Problem 43
Question
Factor using the Binomial Theorem. $$ x^{4}+4 x^{3} y+6 x^{2} y^{2}+4 x y^{3}+y^{4} $$
Step-by-Step Solution
Verified Answer
The expression factors to \((x+y)^4\).
1Step 1: Recognize the Expression Structure
First, look at the given expression \(x^{4}+4 x^{3} y+6 x^{2} y^{2}+4 x y^{3}+y^{4}\). Notice that it follows the pattern of a binomial expansion.
2Step 2: Identify the Binomial Form
This expression resembles the expansion of \((x+y)^4\) using the Binomial Theorem, which states that \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\). Verify each term: \(\binom{4}{0}x^4y^0,\ \binom{4}{1}x^3y^1,\ \binom{4}{2}x^2y^2,\ \binom{4}{3}x^1y^3,\ \binom{4}{4}x^0y^4\).
3Step 3: Verify the Binomial Coefficients
Assess the coefficients for each term: \(1, 4, 6, 4, 1\). These coefficients match the binomial coefficients of \((x+y)^4\) which are calculated as \(\binom{4}{0} = 1\), \(\binom{4}{1} = 4\), \(\binom{4}{2} = 6\), \(\binom{4}{3} = 4\), \(\binom{4}{4} = 1\).
4Step 4: Confirm and Write the Factorized Expression
By confirming that the structure and coefficients match, recognize that the expression \(x^{4}+4 x^{3} y+6 x^{2} y^{2}+4 x y^{3}+y^{4}\) is indeed the expansion of \((x+y)^4\). Thus, the factorized form is \((x+y)^4\).
Key Concepts
FactorizationBinomial ExpansionBinomial Coefficients
Factorization
Factorization is the mathematical process of breaking down an expression into simpler "factors" that, when multiplied together, give the original expression. This is like taking a complex puzzle and finding all the smaller pieces that make it up. In the exercise, the expression \(x^{4} + 4x^{3}y + 6x^{2}y^{2} + 4xy^{3} + y^{4}\) is factorized into \((x+y)^4\) using the concept of binomial expansion. To factorize, you need to observe the structure of the expression to find a common form. Once you recognize that the terms share similarities, such as the presence of powers of \(x\) and \(y\) in a symmetrical pattern, you can apply the Binomial Theorem to simplify the expression into its factorized form. This process allows you to understand the deep connection between the terms and their unified construction.
Binomial Expansion
Binomial expansion refers to the process of expanding expressions that are raised to a power. Using the Binomial Theorem, expressions like \((a+b)^n\) can be expanded into a series of terms. Binomial expansion helps in finding out how each part of a binomial expression contributes to the whole, by expanding it into simpler addends. In the given problem, the original polynomial \(x^{4} + 4x^{3}y + 6x^{2}y^{2} + 4xy^{3} + y^{4}\) is an example of an expanded binomial of the form \((x+y)^4\). Each term follows the structure dictated by the theorem, which involves different combinations of powers of \(x\) and \(y\), multiplied by binomial coefficients. Understanding binomial expansion allows you to both expand and later, if required, simplify back into its compact binomial form.
Binomial Coefficients
Binomial coefficients are the numerical values that multiply the terms in a binomial expansion. They represent how many ways you can choose elements within a set, often denoted as \( \binom{n}{k} \), which is read as "n choose k". These coefficients play a vital role in determining the contribution of each term in an expanded binomial expression. For example, in the polynomial given in the exercise, the coefficients 1, 4, 6, 4, and 1 correspond to \( \binom{4}{0} \), \( \binom{4}{1} \), \( \binom{4}{2} \), \( \binom{4}{3} \), and \( \binom{4}{4} \) respectively. Each coefficient indicates the number of ways to combine \(x\) and \(y\) terms of certain degrees in the expansion. They can be quickly calculated using Pascal's triangle or the formula involving factorials: \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \). By understanding and using binomial coefficients, you can expertly navigate through binomial expansions and make sense of the expression's structure.
Other exercises in this chapter
Problem 43
Find the partial sum \(S_{n}\) of the geometric sequence that satisfies the given conditions. $$ a=5, \quad r=2, \quad n=6 $$
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\(41-48\) Find the sum. $$ \sum_{k=1}^{3} \frac{1}{k} $$
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\(43-48\) . Find the partial sum \(S_{n}\) of the arithmetic sequence that satisfies the given conditions. $$ a=3, d=2, n=12 $$
View solution Problem 44
Find the partial sum \(S_{n}\) of the geometric sequence that satisfies the given conditions. $$ a=\frac{2}{3}, \quad r=\frac{1}{3}, \quad n=4 $$
View solution