Problem 43
Question
Find the least common multiple of the numbers. \(8,10,\) and 15
Step-by-Step Solution
Verified Answer
The least common multiple is 120.
1Step 1: Prime Factorization
Start by finding the prime factorization of each number.
- **Prime factors of 8**: 8 = 2 × 2 × 2 = 2^3
- **Prime factors of 10**: 10 = 2 × 5 = 2^1 × 5^1
- **Prime factors of 15**: 15 = 3 × 5 = 3^1 × 5^1
2Step 2: Determine the Highest Powers
Identify the highest power of each prime number that appears in the factorizations.
- The highest power of **2** is 2^3 from the number 8.
- The highest power of **3** is 3^1 from the number 15.
- The highest power of **5** is 5^1 from both 10 and 15.
3Step 3: Calculate the LCM
To find the least common multiple, multiply these highest powers together.\[LCM = 2^3 \times 3^1 \times 5^1 = 8 \times 3 \times 5\]Calculate:- 8 × 3 = 24- 24 × 5 = 120
4Step 4: Verify the Result
Ensure that 120 is divisible by each of the original numbers (8, 10, and 15) to verify correctness.
- 120 ÷ 8 = 15
- 120 ÷ 10 = 12
- 120 ÷ 15 = 8
Since all quotients are integers, the LCM is verified.
Key Concepts
Prime FactorizationHighest PowerDivisibility Verification
Prime Factorization
Prime factorization is a process of breaking down a number into a product of prime numbers. Prime numbers are numbers greater than 1 that have no divisors other than 1 and themselves. By identifying the prime factors of a given set of numbers, we're setting the stage for finding their least common multiple (LCM).
For instance, in our original exercise:
For instance, in our original exercise:
- 8 can be expressed as a product of 2s: \(8 = 2 \times 2 \times 2 = 2^3\).
- 10 breaks down into two primes: \(10 = 2 \times 5 = 2^1 \times 5^1\).
- 15 is expressed using the primes 3 and 5: \(15 = 3 \times 5 = 3^1 \times 5^1\).
Highest Power
After determining the prime factors, the next step involves identifying the highest power of each prime that appears in any of the factorizations. This step ensures that the final LCM will be divisible by each of the original numbers, without unnecessary repetitions of lower power primes.
- The number 8 presents the highest power of 2, as \(2^3\).
- The number 15 introduces the prime number 3 in the highest power \(3^1\) since there are no other threes in our initial factorization.
- The highest power of 5, \(5^1\), appears twice (in 10 and 15), but since both are to the 1st power, it remains \(5^1\).
Divisibility Verification
After calculating the Least Common Multiple, it is fundamental to verify the solution for accuracy. This step involves checking if the LCM is divisible by each of the original numbers.
This verification acts as a failsafe to ensure calculations were performed correctly. For our original problem, we determined the LCM to be 120. Here’s how you can confirm this:
This verification acts as a failsafe to ensure calculations were performed correctly. For our original problem, we determined the LCM to be 120. Here’s how you can confirm this:
- When divided by 8, \(120 \div 8 = 15\), which is an integer.
- Similarly, for 10, \(120 \div 10 = 12\), which is also an integer.
- And for 15, \(120 \div 15 = 8\), giving another integer.
Other exercises in this chapter
Problem 42
Determine the value of each of the powers. Use a calculator to check each result. \(100^{2}\)
View solution Problem 43
Use the order of operations to determine each value. \(\sqrt{6 \cdot 6}\)
View solution Problem 43
Find all the factors of each of the numbers. 218
View solution Problem 43
Find each value. Check each result with a calculator. \(\frac{51}{17}+7-2 \cdot 5 \cdot\left(\frac{12}{3}\right)\)
View solution