Problem 43
Question
Find or evaluate the integral using substitution first, then using integration by parts. $$ \int \cos (\ln x) d x $$
Step-by-Step Solution
Verified Answer
The result of the integral \( \int \cos (\ln x) dx \) using both methods, substitution and integration by parts, is \( x\ln{x} - x + C \).
1Step 1: Identify a suitable substitution
Identify that \( u = \ln x \) is a suitable substitution. Use this to simplify the integral. We must also calculate the derivative of \( u \), which is \( du = (1/x) dx \). Multiplied both sides by \( x \), we get \( dx = x du \). This substitution changes the integral into a format that we can evaluate.
2Step 2: Compute the integral with substitution
Replace \( \ln x \) and \( dx \) in the equation with the substitution results to get \( \int cos(u) \cdot x du \). This integral can be solved using integration by parts.
3Step 3: Integration by parts
For the integration by parts, let \( v = x \) and \( du = cos(u) du \). Then, \( dv = dx \) and \( u = \ln{x} \). We can use integration by parts formula \( \int udv = uv - \int vdu \) substituting the u, v, du, and dv accordingly. The integral thus becomes \( \int cos(u) \cdot x du = x\ln{x} - \int x du \).
4Step 4: Further simplification and final integral
The next integral to be solved is \( \int x du \). This can be simplified to \( \int x (1/x) dx = \int dx \). Solving this integral gives \( x \). Therefore, the final integral becomes: \( x\ln{x} - x + C \) where C is the integration constant.
Other exercises in this chapter
Problem 43
Evaluate $$\int_{0}^{\pi / 2} \frac{d x}{1+(\tan x)^{\sqrt{2}}}$$.
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State the substitution you would make if you used trigonometric substitution and the integral involving the given radical, where \(a>0\). Explain your reasoning
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Given continuous functions \(f\) and \(g\) such that \(0 \leq f(x) \leq g(x)\) on the interval \([a, \infty),\) prove the following. (a) If \(\int_{a}^{\infty}
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Find the integral. Use a computer algebra system to confirm your result. $$ \int \tan ^{4} \frac{x}{2} \sec ^{4} \frac{x}{2} d x $$
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