Problem 43
Question
At \(20^{\circ} \mathrm{C},\) the vapor pressure of cthanol is 45 torr and the vapor pressure of methanol is 92 torr. What is the vapor pressure at \(20^{\circ} \mathrm{C}\) of a solution prepared by mixing \(25 \mathrm{g}\) of methanol and \(75 \mathrm{g}\) of ethanol?
Step-by-Step Solution
Verified Answer
Answer: The vapor pressure of the solution at 20°C is 60.2 torr.
1Step 1: Calculate the mole fractions of ethanol and methanol
We are given 25 grams of methanol and 75 grams of ethanol. We need to find the mole fraction of each component in the solution. To do this, we first need the molar mass of each component:
- Molar mass of methanol (CH3OH): 12.01 (C) + 3x1.01 (H) + 16.00 (O) + 1.01 (H) = 32.04 g/mol
- Molar mass of ethanol (C2H5OH): 12.01x2 (C) + 5x1.01 (H) + 16.00 (O) + 1.01 (H) = 46.07 g/mol
Next, we find the moles of each component in the solution:
- Moles of methanol: 25 g / 32.04 g/mol = 0.780 mol
- Moles of ethanol: 75 g / 46.07 g/mol = 1.628 mol
Now we can find the mole fraction of each component:
- Mole fraction of methanol (X_methanol): 0.780 mol / (0.780 + 1.628) mol = 0.324
- Mole fraction of ethanol (X_ethanol): 1.628 mol / (0.780 + 1.628) mol = 0.676
2Step 2: Apply Raoult's Law to find the partial vapor pressures
Raoult's Law states that the partial vapor pressure of a component in an ideal solution is equal to the mole fraction of that component multiplied by its vapor pressure in the pure state. We are given the pure vapor pressure of methanol (92 torr) and ethanol (45 torr). To calculate the partial vapor pressure of each component in the solution, use the following formula:
Partial vapor pressure = mole fraction x pure vapor pressure
- Partial vapor pressure of methanol: 0.324 x 92 torr = 29.8 torr
- Partial vapor pressure of ethanol: 0.676 x 45 torr = 30.4 torr
3Step 3: Calculate the total vapor pressure of the solution
The total vapor pressure of the solution is the sum of the partial vapor pressures of each component. So, we just need to add the partial vapor pressures of methanol and ethanol:
Total vapor pressure = partial vapor pressure of methanol + partial vapor pressure of ethanol
Total vapor pressure = 29.8 torr + 30.4 torr = 60.2 torr
Therefore, the vapor pressure of the solution at 20°C is 60.2 torr.
Key Concepts
Vapor Pressure ConceptMole Fractions and Their RoleUnderstanding Partial Vapor Pressures
Vapor Pressure Concept
Vapor pressure is an important concept in chemistry, particularly when dealing with solutions and mixtures. It refers to the pressure exerted by a vapor when it is in equilibrium with its liquid form at a given temperature. This pressure is a measure of a liquid's tendency to evaporate and is determined by the intermolecular forces present.
Stronger forces within the liquid mean fewer molecules escape into the vapor phase, resulting in lower vapor pressure. Conversely, weaker intermolecular attractions allow for more evaporation, leading to higher vapor pressure.
Stronger forces within the liquid mean fewer molecules escape into the vapor phase, resulting in lower vapor pressure. Conversely, weaker intermolecular attractions allow for more evaporation, leading to higher vapor pressure.
- In pure substances, the vapor pressure is specific to a given temperature.
- For a mixture of substances, the overall vapor pressure is influenced by the individual vapor pressures of the components.
Mole Fractions and Their Role
Mole fraction is a way of expressing the concentration of a component in a mixture. It is defined as the number of moles of one component divided by the total number of moles of all components in the mixture. This measure is unitless and gives us a simple ratio expressing how much of the total mixture is made up by a particular component.
The mole fraction is particularly useful because it directly relates to vapor pressure through Raoult's Law, providing a means to calculate how each component's potential to evaporate contributes to the overall vapor pressure.
The mole fraction is particularly useful because it directly relates to vapor pressure through Raoult's Law, providing a means to calculate how each component's potential to evaporate contributes to the overall vapor pressure.
- The mole fraction of a component can vary from 0 to 1, where 0 means it is absent, and 1 means it is the only substance present.
- In solutions, the sum of mole fractions of all components equals 1.
Understanding Partial Vapor Pressures
Partial vapor pressures refer to the individual pressures exerted by each component in a mixture. They are a key concept when using Raoult's Law to find the total vapor pressure of a solution. To determine the partial vapor pressure of each component, multiply its mole fraction by its vapor pressure in the pure state.
This gives insight into how each component contributes to the overall pressure observed.
This gives insight into how each component contributes to the overall pressure observed.
- Partial pressures reflect the behavior and interaction of components within the mixture as they evaporate.
- The concept of partial pressure is crucial when understanding and predicting the behaviors of gases and volatile liquids.
Other exercises in this chapter
Problem 41
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