Problem 43
Question
Evaluate \(2(x+h) 2-5(x+h)+3,\) given \(x=2\) and \(h=0.1\)
Step-by-Step Solution
Verified Answer
The expression evaluates to 1.32.
1Step 1: Substitute the Values
Start by substituting the given values of \(x = 2\) and \(h = 0.1\) into the expression \(2(x+h)^2 - 5(x+h) + 3\). This results in the expression \(2(2+0.1)^2 - 5(2+0.1) + 3\).
2Step 2: Simplify Inside the Parentheses
Add \(x\) and \(h\) inside the parentheses to get \(2.1\). So, the expression becomes \(2(2.1)^2 - 5(2.1) + 3\).
3Step 3: Square the Term
Calculate \((2.1)^2\), which equals \(4.41\). Substitute back into the expression to get \(2(4.41) - 5(2.1) + 3\).
4Step 4: Multiply the Squared Term
Multiply \(2\) and \(4.41\) to get \(8.82\). The expression now reads \(8.82 - 5(2.1) + 3\).
5Step 5: Multiply the Linear Term
Multiply \(5\) and \(2.1\) to get \(10.5\). Now the expression becomes \(8.82 - 10.5 + 3\).
6Step 6: Combine the Terms
Subtract \(10.5\) from \(8.82\) to get \(-1.68\) and then add \(3\) to \(-1.68\) to arrive at the final result. The final result is \(1.32\).
Key Concepts
Evaluating ExpressionsSubstitution in AlgebraSimplifying Algebraic Expressions
Evaluating Expressions
Evaluating algebraic expressions involves finding the value of the expression by substituting numbers for the variables. This is a fundamental skill in algebra. When given an expression and specific values for the variables, you perform operations to simplify and arrive at a numerical result.
In the given exercise, you begin with the expression \(2(x+h)^2 - 5(x+h) + 3\). The values provided are \(x = 2\) and \(h = 0.1\). Start by replacing these variables with the given numbers, transforming the expression into a numeric form:
In the given exercise, you begin with the expression \(2(x+h)^2 - 5(x+h) + 3\). The values provided are \(x = 2\) and \(h = 0.1\). Start by replacing these variables with the given numbers, transforming the expression into a numeric form:
- Substitute \(x = 2\) and \(h = 0.1\)
- The expression becomes \(2(2+0.1)^2 - 5(2+0.1) + 3\)
Substitution in Algebra
Substitution is a key technique in algebra that involves replacing variables in an expression with their actual values or numbers. This process helps in evaluating the expression to find its numerical value.
Here's a simple way to substitute:
After substitution, proceed with operational steps such as simplifying within parentheses, performing basic arithmetic operations, like squaring numbers, multiplying, and combining terms.
Here's a simple way to substitute:
- Ensure you clearly know the values you are substituting. In our example: \(x = 2\) and \(h = 0.1\).
- Replace every occurrence of the variables \(x\) and \(h\) with these numbers.
After substitution, proceed with operational steps such as simplifying within parentheses, performing basic arithmetic operations, like squaring numbers, multiplying, and combining terms.
Simplifying Algebraic Expressions
Simplifying expressions involves reducing them to their simplest form, making calculations easier and clearer. Here's how you can simplify the expression from the given problem:
- First, solve inside the parentheses. Add \(2\) and \(0.1\) to get \(2.1\).
- Next, square the result: \((2.1)^2 = 4.41\).
- Then, follow the order of operations, multiplying and subtracting the results: \(2 \times 4.41 = 8.82\) and \(5 \times 2.1 = 10.5\).
- Subtract \(10.5\) from \(8.82\) to get \(-1.68\) and finally, add \(3\) to result in \(1.32\).
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