Problem 43
Question
Give the slope and y-intercept of each line whose equation is given. Then graph the line. $$y=\frac{3}{4} x-2$$
Step-by-Step Solution
Verified Answer
The slope of the line is \(\frac{3}{4}\) and the y-intercept is \(-2\). Limitations in text representation don't allow for the real-life graphing portion of this solution, one must draw this on paper or use graphing software to visualize the line.
1Step 1: Identify the slope and y-intercept
The given equation is \(y = \frac{3}{4}x - 2\), it's already in the form \(y = mx + b\). Here, the coefficient of \(x\) is the slope \(m = \frac{3}{4}\), and the constant term \(-2\) is the y-intercept \(b\).
2Step 2: Plotting the y-intercept
The y-intercept is \(-2\), which represents the point on the y-axis where the line crosses. So, the first point to plot on the graph is \((0, -2)\). Draw a small dot at this point on the y-axis.
3Step 3: Plotting more points using the slope
The slope being \(\frac{3}{4}\) means 'rise 3 and run 4'. From the y-intercept, count 3 units upward (positive because it's 3), and 4 units rightward (positive because it's 4). Each of these new points is also on the line.
4Step 4: Draw the line
Using a ruler, neatly draw a straight line that goes through all the plotted points. The line represents all the solution of the given equation.
Key Concepts
Understanding the SlopeIdentifying the Y-InterceptTips for Graphing Lines
Understanding the Slope
The slope of a line, often represented by the letter *m* in the equation of a line, tells us how steep the line is. In a linear equation written in slope-intercept form, i.e., \(y = mx + b\), the slope is the coefficient of \(x\).
In the example given, the equation \(y = \frac{3}{4}x - 2\) has a slope of \(\frac{3}{4}\). This fraction indicates that for every 4 units you move horizontally (to the right), the line moves up 3 units vertically. This is called "rise over run."
In the example given, the equation \(y = \frac{3}{4}x - 2\) has a slope of \(\frac{3}{4}\). This fraction indicates that for every 4 units you move horizontally (to the right), the line moves up 3 units vertically. This is called "rise over run."
- If the slope is positive, like \(\frac{3}{4}\), the line goes upwards as you move from left to right.
- If the slope were negative, the line would slope downwards.
- A larger slope value means a steeper line, whereas a smaller slope means a gentler incline.
Identifying the Y-Intercept
In the slope-intercept form of a linear equation \(y = mx + b\), the *y-intercept* is the term \(b\). It refers to the point where the line crosses the y-axis, which occurs when \(x = 0\).
For the equation \(y = \frac{3}{4}x - 2\), the y-intercept is \(-2\). This means that the line will intersect the y-axis at the point \((0, -2)\). It's crucial to plot this point as your first step when graphing a line because it serves as the starting position.
For the equation \(y = \frac{3}{4}x - 2\), the y-intercept is \(-2\). This means that the line will intersect the y-axis at the point \((0, -2)\). It's crucial to plot this point as your first step when graphing a line because it serves as the starting position.
- A positive y-intercept means the line crosses above the origin.
- A negative y-intercept, like in our example, indicates it crosses below the origin.
Tips for Graphing Lines
Graphing lines involves transforming an equation into a visual representation on a coordinate plane. Here's a step by step approach using the provided equation \(y = \frac{3}{4}x - 2\):
- Start with the y-intercept: Identify the y-intercept from the equation (\(-2\)) and plot this on the y-axis at \((0, -2)\).
- Use the slope for direction: From the y-intercept, use the slope \(\frac{3}{4}\). Move 3 units up and 4 units to the right to find another point on the line, e.g., reaching the point \((4, 1)\).
- Connect the dots: After plotting these points, draw a straight line through them using a ruler. Ensure the line extends in both directions, covering the entire plane.
Other exercises in this chapter
Problem 42
Give the center and radius of the circle described by the equation and graph each equation. $$ x^{2}+y^{2}=49 $$
View solution Problem 43
Begin by graphing the standard cubic function, \(f(x)=x^{3} .\) Then use transformations of this graph to graph the given function. $$ r(x)=(x-3)^{3}+2 $$
View solution Problem 43
Express the given function h as a composition of two functions f and g so that \(h(x)=(f \circ g)(x)\) $$h(x)=|2 x-5|$$
View solution Problem 43
In Exercises \(33-44\), find and simplify the difference quotient $$\frac{f(x+h)-f(x)}{h}, h \neq 0$$for the given function. $$f(x)=\frac{1}{x}$$
View solution