Problem 43
Question
Find the area under the curve for each function and interval given, using the rectangle method and \(n\) subintervals of equal width. $$f(x)=-\frac{1}{2} x^{2}+4 x, x \in[0,6]$$
Step-by-Step Solution
Verified Answer
Use the midpoint rectangle method with \(n\) subintervals for the function within the interval \([0,6]\) to approximate the area.
1Step 1: Determine Subinterval Width
The interval of integration is \([0, 6]\), meaning the total length of the interval is 6. Given \(n\) subintervals, each subinterval will have a width of \(\Delta x = \frac{6}{n}\).
2Step 2: Identify Midpoint of Each Subinterval
For the midpoint rectangle method, the midpoint \(x_i\) of each subinterval \([x_{i-1}, x_i]\) is given by \(x_i = x_{i-1} + \frac{\Delta x}{2}\), where \(x_{i-1} = (i-1)\Delta x\). Calculate \(x_i\) for each subinterval using these formulas.
3Step 3: Evaluate the Function at Each Midpoint
Calculate the value of the function \(f(x) = -\frac{1}{2}x^2 + 4x\) at each midpoint \(x_i\). This gives the height of each rectangle: \(f(x_i)\).
4Step 4: Calculate Area of Each Rectangle
The area of each rectangle is given by the product of the height and the width: \(\text{Area}_i = f(x_i) \cdot \Delta x\). Sum these areas over all subintervals.
5Step 5: Sum the Areas of All Rectangles
The total approximate area under the curve is the sum of the areas of all \(n\) rectangles, \(\sum_{i=1}^{n} \text{Area}_i = \sum_{i=1}^{n} f(x_i) \cdot \Delta x\).
6Step 6: Calculate the Approximate Area
Substitute step 2 and 3 expressions in the summation from step 5. Simplify and calculate to find the total approximate area under the curve.
Key Concepts
Subinterval WidthMidpoint ApproximationFunction Evaluation at MidpointsArea Approximation
Subinterval Width
The concept of subinterval width is crucial when using the rectangle method for approximating areas under a curve. To divide an interval into equal parts with clear boundaries, we determine the width, Δx, of each subinterval. Consider an interval [0,6], split into nequally sized subintervals. The width of each subinterval is given by the formula: Δx = \( \frac{6}{n} \). This ensures that the entire range from 0 to 6 is covered evenly.
- Each subinterval has the same width of Δx.
- Knowing the width helps in further calculations, including midpoint determination and area approximation.
Midpoint Approximation
Midpoint approximation is a key step in utilizing the rectangle method for area estimation. Each rectangle’s height is determined by evaluating the function at the midpoint of each subinterval. Here's how to find the midpoints: the midpoint x_iof each subinterval [x_{i-1}, x_i] is calculated using:x_i = x_{i-1} + \( \frac{Δx}{2} \), where x_{i-1} = (i-1)Δx.
This method ensures that the function's value at the center of each subinterval is used, which typically provides a better approximation than using either endpoint.
This method ensures that the function's value at the center of each subinterval is used, which typically provides a better approximation than using either endpoint.
- The midpoint offers a balance, taking into account the function’s behavior across the subinterval.
- Accurate midpoints lead to more reliable area estimations.
Function Evaluation at Midpoints
Evaluating the function at midpoints involves substituting these points into the given function to determine each rectangle's height under the curve. For the function f(x) = -\( \frac{1}{2}x^2 + 4x \), we compute f(x_i)at each midpoint x_i.This gives us the height of the rectangle corresponding to each subinterval.
- The calculation of f(x_i)provides the rectangle’s height.
- A correct evaluation ensures the approximation closely represents the curve’s shape.
Area Approximation
The final step in the rectangle method is the calculation of the approximate area under the curve.In this step, we multiply the height of each rectangle f(x_i)obtained from function evaluation at midpoints by the subinterval width Δx.This product yields the area of each individual rectangle:Area_i = \( f(x_i) \cdot Δx \).
To find the total approximate area, sum all individual areas: \(\sum_{i=1}^{n} f(x_i) \cdot Δx\).
To find the total approximate area, sum all individual areas: \(\sum_{i=1}^{n} f(x_i) \cdot Δx\).
- This summation provides a practical estimate of the integral over the interval [0,6].
- A greater number of subintervals (n)usually results in a more accurate approximation.
Other exercises in this chapter
Problem 43
In each part, determine where \(f\) is differentiable. (a) \(f(x)=\sin x\) (b) \(f(x)=\cos x\) (c) \(f(x)=\tan x\) (d) \(f(x)=\cot x\) (e) \(f(x)=\sec x\) (f) \
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Evaluate the following limits. Write your answer in simplest form. $$\lim _{h \rightarrow 0} \frac{(x+h+2)^{3}-(x+2)^{3}}{h}$$
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Write each statement using limit notation. As \(x\) approaches 3 from the left, \(I_{x}\) approaches \(3 \cos ^{2}\left(R_{1}+R_{2}\right)\)
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Evaluate the following limits. Write your answer in simplest form. $$\lim _{h \rightarrow 0} \frac{(x+h-4)^{3}-(x-4)^{3}}{h}$$
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