Problem 43
Question
Find the LCD of each pair of rational expressions. \(\frac{33}{15 a^{3}}, \frac{9}{10 a}\)
Step-by-Step Solution
Verified Answer
The LCD of the expressions is \(30a^3\).
1Step 1: Identify the Denominators
Look at the denominators of each rational expression. They are \(15a^3\) and \(10a\).
2Step 2: Determine the Prime Factorization of Coefficients
Break down the numerical parts of each denominator. \[15 = 3 imes 5\]\[10 = 2 imes 5\]
3Step 3: Identify the Variable Parts
The variable part of the first denominator is \(a^3\) and for the second it is \(a\).
4Step 4: Combine the Prime Factors and Variables for the LCD
To find the least common denominator (LCD), take the highest power of all prime numbers and variables that appear in the denominators:- Highest power of 2 is \(2^1\)- Highest power of 3 is \(3^1\)- Highest power of 5 is \(5^1\)- Highest power of \(a\) is \(a^3\)Thus, \[\text{LCD} = 2 imes 3 imes 5 imes a^3 = 30a^3\]
5Step 5: Verify the LCD
Verify that each denominator \(15a^3\) and \(10a\) can divide the \(30a^3\):- \(15 = 3 imes 5\) divides \(2 imes 3 imes 5\)- \(10 = 2 imes 5\) divides \(2 imes 3 imes 5\)- \(a^3\) divides \(a^3\); \(a\) divides \(a^3\)
Key Concepts
Understanding Rational ExpressionsExploring Prime FactorizationHandling Variables in Denominators
Understanding Rational Expressions
Rational expressions are similar to fractions but involve polynomials in the numerator and denominator. This means you are working with expressions that look like a fraction but with polynomial components. The denominator cannot be zero, just in the same way the denominator of a fraction cannot be zero. For example, in the exercise, we are dealing with \(\frac{33}{15a^3}\) and \(\frac{9}{10a}\). The key is to handle these expressions carefully, keeping in mind the rules of arithmetic for fractions and adding the layers of polynomial operations.
Exploring Prime Factorization
Prime factorization is crucial for simplifying the process of finding the Least Common Denominator (LCD). It involves breaking down numbers into their "prime" number building blocks, which are numbers greater than 1 that have no divisors other than 1 and themselves. To find the prime factorization of the denominators in our exercise, we break down 15 and 10 as follows:
- 15 becomes \(3 \times 5\).
- 10 becomes \(2 \times 5\).
Handling Variables in Denominators
Including variables in denominators requires careful attention. Like numbers, variables also follow rules for determining the LCD. In the exercise, variables are represented as powers of \(a\). It's important to keep track of the highest power of each variable, as it will contribute to the LCD determination:
- The first denominator includes \(a^3\).
- The second has \(a^1\) (simply \(a\)).
Other exercises in this chapter
Problem 43
Solve each equation and check the result. If an equation has no solution, so indicate. $$ \frac{x+6}{x+4}+\frac{1}{x^{2}+x-12}=1 $$
View solution Problem 43
Simplify. See Example 4. $$ \frac{6 x+3}{9} $$
View solution Problem 43
Divide, and then simplify, if possible. \(\frac{x^{3}}{18 y} \div \frac{x}{6 y}\)
View solution Problem 44
Perform the operations. Simplify, if possible. $$ \frac{1}{c+6}+\frac{4}{c^{2}+8 c+12} $$
View solution