Problem 43
Question
Express the first trigonometric function in terms of the second. $$ \cot \theta, \csc \theta $$
Step-by-Step Solution
Verified Answer
The expression of \(\cot \theta\) in terms of \(\csc \theta\) is \(\sqrt{\csc^2 \theta - 1}\).
1Step 1: Express Cotangent in Terms of Sine and Cosine
We start by expressing the cotangent function, \(\cot \theta\), in terms of cosine and sine. \(\cot \theta = \frac{\cos \theta}{\sin \theta}\)
2Step 2: Replace Sine with its Reciprocal
Next, we replace \(\sin \theta\) with \(\frac{1}{\csc \theta}\). So, our \(\cot \theta\) becomes \(\cot \theta = \frac{\cos \theta}{\frac{1}{\csc \theta}} = \cos \theta * \csc \theta\).
3Step 3: Replace Cosine with Cosecant
Remember that, \(\cos \theta = \sqrt{1 - \sin^2 \theta}\). Since \(\sin \theta = \frac{1}{\csc \theta}\), we can write \(\cos \theta = \sqrt{1 - \left(\frac{1}{\csc \theta}\right)^2} = \sqrt{\frac{\csc^2 \theta - 1}{\csc^2 \theta}} = \frac{\sqrt{\csc^2 \theta - 1}}{\csc \theta}\). Therefore, \(\cot \theta = \frac{\sqrt{\csc^2 \theta - 1}}{\csc \theta} * \csc \theta = \sqrt{\csc^2 \theta - 1}\).
Key Concepts
Cotangent FunctionCosecant FunctionSin and Cos Relationships
Cotangent Function
The cotangent function, often symbolized as \( \cot \theta \), is a trigonometric ratio that is the reciprocal of the tangent function. Essentially, it gives us the ratio of the adjacent side to the opposite side in a right-angled triangle. This can be interpreted as:
- \( \cot \theta = \frac{1}{\tan \theta} \)
- In terms of sine and cosine, it is expressed as \( \cot \theta = \frac{\cos \theta}{\sin \theta} \)
Cosecant Function
The cosecant function, denoted as \( \csc \theta \), is another reciprocal trigonometric function. It is specifically the reciprocal of sine, providing a relation reflecting the length dynamics of the hypotenuse to the opposite side in a triangle:
- \( \csc \theta = \frac{1}{\sin \theta} \)
- This implies that \( \sin \theta = \frac{1}{\csc \theta} \)
Sin and Cos Relationships
Sine and cosine functions form the foundational core of trigonometry. Understanding the relationship between these functions is essential, especially when translating between different trigonometric equations. Here’s how it works:
- The Identity: \( \sin^2 \theta + \cos^2 \theta = 1 \)
- Express Cosine in terms of Sine: \( \cos \theta = \sqrt{1 - \sin^2 \theta} \)
Other exercises in this chapter
Problem 43
Reasoning Show that the equation \(\sin (A+B)=\sin A+\sin B\) is not an identity by finding a counterexample, values for \(A\) and \(B\) for which the equation
View solution Problem 43
Sailing Buoys are located in the sea at points \(A, B,\) and \(C . \angle A C B\) is a right angle. \(A C=3.0 \mathrm{mi}, B C=4.0 \mathrm{mi},\) and \(A B=5.0
View solution Problem 44
Use identities to write each equation in terms of the single angle \(\theta .\) Then solve the equation for \(0 \leq \theta
View solution Problem 44
In \(\Delta R S T, t=7 \mathrm{ft}\) and \(s=13 \mathrm{ft}\) . Find each value to the nearest tenth. Find \(r\) for \(m \angle R=35^{\circ}\)
View solution