Problem 43
Question
For the given \(f(x)\), find a formula for \(f^{\prime}(a)\). $$f(x)=3 x-1$$
Step-by-Step Solution
Verified Answer
The derivative \(f'(a)\) is 3.
1Step 1: Understanding the Function
We start with the linear function given by \(f(x) = 3x - 1\). This is a straightforward linear function of the form \(ax + b\), where \(a = 3\) and \(b = -1\).
2Step 2: Recall the Derivative Rule for Linear Functions
For a linear function \(f(x) = ax + b\), the derivative \(f'(x)\) is simply the coefficient of \(x\), which is \(a\). This comes from the rule that the derivative of \(x\) is 1, so \(\frac{d}{dx}(ax + b) = a\).
3Step 3: Differentiate the Function
Apply the derivative rule: since \(f(x) = 3x - 1\), the derivative \(f'(x)\) is \(3\).
4Step 4: Evaluate the Derivative at a Specific Point
To find \(f'(a)\), substitute \(a\) into the expression for \(f'(x)\). It remains the constant \(3\) since the derivative of a linear function is constant.
Key Concepts
Linear FunctionsDerivative RulesEvaluation of Derivatives
Linear Functions
A linear function is one of the simplest types of functions you can encounter in mathematics. It has the general form of \(f(x) = ax + b\), where \(a\) and \(b\) are constants.
This type of function graphs as a straight line, with the slope of the line being \(a\). The constant term \(b\) represents the y-intercept, which is the value of the function when \(x = 0\).
This type of function graphs as a straight line, with the slope of the line being \(a\). The constant term \(b\) represents the y-intercept, which is the value of the function when \(x = 0\).
- Example: The function \(f(x) = 3x - 1\) has a slope of \(3\) and a y-intercept at \(y = -1\).
- Slope: This number \(a\) shows the steepness of the line. A larger absolute value of \(a\) means a steeper slope.
- Intercept: The value \(b\) shifts the line up or down on the y-axis, determining where the line crosses the y-axis.
Derivative Rules
Derivative rules are guidelines that help us find the derivatives of various functions easily and quickly.
The rules simplify the process so that you don't need to go back to the most basic definition of a derivative every time.
For our function \(f(x) = 3x - 1\), the derivative rule for linear functions tells us that \(f'(x) = 3\). This is a simplified process compared to more complex functions.
The rules simplify the process so that you don't need to go back to the most basic definition of a derivative every time.
- For Linear Functions: The derivative of a linear function \(f(x) = ax + b\) is \(f'(x) = a\). This means that the derivative of any linear function is its slope \(a\).
- Constant Rule: If you have a constant function \(f(x) = c\), its derivative is \(0\) because it remains unchanged as \(x\) changes.
- Power Rule: For a function \(x^n\), the derivative is \(nx^{n-1}\). This rule doesn't directly apply to linear functions without adjustment, since a linear function is a first-degree polynomial (\(n=1\)).
For our function \(f(x) = 3x - 1\), the derivative rule for linear functions tells us that \(f'(x) = 3\). This is a simplified process compared to more complex functions.
Evaluation of Derivatives
Evaluating derivatives involves applying the derivative you've found to particular values of \(x\). For linear functions, this is straightforward.
Since the derivative of a linear function is constant, evaluating it at any point \(a\) will yield the same result.
When given the function \(f(x) = 3x - 1\), its derivative is \(f'(x) = 3\). This means:
Thus, the evaluation of the derivative simply confirms the constant rate of change of the function. This concept is core to understanding how derivatives work in relation to linear functions.
Since the derivative of a linear function is constant, evaluating it at any point \(a\) will yield the same result.
When given the function \(f(x) = 3x - 1\), its derivative is \(f'(x) = 3\). This means:
- Regardless of the value of \(a\) we choose, \(f'(a) = 3\).
- The derivative tells us that the slope of the tangent to the line at any point is always \(3\).
Thus, the evaluation of the derivative simply confirms the constant rate of change of the function. This concept is core to understanding how derivatives work in relation to linear functions.
Other exercises in this chapter
Problem 42
Determine each limit, if it exists. $$\lim _{x \rightarrow 0}\left[2^{3 x}-\ln (x+1)\right]$$
View solution Problem 43
Use a table and/or graph to decide whether each limit exists. If a limit exists, find its value. \(\lim _{x \rightarrow 3} f(x),\) where \(f(x)=\left\\{\begin{a
View solution Problem 43
Determine each limit. $$\lim _{x \rightarrow \infty} \frac{1-7 x^{3}}{x^{2}+7 x^{3}}$$
View solution Problem 43
Determine each limit, if it exists. $$\lim _{x \rightarrow 3} \frac{\sqrt{x+1}}{\log _{2}(5 x+1)}$$
View solution