Problem 43
Question
A block with mass 0.50 \(\mathrm{kg}\) is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 \(\mathrm{m}(\mathrm{Fig} .7 .31) .\) When released, the block moves on a horizontal tabletop for 1.00 \(\mathrm{m}\) before coming to rest. The spring constant \(k\) is 100 \(\mathrm{N} / \mathrm{m}\) . What is the coefficient of kinetic friction \(\mu_{k}\) between the block and the tabletop?
Step-by-Step Solution
Verified Answer
The coefficient of kinetic friction is approximately 0.408.
1Step 1: Calculate the Potential Energy Stored in the Spring
The potential energy stored in a compressed spring can be calculated using the formula \( U = \frac{1}{2} k x^2 \), where \( k \) is the spring constant, and \( x \) is the compression distance. Substituting the given values: \[ U = \frac{1}{2} \times 100 \, \text{N/m} \times (0.20 \, \text{m})^2 = 2 \, \text{J}. \] This is the energy stored in the spring.
2Step 2: Determine the Work Done by Friction
The work done by friction as the block moves 1.00 m and comes to rest is equivalent to the potential energy of the spring. Thus, \[ W_{friction} = 2 \, \text{J}. \] This work is given by \( W_{friction} = f_k \cdot d \), where \( f_k \) is the frictional force and \( d \) is the distance (1.00 m). Substituting: \[ f_k \cdot 1.00 \, \text{m} = 2 \, \text{J}. \] So, \( f_k = 2 \, \text{N}. \)
3Step 3: Relate Frictional Force to Normal Force and Coefficient of Friction
The frictional force \( f_k \) is also given by the equation \( f_k = \mu_k N \), where \( \mu_k \) is the coefficient of kinetic friction and \( N \) is the normal force. Since the block is moving on a horizontal table, \( N = mg \), where \( m = 0.50 \, \text{kg} \) and \( g = 9.8 \, \text{m/s}^2 \). Therefore, \[ N = 0.50 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 4.9 \, \text{N}. \]
4Step 4: Solve for the Coefficient of Kinetic Friction
Substituting \( f_k = 2 \, \text{N} \) and \( N = 4.9 \, \text{N} \) into the friction equation \( 2 \, \text{N} = \mu_k \times 4.9 \, \text{N} \), we solve for \( \mu_k \): \[ \mu_k = \frac{2 \, \text{N}}{4.9 \, \text{N}} \approx 0.408. \] So, the coefficient of kinetic friction is approximately \( 0.408 \).
Key Concepts
Spring Potential EnergyKinetic FrictionWork-Energy Principle
Spring Potential Energy
When a spring is compressed or stretched from its natural length, it stores energy. This energy is known as spring potential energy. Spring potential energy is a form of mechanical energy, and can be calculated using the formula \[ U = \frac{1}{2} k x^2 \]where:
- \( U \) is the potential energy in joules (J),
- \( k \) is the spring constant in newtons per meter (N/m),
- \( x \) is the compression or elongation in meters (m).
Kinetic Friction
Kinetic friction is the force that opposes the motion of two objects sliding past each other. It is crucial to understand that kinetic friction only acts once the objects are in motion, as opposed to static friction, which acts when objects are stationary. The frictional force can be calculated using:\[ f_k = \mu_k \cdot N \]where:
- \( f_k \) is the kinetic frictional force in newtons (N),
- \( \mu_k \) is the coefficient of kinetic friction (dimensionless),
- \( N \) is the normal force in newtons (N), equal to the gravitational force when on a horizontal plane.
Work-Energy Principle
The work-energy principle is a fundamental concept in physics. It states that the work done by the forces acting on an object results in a change in energy. Essentially, the principle links the work done on an object to its change in kinetic and potential energy.
In a situation where a block compresses a spring, as in our exercise, the work-energy principle underpins the transition from the stored spring potential energy to overcoming kinetic friction as the block moves.
When the block is released, the spring potential energy is converted into kinetic energy, propelling the block forward. As it slides across the table, kinetic friction gradually dissipates this energy, eventually bringing the block to a halt. This illustrates how the initial spring potential energy was used entirely to do the work against friction to stop the block.
Thus, understanding the work-energy principle helps us comprehend how energy transformation and work done in friction are related in physical systems.
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