Problem 43
Question
41–54 These problems involve combinations. Choosing a Group In how many ways can six people be chosen from a group of ten?
Step-by-Step Solution
Verified Answer
There are 210 ways to choose six people from ten.
1Step 1: Understand the Concept of Combination
In combinatorics, a combination refers to the selection of items from a larger collection, where the order of selection does not matter. The formula to calculate combinations is given by \( C(n, r) = \frac{n!}{r!(n-r)!} \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.
2Step 2: Assign Values to Variables
For this problem, we need to select \( r = 6 \) people from a larger group of \( n = 10 \) people. We will substitute these values into the combination formula to find the number of ways to choose the group.
3Step 3: Calculate Factorials
First, calculate the factorials required for the combination formula: - \( 10! = 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \) - \( 6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 \) - \( (10-6)! = 4! = 4 \times 3 \times 2 \times 1 \) .
4Step 4: Substitute and Solve
Now that we have the factorials, use the combination formula: \[ C(10, 6) = \frac{10!}{6! \times 4!} \] Calculate \( 10! = 3628800 \), \( 6! = 720 \), and \( 4! = 24 \). Thus, \[ C(10, 6) = \frac{3628800}{720 \times 24} = \frac{3628800}{17280} = 210 \].
5Step 5: Interpret the Result
The result of the combination calculation, 210, represents the number of different ways to choose 6 people from a group of 10, without regard to the order of selection.
Key Concepts
FactorialCombinatoricsChoosing Groups
Factorial
The concept of a factorial is fundamental to understanding combinations. A factorial, denoted by an exclamation mark (!), is the product of an integer and all the integers below it. For example, a factorial of 5, written as 5!, is calculated as:
- 5! = 5 × 4 × 3 × 2 × 1 = 120
Combinatorics
Combinatorics is a branch of mathematics focused on counting, arrangement, and combination of objects. It provides tools and methods to solve various problems related to the structure and counting of sets. One of the primary applications of combinatorics is in calculating combinations, where the order of items does not matter, but the selection itself is key.
- In a combination, the number of ways to choose \( r \) items from \( n \) items is given by the formula: \( C(n, r) = \frac{n!}{r! \times (n-r)!} \).
Choosing Groups
When faced with a task of choosing groups, it is essential to consider whether the order of selection matters. In the context of combinations, we are concerned with choosing elements without regard to order. This makes it different from permutations where order does play a role.
The given problem of selecting 6 people from a group of 10 is a classic example of a combination. Using the formula \( C(n, r) = \frac{n!}{r! \times (n-r)!} \), we assign \( n = 10 \) and \( r = 6 \) to find:
The given problem of selecting 6 people from a group of 10 is a classic example of a combination. Using the formula \( C(n, r) = \frac{n!}{r! \times (n-r)!} \), we assign \( n = 10 \) and \( r = 6 \) to find:
- \( C(10, 6) = \frac{10!}{6! \times (10-6)!} = \frac{10!}{6! \times 4!} \).
Other exercises in this chapter
Problem 42
Explain why in any group of 677 people, at least two people must have the same pair of initials.
View solution Problem 42
In the 6/49 lottery game a player selects six numbers from 1 to 49. What is the probability of selecting at least five of the six winning numbers?
View solution Problem 43
A jar contains six red marbles numbered 1 to 6 and ten blue marbles numbered 1 to 10. A marble is drawn at random from the jar. Find the probability that the gi
View solution Problem 44
41–54 These problems involve combinations. Committee In how many ways can a committee of three members be chosen from a club of 25 members?
View solution