Problem 43
Question
For exercises 39-82, simplify. $$ \frac{3 a}{5} \div \frac{9}{10 a^{2}} $$
Step-by-Step Solution
Verified Answer
\( \frac{2a^3}{3} \)
1Step 1: Rewrite the Division as Multiplication
To simplify the division of fractions, rewrite the division problem as a multiplication problem by multiplying by the reciprocal of the divisor. The given problem is: \( \frac{3a}{5} \div \frac{9}{10a^2} \).Rewrite it as: \( \frac{3a}{5} \times \frac{10a^2}{9} \).
2Step 2: Multiply the Numerators
Multiply the numerators of the fractions together:\( 3a \times 10a^2 = 30a^3 \).
3Step 3: Multiply the Denominators
Multiply the denominators of the fractions together:\( 5 \times 9 = 45 \).
4Step 4: Combine the Results
Combine the results from steps 2 and 3 into one fraction:\( \frac{30a^3}{45} \).
5Step 5: Simplify the Fraction
Simplify the fraction. Find the greatest common divisor (GCD) of 30 and 45, which is 15, and divide both the numerator and denominator by this GCD:\( \frac{30a^3 \div 15}{45 \div 15} = \frac{2a^3}{3} \).
Key Concepts
Multiplying FractionsGreatest Common DivisorReciprocal
Multiplying Fractions
To simplify algebraic fractions, one core concept to understand is how to multiply fractions. When multiplying fractions, you simply:
Consider two fractions, \( \frac{a}{b} \) and \( \frac{c}{d} \). When you multiply them, the result is \( \frac{a \times c}{b \times d} \). It's important to remember to perform these multiplications separately.
In our exercise, we reframe the given problem to a multiplication scenario. This results in \( \frac{3a}{5} \times \frac{10a^2}{9} \). We then multiply the numerators: \( 3a \times 10a^2 = 30a^3 \), and the denominators: \( 5 \times 9 = 45 \). Finally, we combine them to form \( \frac{30a^3}{45} \).
- Multiply the numerators together.
- Multiply the denominators together.
Consider two fractions, \( \frac{a}{b} \) and \( \frac{c}{d} \). When you multiply them, the result is \( \frac{a \times c}{b \times d} \). It's important to remember to perform these multiplications separately.
In our exercise, we reframe the given problem to a multiplication scenario. This results in \( \frac{3a}{5} \times \frac{10a^2}{9} \). We then multiply the numerators: \( 3a \times 10a^2 = 30a^3 \), and the denominators: \( 5 \times 9 = 45 \). Finally, we combine them to form \( \frac{30a^3}{45} \).
Greatest Common Divisor
Simplifying a fraction often involves finding the Greatest Common Divisor (GCD). The GCD is the largest number that can exactly divide both the numerator and the denominator.
The prime factors of 30 are 2, 3, and 5, and for 45, they are 3, 3, and 5.
The common factors are 3 and 5, which multiply to give the GCD of 15.
We simplify the fraction by dividing both the numerator and the denominator by 15:
\[ \frac{30a^3 \div 15}{45 \div 15} = \frac{2a^3}{3} \]. Hence, the simplified fraction is \( \frac{2a^3}{3} \).
- Firstly, find the prime factors of both numbers.
- Identify the common factors.
- Select the highest common factor, which is the GCD.
The prime factors of 30 are 2, 3, and 5, and for 45, they are 3, 3, and 5.
The common factors are 3 and 5, which multiply to give the GCD of 15.
We simplify the fraction by dividing both the numerator and the denominator by 15:
\[ \frac{30a^3 \div 15}{45 \div 15} = \frac{2a^3}{3} \]. Hence, the simplified fraction is \( \frac{2a^3}{3} \).
Reciprocal
The concept of the reciprocal is key in simplifying fractions involving division. The reciprocal of a fraction is obtained by swapping the numerator and the denominator.
For example, the reciprocal of \( \frac{a}{b} \) is \( \frac{b}{a} \).
To solve a division of fractions, multiply by the reciprocal of the divisor.
In our exercise, converting \( \frac{3a}{5} \div \frac{9}{10a^2} \) involves using the reciprocal of \( \frac{9}{10a^2} \), which is \( \frac{10a^2}{9} \).
Thus, we rewrite it as \( \frac{3a}{5} \times \frac{10a^2}{9} \). This conversion simplifies the division problem into a multiplication problem,
which we can solve using the multiplication rules discussed earlier.
For example, the reciprocal of \( \frac{a}{b} \) is \( \frac{b}{a} \).
To solve a division of fractions, multiply by the reciprocal of the divisor.
In our exercise, converting \( \frac{3a}{5} \div \frac{9}{10a^2} \) involves using the reciprocal of \( \frac{9}{10a^2} \), which is \( \frac{10a^2}{9} \).
Thus, we rewrite it as \( \frac{3a}{5} \times \frac{10a^2}{9} \). This conversion simplifies the division problem into a multiplication problem,
which we can solve using the multiplication rules discussed earlier.
Other exercises in this chapter
Problem 42
For exercises \(5-48\), simplify. $$ \frac{2 c^{2}}{3 c^{3}+18 c^{2}+24 c}-\frac{6 c+56}{3 c^{3}+18 c^{2}+24 c} $$
View solution Problem 42
For exercises 39-82, simplify. $$ z \div \frac{1}{z} $$
View solution Problem 43
For exercises 1-66, simplify. $$ \frac{k^{2}-3 k-40}{k^{2}-4 k-45} $$
View solution Problem 44
For exercises \(41-44\), the formula \(R=\frac{V C}{T}\) describes the flow rate of fluid \(R\) through an intravenous drip. Is the relationship of the given va
View solution