Problem 43
Question
Change each radical to simplest radical form. \(\sqrt{\frac{75}{81}}\)
Step-by-Step Solution
Verified Answer
\(\frac{5\sqrt{3}}{9}\)
1Step 1: Simplify Inside the Radical
First, simplify the fraction under the square root sign. The fraction is \(\frac{75}{81}\). Note that both 75 and 81 can be divided by 3. Simplify it to \(\frac{25}{27}\).
2Step 2: Prime Factorization
Perform prime factorization on the numerator and the denominator separately. The number 25 is \(5^2\), and 27 is \(3^3\).
3Step 3: Rewrite the Radical
Rewrite \(\sqrt{\frac{25}{27}}\) as \(\frac{\sqrt{25}}{\sqrt{27}}\).
4Step 4: Simplify Each Square Root
Simplify \(\sqrt{25}\) to 5, since 25 is a perfect square. Simplify \(\sqrt{27}\) to \(3\sqrt{3}\) because 27 is \(3^3\), and you can take out \(\sqrt{9} = 3\), leaving \(\sqrt{3}\).
5Step 5: Combine the Results
Combine the simplified forms: \(\frac{5}{3\sqrt{3}}\).
6Step 6: Rationalize the Denominator
Multiply both the numerator and the denominator by \(\sqrt{3}\) to remove the radical in the denominator. This gives \(\frac{5\sqrt{3}}{9}\).
Key Concepts
Prime FactorizationRationalizing the DenominatorSquare Roots Simplification
Prime Factorization
Prime factorization involves breaking down a number into its smallest prime factors. It’s a method used to simplify numbers by expressing them as a multiplication of prime numbers.
For instance, when simplifying \[\sqrt{\frac{75}{81}}\] in the original exercise, we first needed to simplify the fraction to \(\frac{25}{27}\). Prime factorization tells us that 25 is composed of two 5s, as \(25 = 5^2\), and 27 is made up of three 3s, or \(27 = 3^3\).
For instance, when simplifying \[\sqrt{\frac{75}{81}}\] in the original exercise, we first needed to simplify the fraction to \(\frac{25}{27}\). Prime factorization tells us that 25 is composed of two 5s, as \(25 = 5^2\), and 27 is made up of three 3s, or \(27 = 3^3\).
- This breakdown reveals that 25 and 27 are not perfect square ratios, so we must simplify further.
- Prime factorization is essential to identify the parts of a number we can simplify, particularly when dealing with square roots.
Rationalizing the Denominator
Rationalizing the denominator involves removing the square root or the radical from the denominator of a fraction.
This is often required because a simpler form of a fraction without recourse to square roots in its denominator is more conventional in mathematics. In the original solution, after simplifying to \[\frac{5}{3\sqrt{3}}\] this step was necessary:
This is often required because a simpler form of a fraction without recourse to square roots in its denominator is more conventional in mathematics. In the original solution, after simplifying to \[\frac{5}{3\sqrt{3}}\] this step was necessary:
- We multiply both the numerator and the denominator by \(\sqrt{3}\), which is the radical present in the denominator, to maintain the equality of the expression.
- This yields \(\frac{5\sqrt{3}}{9}\), a form without radicals in the denominator.
Square Roots Simplification
Simplifying square roots means reducing the expression under the radical sign to its simplest form.
This is achieved by factoring the expression and extracting the perfect squares. In our step-by-step solution:
This is achieved by factoring the expression and extracting the perfect squares. In our step-by-step solution:
- We simplified \(\sqrt{25}\) to 5, as 25 is a perfect square, leaving a clean expression free from radicals.
- The square root of 27 became \(3\sqrt{3}\), after identifying 9 (a perfect square) within 27, hence \(\sqrt{27} = \sqrt{9 \times 3} = 3\sqrt{3}\).
Other exercises in this chapter
Problem 43
Find the following products and express answers in simplest radical form. All variables represent nonnegative real numbers. \((\sqrt{6}+4)(\sqrt{6}-4)\)
View solution Problem 43
Express each of the following in simplest radical form. All variables represent positive real numbers. \(\frac{\sqrt{7 x}}{\sqrt{8 y^{5}}}\)
View solution Problem 43
For Problems \(43-62\), simplify each expression. Express final results without using zero or negative integers as exponents. \(x^{2} \cdot x^{-8}\)
View solution Problem 44
Use scientific notation and the properties of exponents to help you perform the following operations. \(\frac{(0.00016)(300)(0.028)}{0.064}\)
View solution