Problem 42
Question
Write logarithm as a difference. Then simplify, if possible. \(\log _{8} \frac{y}{8}\)
Step-by-Step Solution
Verified Answer
\(\log_8 y - 1\)
1Step 1: Apply the Quotient Rule of Logarithms
The quotient rule of logarithms states that \( \log_b \left( \frac{M}{N} \right) = \log_b M - \log_b N \). Here, we apply this to our problem: \( \log_8 \frac{y}{8} = \log_8 y - \log_8 8 \).
2Step 2: Simplify the Expression
We know that \( \log_8 8 = 1 \) because the logarithm of any number to its own base is 1. Thus, substitute \( \log_8 8 \) with 1 in the expression. The simplified expression becomes \( \log_8 y - 1 \).
Key Concepts
Quotient Rule of LogarithmsSimplifying Logarithmic ExpressionsBase of Logarithm
Quotient Rule of Logarithms
The Quotient Rule of Logarithms is a vital tool in simplifying logarithmic expressions, especially those involving division. According to this rule, when you have a logarithm of a quotient, it can be expressed as the difference between two separate logarithms. This means that for a base \( b \), the expression \( \log_b \left( \frac{M}{N} \right) \) can be rewritten as \( \log_b M - \log_b N \). This rule is derived from the properties of exponents since logarithms are essentially a reverse function of exponents. By separating the expression into two parts, we can handle them individually, which often makes calculations easier and more straightforward.
For example, in the exercise given, \( \log_8 \frac{y}{8} \) becomes \( \log_8 y - \log_8 8 \). This application of the quotient rule helps us move towards a simpler form of the expression, preparing it for further simplification.
For example, in the exercise given, \( \log_8 \frac{y}{8} \) becomes \( \log_8 y - \log_8 8 \). This application of the quotient rule helps us move towards a simpler form of the expression, preparing it for further simplification.
Simplifying Logarithmic Expressions
Simplifying logarithmic expressions involves reducing them to their simplest form, making them easier to interpret and work with. After applying rules like the quotient rule, the resulting expression can often be simplified further.
In the example with \( \log_8 y - \log_8 8 \), we recognize that \( \log_8 8 \) is equal to 1. Why is that? Because when the base of the logarithm is the same as the number, the result is always 1.
Thus, we substitute \( \log_8 8 \) with 1, leading to a further simplified expression: \( \log_8 y - 1 \). Simplification enhances clarity and makes it easier to deal with the expression, whether for solving equations or other applications.
In the example with \( \log_8 y - \log_8 8 \), we recognize that \( \log_8 8 \) is equal to 1. Why is that? Because when the base of the logarithm is the same as the number, the result is always 1.
- This is because the logarithm answers the question: to what power must the base be raised, to result in that number? Since \( 8^1 = 8 \), \( \log_8 8 = 1 \).
Thus, we substitute \( \log_8 8 \) with 1, leading to a further simplified expression: \( \log_8 y - 1 \). Simplification enhances clarity and makes it easier to deal with the expression, whether for solving equations or other applications.
Base of Logarithm
Understanding the base of a logarithm is crucial in manipulating logarithmic expressions. The base represents the number that we repeatedly multiply to reach another number, which is the argument of the logarithm. In mathematical terms, if \( b^x = N \), then \( x = \log_b N \). The base \( b \) is a pivotal part of the logarithm as it determines how the logarithm is calculated and how it can be simplified or expanded.
In our example, the base is 8, denoting that all logarithmic calculations in this expression consider powers of 8. When simplifying logarithmic expressions, familiarity with the base allows us to make logical deductions, such as realizing \( \log_b b = 1 \) for any base \( b \). Being mindful of the base helps in accurately applying logarithmic rules and transforms the expression into its simplest form. Remember, the base also guides how effectively we can interpret or convert between different logarithmic forms. It's as if the base sets the rules of the game, guiding each step of transformation or simplification.
In our example, the base is 8, denoting that all logarithmic calculations in this expression consider powers of 8. When simplifying logarithmic expressions, familiarity with the base allows us to make logical deductions, such as realizing \( \log_b b = 1 \) for any base \( b \). Being mindful of the base helps in accurately applying logarithmic rules and transforms the expression into its simplest form. Remember, the base also guides how effectively we can interpret or convert between different logarithmic forms. It's as if the base sets the rules of the game, guiding each step of transformation or simplification.
Other exercises in this chapter
Problem 42
Evaluate each expression without using a calculator. $$ \ln e^{2} $$
View solution Problem 42
Each of the following functions is one-to-one. Find the inverse of each function and express it using \(f^{-1}(x)\) notation. \(f(x)=\frac{3}{x+1}\)
View solution Problem 43
Solve each equation. See Example \(6 .\) $$ \log _{3}(x-3)=2 $$
View solution Problem 43
Let \(f(x)=2 x+1\) and \(g(x)=x^{2}-1 .\) Find each of the following. $$ (g \circ f)(2 x) $$
View solution