Problem 42
Question
Write the indicated tem of each binomial expansion. Twelfth term of \(\left(2 x+y^{2}\right)^{16}\)
Step-by-Step Solution
Verified Answer
The 12th term is \(139776x^5 y^{22}\).
1Step 1: Understand Binomial Theorem
The binomial theorem is used to expand expressions of the form \((a+b)^n\). According to the theorem, \((a+b)^n\) can be expanded as \( \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \).
2Step 2: Identify the Parameters
In the expression \((2x + y^2)^{16}\), identify \(a = 2x\), \(b = y^2\), and \(n = 16\). We are looking for the 12th term.
3Step 3: Determine the Term Number
For finding the 12th term in the expansion, recall that the (k+1)-th term from a binomial expansion \((a+b)^n\) is given by \(\binom{n}{k} a^{n-k} b^k\). Thus, for the 12th term, set \(k+1 = 12\), which gives \(k = 11\).
4Step 4: Apply Binomial Formula for the 12th Term
Using \(k=11\), the term can be calculated as: \[ \binom{16}{11} (2x)^{16-11} (y^2)^{11} \].
5Step 5: Calculate the Coefficient and simplify
Compute the binomial coefficient \( \binom{16}{11} = 4368 \). Then calculate \((2x)^5 = 32x^5\) and \((y^2)^{11} = y^{22}\). Multiply these terms to get: \[ 4368 \times 32x^5 \times y^{22} = 139776x^5 y^{22} \].
Key Concepts
Binomial ExpansionBinomial CoefficientAlgebraic Expressions
Binomial Expansion
A binomial expansion is a method for expressing the power of a binomial as a sum. This concept stems from the Binomial Theorem, which states that any expression in the form \((a + b)^n\) can be expanded into a sum involving terms of the form \(a^{n-k}b^k\). Each term in the expansion has a binomial coefficient, denoted as \(\binom{n}{k}\).
- The Binomial Theorem allows us to find any term in the expansion of a binomial expression without having to multiply the expression repeatedly.
- This theorem is particularly useful for large values of \(n\), as it provides a formulaic approach to expansion.
Binomial Coefficient
The binomial coefficient plays a crucial role in binomial expansions. It is represented by the symbol \(\binom{n}{k}\), which is read as "n choose k." This coefficient determines the number of ways to choose \(k\) items from \(n\) items without regard to order.
- To compute \(\binom{n}{k}\), use the formula: \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\).
- For instance, in the expression \(\left(2x + y^2\right)^{16}\), if we need the 12th term, we calculate \(\binom{16}{11}\), resulting in 4368.
Algebraic Expressions
Algebraic expressions are mathematical phrases involving numbers, variables, and operations. They play an integral role in various branches of mathematics and serve as the foundation for algebra.
- In the context of the binomial theorem, algebraic expressions like \((2x + y^2)\) are raised to powers, significantly increasing their complexity.
- Breaking down such expressions into expanded forms simplifies operations and provides insights into their structure.
Other exercises in this chapter
Problem 42
Find the sum of the first 10 terms of each arithmetic sequence. $$8,6,4, \dots$$
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Use the fundamental principle of counting or permutations to solve each problem. How many 7-digit telephone numbers are possible if the first digit cannot be 0
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Use a formula to find the sum of each series. $$\sum_{j=1}^{3}-3\left(\frac{1}{4}\right)^{j}$$
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Find the sum for each series. $$\sum_{i=-1}^{2} 5(2)^{i}$$
View solution