Problem 43
Question
In Exercises \(41-48,\) factor any perfect square trinomials, or state that the polynomial is prime. $$x^{2}-14 x+49$$
Step-by-Step Solution
Verified Answer
The factored form of the polynomial \(x^{2}-14x+49\) is \((x-7)^{2}\)
1Step 1: Identification
Identify that the given polynomial \(x^{2}-14x+49\) is in the form of \(a^{2}-2ab+b^{2}\), where \(a=x\), \(b=7\)
2Step 2: Factorize
Factorize the polynomial by using the perfect square trinomial formula \(x^{2}-2ab+b^{2} = (a-b)^{2}\). Thus, \(x^{2}-14x+49 = (x-7)^{2}\)
3Step 3: Write Down the Answer
Write down final factored form of the given polynomial which is \((x-7)^{2}\)
Key Concepts
Perfect Square TrinomialsAlgebraic ExpressionsPolynomial Factorization
Perfect Square Trinomials
A perfect square trinomial is a special type of polynomial that can be expressed as the square of a binomial. You'll often encounter perfect square trinomials in the form \(a^2 - 2ab + b^2\) or \(a^2 + 2ab + b^2\). These types of trinomials are particularly convenient to work with because they can be easily factored into a binomial squared.
For instance, consider the given polynomial: \(x^2 - 14x + 49\). It matches the pattern \(a^2 - 2ab + b^2 = (a-b)^2\), where \(a = x\) and \(b = 7\). By recognizing this pattern, we understand that this trinomial is a perfect square. Therefore, it can be factored as \((x-7)^2\).
Recognizing and factoring perfect square trinomials is a useful skill in algebra because it simplifies the polynomial into a much more manageable form.
For instance, consider the given polynomial: \(x^2 - 14x + 49\). It matches the pattern \(a^2 - 2ab + b^2 = (a-b)^2\), where \(a = x\) and \(b = 7\). By recognizing this pattern, we understand that this trinomial is a perfect square. Therefore, it can be factored as \((x-7)^2\).
Recognizing and factoring perfect square trinomials is a useful skill in algebra because it simplifies the polynomial into a much more manageable form.
Algebraic Expressions
Algebraic expressions are mathematical phrases that can involve numbers, variables, and operators such as addition, subtraction, multiplication, and division. Variables, such as \(x\) in our example, are symbols used to represent an unknown or varying number. They are a fundamental part of algebra, allowing for generalization and simplification of problems.
In the expression \(x^2 - 14x + 49\), \(x^2\) represents \(x\) multiplied by itself, \(-14x\) shows that \(x\) is multiplied by \(-14\), and \(49\) is a constant term. The beauty of algebraic expressions lies in how they enable us to solve complex problems by applying mathematical principles systematically.
In the expression \(x^2 - 14x + 49\), \(x^2\) represents \(x\) multiplied by itself, \(-14x\) shows that \(x\) is multiplied by \(-14\), and \(49\) is a constant term. The beauty of algebraic expressions lies in how they enable us to solve complex problems by applying mathematical principles systematically.
- Variables represent unknowns or can stand for a set of values.
- Constants are fixed values.
- Coefficients indicate how many times to multiply the variable.
Polynomial Factorization
Polynomial factorization is the process of breaking down a polynomial into simpler "factor" polynomials that, when multiplied together, yield the original polynomial. This process is akin to breaking down numbers into prime factors, making it easier to work with polynomials in equations.
In the problem of factoring \(x^2 - 14x + 49\), we used the recognition of a perfect square trinomial to factor it as \((x-7)^2\). Not all polynomials are this straightforward, and some might require different techniques such as the greatest common factor method, grouping, or applying the quadratic formula for factorization.
The essence of polynomial factorization lies in:
In the problem of factoring \(x^2 - 14x + 49\), we used the recognition of a perfect square trinomial to factor it as \((x-7)^2\). Not all polynomials are this straightforward, and some might require different techniques such as the greatest common factor method, grouping, or applying the quadratic formula for factorization.
The essence of polynomial factorization lies in:
- Simplifying algebraic expressions.
- Finding solutions to equations.
- Understanding the behavior of polynomial graphs.
Other exercises in this chapter
Problem 43
evaluate each algebraic expression for the given value of the variable or variables. $$ \frac{5}{9}(F-32) ; F=77 $$
View solution Problem 43
Find each product. $$(2 x+3)^{2}$$
View solution Problem 43
In Exercises \(39-48\), rationalize the denominator. $$\frac{13}{3+\sqrt{11}}$$
View solution Problem 43
Add or subtract as indicated. $$ \frac{3}{x+1}-\frac{3}{x} $$
View solution