) (b) the matrix of cofactors \(M_{C},(\mathrm{c})\) adj \((A),\) and, if possible, \((\mathrm{d}) A^{-1}.\) $$A=\left[\begin{
View solution Problem 44
Evaluate the determinant of the given matrix function. \(A(t)=\left[\begin{array}{lll}\sin t & \cos t & 1 \\ \cos t & -\sin t & 0 \\\ \sin t & -\cos t & 0\end{a
View solution