Problem 42
Question
Write each of the following in terms of \(i\) and simplify. $$ 9 \sqrt{-40} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(18\sqrt{10}i\).
1Step 1: Identify the Expression Type
The expression given is \(9 \sqrt{-40}\), which involves a square root of a negative number. Recall that the imaginary unit \(i\) is defined as \(\sqrt{-1}\). This will help us rewrite the square root of the negative number in terms of \(i\).
2Step 2: Rewrite the Square Root
Start by rewriting \(\sqrt{-40}\) as \(\sqrt{40} \times \sqrt{-1}\). This uses the property that \(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\) when both \(a\) and \(b\) are non-negative. This gives us \(\sqrt{40} \times i\).
3Step 3: Simplify the Radical
Next, simplify \(\sqrt{40}\). Note that \(40 = 4 \times 10\), where \(4\) is a perfect square. So, \(\sqrt{40} = \sqrt{4 \times 10} = \sqrt{4} \times \sqrt{10} = 2\sqrt{10}\).
4Step 4: Substitute Back and Simplify
Now substitute \(\sqrt{40} = 2\sqrt{10}\) back into the expression from Step 2. We have \(\sqrt{-40} = 2\sqrt{10} \times i\). Multiply this result by 9 as given in the problem: \(9 \times 2\sqrt{10} \times i = 18\sqrt{10}i\).
5Step 5: State the Final Simplified Expression
The fully simplified expression in terms of \(i\) is \(18\sqrt{10}i\). Therefore, \(9\sqrt{-40} = 18\sqrt{10}i\).
Key Concepts
Imaginary UnitSimplifying RadicalsMultiplication of Imaginary Numbers
Imaginary Unit
Numbers can sometimes be difficult to work with, especially when they involve taking the square root of a negative number. In this context, the imaginary unit "i" is a helpful tool. By definition, the imaginary unit is represented as\(i = \sqrt{-1}\). This allows us to work with numbers that we couldn't otherwise. For example, the square root of \(-4\) can be expressed as \(2i\), because \(-4 = 4 \times (-1)\). Anytime you have the square root of a negative number, you can express it using "i". This concept is fundamental in simplifying complex numbers, allowing you to transform otherwise challenging calculations into more manageable ones.By using the imaginary unit, you open up a world of mathematical possibilities. Complex numbers, which include real and imaginary parts, are extensively used in fields such as engineering, physics, and computer science.
Simplifying Radicals
Simplifying radicals, particularly when working with complex numbers, involves reducing expressions to their simplest form. Radicals refer to expressions that contain a square root, cube root, or other root symbols. To simplify, identify factors within the radicand, which is the number inside the root symbol.For example, if you have \(\sqrt{40}\), break it down into the product of its factors: \(\sqrt{4 \times 10}\). Since \(4\) is a perfect square, it can be simplified. Thus, \(\sqrt{4} \times \sqrt{10} = 2\sqrt{10}\). This process of breaking down the radicand into manageable parts and simplifying them is crucial. Some helpful tips include:
- Look for perfect square factors in the radicand, as these can be simplified easily.
- Rewrite the radicand as a product of simpler numbers if possible.
Multiplication of Imaginary Numbers
Multiplying imaginary numbers involves combining the values of the terms and simplifying the expression accordingly. When you multiply two imaginary numbers or expressions involving "i", apply normal arithmetic rules but remember that \(i^2 = -1\).Let's consider the multiplication of \(9\sqrt{-40} \). By rewriting the term, we have \(9 \times 2\sqrt{10} \times i \), resulting from the simplified form as we previously mentioned. Calculate it step-by-step:
- Multiply the coefficients: \(9 \times 2 = 18\).
- Combine the terms with the radical: \(18\sqrt{10}\).
- Do not forget the \(i\): \(18\sqrt{10}i\).
Other exercises in this chapter
Problem 42
Set up an equation and solve each problem. Find two consecutive odd whole numbers such that the sum of their squares is 74 .
View solution Problem 42
Solve each quadratic equation using the method that seems most appropriate. $$ 3 x^{2}+6 x=1 $$
View solution Problem 43
Solve each inequality. $$ \frac{2 x-1}{x} \geq 0 $$
View solution Problem 43
Set up an equation and solve each problem. Two positive integers differ by 3 , and their product is 108. Find the numbers.
View solution