Problem 424
Question
For the following exercises, Fourier's law of heat transfer states that the heat flow vector \(\mathbf{F}\) at a point is proportional to the negative gradient of the temperature; that is, \(\mathbf{F}=-k \nabla T,\) which means that heat energy flows hot regions to cold regions. The constant \(k>0\) is called the conductivity, which has metric units of joules per meter per second-kelvin or watts per meter-kelvin. A temperature function for region \(D\) is given. Use the divergence theorem to find net outward heat \(\quad\) flux \(\iint_{S} \mathbf{F} \cdot \mathbf{N} d S=-k \iint_{S} \nabla T \cdot \mathbf{N} d S\) across the boundary \(S\) of \(D,\) where \(k=1\). \(T(x, y, z)=100+x+2 y+z ;\) \(D=\mid(x, y, z): 0 \leq x \leq 1,0 \leq y \leq 1,0 \leq z \leq 1\\}\)
Step-by-Step Solution
VerifiedKey Concepts
Gradient of Temperature
For the example function \( T(x, y, z) = 100 + x + 2y + z \), this involves finding the derivatives with respect to \( x \), \( y \), and \( z \). The resulting gradient is \( abla T = (1, 2, 1) \), indicating how the temperature changes in the region along these axes.
- The gradient tells us that the temperature increases at a rate of 1 unit per meter when moving along the x-axis,
- 2 units per meter along the y-axis,
- and 1 unit per meter along the z-axis.
Divergence Theorem
In this context, the theorem is used to calculate heat flux across the boundary \( S \) of any given region \( D \). By considering the divergence of the heat flow vector, \( abla \cdot \mathbf{F} \), we learn about the circulation of heat within the region. For the given exercise, since the divergence is \( 0 \), the heat is evenly balanced inside the region, with no net production or loss internal to \( D \).
The practical use of the divergence theorem allows us to avoid directly computing complex surface integrals, simplifying the problem to a volume integral, which can often be more straightforward to solve.
Heat Flux Calculation
In the problem, Fourier's Law gives us \( \mathbf{F} = -k abla T \). Here, since \( k = 1 \), we found \( \mathbf{F} = (-1, -2, -1) \), indicating the direction and rate at which heat travels.
The net heat flux problem then asks us to understand this vector field's behavior across a closed surface \( S \). With the divergence theorem applied, showing \( abla \cdot \mathbf{F} = 0 \), the net outward heat flux through \( S \) turns out to be zero. Thus, within region \( D \), there is no net gain or loss in heat, leading to temperature stability across the boundary.