Problem 43
Question
Evaluate expression. \(P(52,0)\)
Step-by-Step Solution
Verified Answer
1
1Step 1: Understand the Permutation Formula
The permutation formula is given by \[ P(n, k) = \frac{n!}{(n - k)!} \]where \(n\) is the total number of items, \(k\) is the number of items to choose from, and \(!\) denotes factorial.
2Step 2: Substitute Values into the Formula
For the given problem \(P(52, 0)\), substitute \(n = 52\) and \(k = 0\) into the permutation formula:
3Step 3: Evaluate the Factorials
Calculate the factorial values needed: \[ P(52, 0) = \frac{52!}{(52 - 0)!} = \frac{52!}{52!} \]
4Step 4: Simplify the Expression
Since the factorial expressions \(52!\) in the numerator and denominator are the same, they cancel each other out. Therefore, \[ \frac{52!}{52!} = 1 \]
5Step 5: Conclude the Result
Hence \[ P(52, 0) = 1 \]
Key Concepts
FactorialPermutation FormulaCombinatoricsAlgebra
Factorial
In mathematics, the factorial of a non-negative integer is the product of all positive integers less than or equal to that number. It's denoted by the symbol \(!\). For example, \(!5\) (read as 'five factorial') is calculated as follows:
\[ 5! = 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 = 120 \] The factorial function grows very quickly. Even for relatively small numbers, the factorial can be quite large. For 0, it's defined that \(!0 = 1\). This definition helps in simplifying various mathematical expressions and maintaining consistency in equations.
\[ 5! = 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 = 120 \] The factorial function grows very quickly. Even for relatively small numbers, the factorial can be quite large. For 0, it's defined that \(!0 = 1\). This definition helps in simplifying various mathematical expressions and maintaining consistency in equations.
Permutation Formula
Permutations refer to the different possible arrangements of a set of items. The order in which we arrange the items matters in permutations. The formula for permutations is given by:
\[ P(n, k) = \frac{n!}{(n - k)!} \] Here, \(n\) represents the total number of items, and \(k\) is the number of items to be arranged. The factorial in the numerator (\(n!\)) provides the number of ways to arrange all \(n\) items, while the factorial in the denominator (\((n - k)!\)) removes the excess arrangements when fewer than \(n\) items are being selected. Using this formula, the specific permutation for \(P(52, 0)\) was found by substituting the values into it.
\[ P(n, k) = \frac{n!}{(n - k)!} \] Here, \(n\) represents the total number of items, and \(k\) is the number of items to be arranged. The factorial in the numerator (\(n!\)) provides the number of ways to arrange all \(n\) items, while the factorial in the denominator (\((n - k)!\)) removes the excess arrangements when fewer than \(n\) items are being selected. Using this formula, the specific permutation for \(P(52, 0)\) was found by substituting the values into it.
Combinatorics
Combinatorics is a branch of mathematics dealing with combinations, permutations, and counting. It provides tools and formulas to count the ways objects can be chosen or arranged. In this exercise, we used a specific formula from combinatorics to determine permutations. Combinatorics includes:
- Permutations: Arrangements where order matters.
- Combinations: Selections where order does not matter.
Algebra
Algebra often deals with symbols and the rules for manipulating these symbols to solve equations or perform calculations. In solving permutation problems like \(P(52, 0)\), understanding algebraic manipulation is key. We used algebra to:
- Substitute values into a given formula.
- Simplify expressions.
- Solve factorial equations.
Other exercises in this chapter
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