Problem 43
Question
Evaluate the integrals. $$\int \frac{d x}{\sqrt{9-x^{2}}}$$
Step-by-Step Solution
Verified Answer
The integral evaluates to \( \arcsin\left(\frac{x}{3}\right) + C \).
1Step 1: Identify the form of the integrand
The integrand \( \frac{1}{\sqrt{9-x^2}} \) resembles the derivative of the arcsine function. The derivative of \( \arcsin(x) \) is \( \frac{1}{\sqrt{1-x^2}} \). Notice that the expression under the square root is \( 9-x^2 = 3^2 - x^2 \), which suggests a trigonometric substitution might be suitable.
2Step 2: Apply trigonometric substitution
Use the substitution \( x = 3 \sin(\theta) \), which implies \( dx = 3 \cos(\theta) \, d\theta \). The integral becomes \( \int \frac{3 \cos(\theta) \, d\theta}{\sqrt{9 - 9\sin^2(\theta)}} \). Using the identity \( \cos^2(\theta) = 1 - \sin^2(\theta) \), the integral simplifies to \( \int 1 \, d\theta \).
3Step 3: Evaluate the simplified integral
The integral \( \int 1 \, d\theta \) is straightforward and evaluates to \( \theta + C \), where \( C \) is the constant of integration.
4Step 4: Reverse the trigonometric substitution
Since \( x = 3 \sin(\theta) \), we find \( \theta = \arcsin\left(\frac{x}{3}\right) \). Hence, the solution to the original integral is \( \arcsin\left(\frac{x}{3}\right) + C \).
Key Concepts
Trigonometric SubstitutionArcsine FunctionCalculus Integration
Trigonometric Substitution
Trigonometric substitution is a powerful technique used in calculus for simplifying integrals that involve square roots of quadratic polynomials. The idea is to transform the integral into a simpler form by using trigonometric identities.
Here's why it's helpful:
The real challenge lies in choosing the correct trigonometric identity or substitution. In this example, the expression \( 9-x^2 \) triggers the use of \( ext{sin} \) because it fits the Pythagorean trigonometric identity structure.
Here's why it's helpful:
- It exploits the Pythagorean identity: For example, we know that \( heta \) in trigonometric functions often relates through \( ext{sin}^2(\theta) + ext{cos}^2(\theta) = 1 \).
- This allows the integrand to simplify nicely, often transforming the square root expression into a simple form using trigonometric functions.
The real challenge lies in choosing the correct trigonometric identity or substitution. In this example, the expression \( 9-x^2 \) triggers the use of \( ext{sin} \) because it fits the Pythagorean trigonometric identity structure.
Arcsine Function
The arcsine function, denoted as \( \arcsin(x) \), is the inverse of the sine function and is crucial in integral calculus. It helps in determining angles from given sine values.
In the context of integration, identifying an integral with a form resembling the derivative of arcsine can simplify solving it.
In the context of integration, identifying an integral with a form resembling the derivative of arcsine can simplify solving it.
- Derivative of arcsine: The derivative \( \frac{d}{dx} \arcsin(x) = \frac{1}{\sqrt{1-x^2}} \) is critical for recognizing similar integral forms.
- This derivative matches the general form \( \frac{1}{\sqrt{a^2-x^2}} \), where \( a \) is a constant.
Calculus Integration
Integration constitutes one of the two fundamental operations of calculus, used to find areas under curves among other applications. In particular, calculus integration often involves antiderivatives and definite and indefinite integrals.
Indefinite integrals, like the one in this problem, are a primary type where we seek an antiderivative of a given function.
Indefinite integrals, like the one in this problem, are a primary type where we seek an antiderivative of a given function.
- Understanding the basic rules and techniques, such as substitution and integration of trigonometric identities, provides tools to evaluate complex functions.
- Integration can transform complex algebraic expressions into their respective antiderivatives, simplifying functions and solving equations.
Other exercises in this chapter
Problem 43
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Suppose that the differentiable function \(y=f(x)\) has an inverse and that the graph of \(f\) passes through the point (2,4) and has a slope of \(1 / 3\) there
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