Problem 43
Question
2-Methylpropane (containing traces of 2-methylpropene) is converted by a large excess of deuteriosulfuric acid \(\left(\mathrm{D}_{2} \mathrm{SO}_{4}\right)\) rather rapidly to 2 -methylpropane with only nine deuteriums. a. Write a polar mechanism for this hydrogen-exchange reaction that is in harmony with the known chemical properties of sulfuric acid and that predicts exchange of no more than nine of the ten hydrogens of 2 -methylpropane. b. Explain how 2-methylpropane-D \(_{9}\) can be formed more rapidly than 2 -methylpropane- \(\mathrm{D}_{n}\) with \(n<9\) in the early stages of the reaction.
Step-by-Step Solution
Verified Answer
The reaction exchanges nine hydrogens due to carbocation-mediated deuterium exchange, with rapid conversion in an excess of \( D_2SO_4 \).
1Step 1: Understanding Structure and Reactivity
2-Methylpropane (isobutane) has the formula \( C_4H_{10} \). The molecule contains 9 hydrogen atoms on the three methyl groups and 1 hydrogen on the central methine carbon. Traces of 2-methylpropene could enhance reactivity in the presence of acids due to the alkene's ability to form carbocations.
2Step 2: Polar Mechanism Initiation
In the presence of deuteriosulfuric acid \( \left( D_2SO_4 \right) \), sulfuric acid can donate a \( D^+ \) (deuteron) to form a carbocation \((CH_3)_3C^+ \) from 2-methylpropene. The carbocation is a highly reactive intermediate that can lead to hydrogen (or deuterium in this case) exchange.
3Step 3: Deuterium Exchange Process
The carbocation \((CH_3)_3C^+ \) formed interacts with the deuterated acid causing hydrogen atoms at the methyl groups to undergo sequential deuterium exchange involving reversible deuterium uptake and hydronium release by the repeated addition-elimination through the formation and stabilization of alkenes.
4Step 4: Limitation to Nine Deuteriums
Only the methyl hydrogens (9 in total) are involved in this exchange due to their position in the transition states and their ability to stabilize carbocations during deuterium exchange. The center carbon holding one hydrogen is sterically hindered and less reactive to interconversion during the reaction.
5Step 5: Kinetic Preference for Rapid Formation
Initially, in the presence of an excess of deuteriosulfuric acid, 2-methylpropane-D \(_9\) is formed more rapidly because the carbocation formation and subsequent deuterium exchange processes are fast and localized to the 9 exchangeable hydrogens. The rapid reaction in early stages ensures more hydrogens are replaced quickly, saturating the possible sites before other slower processes equilibrate.
Key Concepts
Hydrogen-Deuterium ExchangeCarbocation ReactionsSulfuric Acid ReactivityAlkane Reactivity
Hydrogen-Deuterium Exchange
Hydrogen-deuterium exchange is a fascinating reaction mechanism frequently observed in organic chemistry. It involves the replacement of hydrogen atoms in a molecule with their heavier isotope, deuterium. In the case of 2-methylpropane, deuteriosulfuric acid \( (D_2SO_4) \) provides a source of deuterons \( (D^+) \) that replace the hydrogen atoms.
- The key step involves the formation of a reactive intermediate known as a carbocation.
- This is initiated when a deuteron is added to form a transient carbocation, facilitating subsequent deuterium incorporation.
Carbocation Reactions
Carbocations are positively charged carbon species that play a central role in many organic reactions, especially in hydrogen-deuterium exchange. When a molecule like 2-methylpropene forms a carbocation through the action of an acid, it becomes highly reactive. This process:
- Occurs when the double bond of the alkene donates electrons to the incoming deuterium, forming the carbocation.
- Sets up the molecule for a sequence of transformations where hydrogen atoms can be swapped with deuterium.
Sulfuric Acid Reactivity
Sulfuric acid, especially in its deuterated form \((D_2SO_4)\), is a potent acid used in facilitating the hydrogen-deuterium exchange reaction. Its role in the reaction is multifaceted:
- It acts as a source of \(D^+\) ions, or deuterons, that are necessary for initiating exchange.
- It helps stabilize carbocations formed during the reaction by its ability to donate deuterons and subsequently partake in protonation-deprotonation cycles.
Alkane Reactivity
Understanding alkane reactivity, as seen in 2-methylpropane, helps clarify why only specific hydrogens are exchanged in a hydrogen-deuterium exchange. Alkanes are typically quite stable, lacking a functional group that participates easily in reactions under normal conditions. However, when an acid such as deuteriosulfuric acid is introduced:
- The normally unreactive alkane (2-methylpropane) becomes susceptible to deuterium exchange at its more reactive sites, such as the methyl group hydrogens.
- The selective reactivity is influenced by the molecule's ability to form and stabilize a carbocation, which is crucial for the exchange to take place.
Other exercises in this chapter
Problem 37
Why is molecular fluorine generally unsatisfactory as a reagent to convert alkenes to 1,2-difluoroalkanes?
View solution Problem 38
Why does the addition of chlorine to 2-pentene in methanol give a mixture of the following products? 2,3-dichloropentane \((16 \%)\) 2-chloro-3-methoxypentane \
View solution Problem 31
It has been reported that a mixture of 2 -methylpropane-2-D, and 2 -methylpropane- \(1-{ }^{13} \mathrm{C}\), \(\left({ }^{13} \mathrm{C}\right.\) is the stable
View solution