Problem 43
Question
Find the inclination \(\theta\) (in radians and degrees) of the line. $$4 x+5 y-9=0$$
Step-by-Step Solution
Verified Answer
The inclination of the given line is \(\arctan(-\frac{4}{5})\) in radians and \(\arctan(-\frac{4}{5}) * \frac{180}{\pi}\) in degrees.
1Step 1: Transform equation into slope-intercept form
Rearrange the equation \(4x + 5y - 9 = 0\) to the form \(y = mx + c\). We get: \( y = -\frac{4}{5}x + \frac{9}{5} \). Thus, our slope \(m = -\frac{4}{5}\).
2Step 2: Find the angle in radians
The inclination \(\theta\) in radians is found by taking the inverse tangent (arctangent) of the slope. So, \(\theta = \arctan (m)\). By plugging in the slope we found earlier, we obtain: \(\theta = \arctan(-\frac{4}{5})\).
3Step 3: Find the angle in degrees
The inclination \(\theta\) in degrees is found by converting the radians to degrees. The formula is \(\theta_{\text{deg}} = \theta_{\text{rad}} * \frac{180}{\pi}\). By plugging our earlier answer, we get: \(\theta_{deg} = \arctan(-\frac{4}{5}) * \frac{180}{\pi}\).
Key Concepts
Slope-Intercept FormInverse TangentRadians to Degrees Conversion
Slope-Intercept Form
The slope-intercept form is a way of expressing the equation of a line. It is written as \( y = mx + c \), where:
First, move \( 4x \) to the other side of the equation, giving you \( 5y = -4x + 9 \). Then, divide everything by 5 to solve for \( y \), resulting in \( y = -\frac{4}{5}x + \frac{9}{5} \). This gives you the slope-intercept form and identifies the slope \( m \) as \( -\frac{4}{5} \). Understanding this form helps in analyzing and graphing linear equations efficiently.
- \( m \) is the slope of the line, which tells us how steep the line is.
- \( c \) is the y-intercept, where the line crosses the y-axis.
First, move \( 4x \) to the other side of the equation, giving you \( 5y = -4x + 9 \). Then, divide everything by 5 to solve for \( y \), resulting in \( y = -\frac{4}{5}x + \frac{9}{5} \). This gives you the slope-intercept form and identifies the slope \( m \) as \( -\frac{4}{5} \). Understanding this form helps in analyzing and graphing linear equations efficiently.
Inverse Tangent
The inverse tangent, also known as the arctangent, is a trigonometric function used to find angles. When you know the slope of a line, the inverse tangent can help you find the angle of inclination, \( \theta \), in radians.
The slope of a line \( m \) is related to the angle of inclination by the equation \( \theta = \arctan(m) \). This means you take the arctangent of the slope to find the angle in radians. for instance, for a slope \( m = -\frac{4}{5} \), you'd compute \( \theta = \arctan(-\frac{4}{5}) \).
The slope of a line \( m \) is related to the angle of inclination by the equation \( \theta = \arctan(m) \). This means you take the arctangent of the slope to find the angle in radians. for instance, for a slope \( m = -\frac{4}{5} \), you'd compute \( \theta = \arctan(-\frac{4}{5}) \).
- The inverse tangent function can handle both positive and negative slopes, making it versatile in finding the angle's direction.
- It's essential in determining how steep or shallow a line appears when graphed.
Radians to Degrees Conversion
Converting radians to degrees is a significant step to make angles more interpretable, as degrees are widely used in everyday contexts. The conversion is completed using the formula:
For instance, if the radian measure is \( \arctan(-\frac{4}{5}) \) from a previous computation, applying the conversion formula will give you the angle in degrees. Doing this allows for easier understanding of an angle's position or rotation, which is crucial in many fields such as navigation and engineering. Keeping a calculator handy is useful, as it simplifies and speeds up the conversion process.
- \( \theta_{\text{deg}} = \theta_{\text{rad}} \times \frac{180}{\pi} \)
For instance, if the radian measure is \( \arctan(-\frac{4}{5}) \) from a previous computation, applying the conversion formula will give you the angle in degrees. Doing this allows for easier understanding of an angle's position or rotation, which is crucial in many fields such as navigation and engineering. Keeping a calculator handy is useful, as it simplifies and speeds up the conversion process.
Other exercises in this chapter
Problem 43
A point in rectangular coordinates is given. Convert the point to polar coordinates. $$(1,1)$$
View solution Problem 43
Sketch the graph of the polar equation using symmetry, zeros, maximum \(r\) -values, and any other additional points. $$r=2 \sec \theta$$
View solution Problem 43
Use a graphing utility to graph the curve represented by the parametric equations. $$\begin{array}{l} x=4 \sec \theta \\ y=2 \tan \theta \end{array}$$
View solution Problem 43
Find the vertex, focus, and directrix of the parabola. Use a graphing utility to graph the parabola. $$x^{2}+4 x+6 y-2=0$$
View solution