Problem 43
Question
At \(100^{\circ} \mathrm{C},\) the equilibrium constant for the reaction \(\mathrm{COCl}_{2}(g) \rightleftharpoons \mathrm{CO}(g)+\mathrm{Cl}_{2}(g)\) has the value \(K_{c}=2.19 \times 10^{-10} .\) Are the following mixtures of \(\mathrm{COCl}_{2}, \mathrm{CO},\) and \(\mathrm{Cl}_{2}\) at \(100^{\circ} \mathrm{C}\) at equilibrium? If not, indicate the direction that the reaction must proceed to achieve equilibrium. (a) \(\left[\mathrm{COCl}_{2}\right]=[\mathrm{CO}]=1.00 \times 10^{-4} \mathrm{M},\left[\mathrm{Cl}_{2}\right]=7.2 \times 10^{-6} \mathrm{M}\) (b) \(\left[\mathrm{COCl}_{2}\right]=2.20 \times 10^{-2} \mathrm{M},[\mathrm{CO}]=2.2 \times 10^{-7} \mathrm{M}\) \(\left[\mathrm{Cl}_{2}\right]=3.0 \times 10^{-6} \mathrm{M}\) (c) \(\left[\mathrm{COCl}_{2}\right]=0.0100 \mathrm{M},[\mathrm{CO}]=\left[\mathrm{Cl}_{2}\right]=7.2 \times 10^{-6} \mathrm{M}\)
Step-by-Step Solution
VerifiedKey Concepts
Reaction Quotient
\[Q_c = \frac{[\text{CO}] \times [\text{Cl}_2]}{[\text{COCl}_2]}\]
It's important to note that \( Q_c \) can change as a reaction progresses, unlike \( K_c \) which is constant at a given temperature.
After calculating \( Q_c \), it is compared to \( K_c \), the equilibrium constant, to assess the system's state:
- If \( Q_c = K_c \), the system is at equilibrium.
- If \( Q_c > K_c \), there are more products compared to reactants than at equilibrium, so the reaction will shift towards the reactants to reach equilibrium.
- If \( Q_c < K_c \), the products are less than the equilibrium concentration, necessitating a shift towards product formation to attain equilibrium as in Mixture (b) from the example.
Equilibrium Constant
For the reaction \( \text{COCl}_2(g) \rightleftharpoons \text{CO}(g) + \text{Cl}_2(g) \), the equilibrium constant is expressed as:
\[K_c = \frac{[\text{CO}] \times [\text{Cl}_2]}{[\text{COCl}_2]}\]
The value of \( K_c \) is given for the reaction at \( 100^{\circ} \text{C} \) as \( 2.19 \times 10^{-10} \). This small value indicates that at equilibrium, the concentrations of reactants are favored over products, as there are fewer molecules of \( \text{CO} \) and \( \text{Cl}_2 \) relative to \( \text{COCl}_2 \).
On comparing the calculated \( Q_c \) values for the mixtures in the exercise with \( K_c \), one can determine in which direction the reaction needs to shift. This helps in predicting how the system reacts to changes in concentration, temperature, and pressure, as it strives for equilibrium.
Le Chatelier's Principle
In the context of the reaction \( \text{COCl}_2(g) \rightleftharpoons \text{CO}(g) + \text{Cl}_2(g) \), if the concentration of one of the components is changed, the system will strive to adjust the concentrations to offset that change, thereby moving towards a new equilibrium state.
- Addition of more \( \text{COCl}_2 \) will shift the reaction to the right (forming more products) to alleviate the stress.
- Conversely, adding more \( \text{CO} \) or \( \text{Cl}_2 \) will push the reaction to the left (forming more reactant) to decrease the product concentration.