Problem 43
Question
For the following exercises, find the inverse function. Then, graph the function and its inverse. $$ f(x)=x^{3}-1 $$
Step-by-Step Solution
Verified Answer
The inverse function is \( f^{-1}(x) = \sqrt[3]{x + 1} \).
1Step 1: Understand the Function
The given function is \( f(x) = x^3 - 1 \). This is a cubic function, which is one-to-one, meaning it has an inverse.
2Step 2: Express f(x) as y
Start by replacing \( f(x) \) with \( y \) to express the equation as \( y = x^3 - 1 \). This helps in finding the inverse function.
3Step 3: Swap x and y
To find the inverse, swap \( x \) and \( y \) in the equation. This gives us \( x = y^3 - 1 \).
4Step 4: Solve for y
Isolate \( y \) by adding 1 to both sides: \( x + 1 = y^3 \). To solve for \( y \), take the cube root of both sides: \( y = \sqrt[3]{x + 1} \).
5Step 5: Write the Inverse Function
The inverse function of \( f(x) \) is \( f^{-1}(x) = \sqrt[3]{x + 1} \).
6Step 6: Graph the Function and Its Inverse
Graph \( f(x) = x^3 - 1 \). The graph is a cubic curve shifted down by 1 unit. Then, graph its inverse \( f^{-1}(x) = \sqrt[3]{x + 1} \), which is a cubic root curve shifted to the left by 1 unit. Note that the two graphs are reflections of each other across the line \( y = x \).
Key Concepts
Cubic FunctionOne-to-One FunctionReflection Across y = xGraphing Inverse Functions
Cubic Function
A cubic function is a type of polynomial function where the highest degree of the variable is three. It generally takes the form \( f(x) = ax^3 + bx^2 + cx + d \), where \( a, b, c, \) and \( d \) are constants, and \( a eq 0 \). In our original exercise, the function is \( f(x) = x^3 - 1 \), which means:
- The cubic term is \( x^3 \).
- There's no quadratic or linear term (since their coefficients are 0).
- It is shifted down by 1 due to the \(-1\) at the end.
One-to-One Function
In mathematics, a one-to-one function is a function where each element of the range is mapped to a unique element in the domain. This ensures that no horizontal line intersects the graph of the function more than once.
- For a function to have an inverse, it must be one-to-one.
- We determine this by using the Horizontal Line Test, which is a visual way to see that no horizontal line cuts through more than one point of the graph.
Reflection Across y = x
Reflecting a function across the line \( y = x \) means swapping the roles of \( x \) and \( y \). This is crucial when determining the inverse of a function. For the original function \( f(x) = x^3 - 1 \), its inverse \( f^{-1}(x) = \sqrt[3]{x + 1} \) is found by interchanging \( x \) and \( y \) in its equation and solving for \( y \). When graphed, the original function and its inverse will "mirror" each other along the identity line \( y = x \).
- The line \( y = x \) acts as a symmetry line.
- The point \( (a, b) \) on the original graph corresponds to \( (b, a) \) on the inverse.
Graphing Inverse Functions
Graphing both a function and its inverse on the same set of axes offers a tangible way to understand their relationship. For the function \( f(x) = x^3 - 1 \), we plot it as a transformed cubic curve, with a characteristic shape that bends and twists through the plane.
- Its inverse, \( f^{-1}(x) = \sqrt[3]{x + 1} \), follows a cubic root path. It appears as a gentler curve, shifted horizontally.
- The graphs intersect on the line \( y = x \), given their reflection.
Other exercises in this chapter
Problem 42
Let \(f(x)=\frac{1}{x} \cdot\) Find a number \(c\) such that the average rate of change of the function \(f\) on the interval \((1, c)\) is \(-\frac{1}{4}\)
View solution Problem 42
For the following exercises, sketch a graph of the piecewise function. Write the domain in interval notation. $$ f(x)=\left\\{\begin{array}{ll}{x^{2}} & {\text
View solution Problem 43
Let \(f(x)=\frac{1}{x} .\) Find the number \(b\) such that the average rate of change of \(f\) on the interval \((2, b)\) is \(-\frac{1}{10}\)
View solution Problem 43
For the following exercises, sketch a graph of the piecewise function. Write the domain in interval notation. $$ f(x)=\left\\{\begin{array}{ll}{x^{2}} & {\text
View solution