Problem 42
Question
Which expression can be simplified to \(\frac{x-1}{x-3} ?\) $$ \begin{array}{ll}{\text { A. } \frac{x^{2}-x-6}{x^{2}-x-2}} & {\text { B. } \frac{x^{2}-2 x+1}{x^{2}+2 x-3}} \\ {\text { C. } \frac{x^{2}-3 x-4}{x^{2}-7 x+12}} & {\text { D. } \frac{x^{2}-4 x+3}{x^{2}-6 x+9}}\end{array} $$
Step-by-Step Solution
Verified Answer
Expression C: \(\frac{x^{2}-3 x-4}{x^{2}-7 x+12}\) simplifies to \(\frac{x-1}{x-3}\). So, the correct answer is C.
1Step 1: Simplify the expression A.
Rewrite the given expression by factoring the polynomials. On simplifying \(\frac{x^{2}-x-6}{x^{2}-x-2}\), we get \(\frac{(x-3)(x+2)}{(x-2)(x+1)}\). The simplified form doesn't match \(\frac{x-1}{x-3}\), so it's not the answer.
2Step 2: Simplify the expression B.
Now, simplify \(\frac{x^{2}-2 x+1}{x^{2}+2 x-3}\). It simplifies to \(\frac{(x-1)^{2}}{(x+1)(x-3)}\). It doesn't simplify to \(\frac{x-1}{x-3}\), so this also doesn't give the correct answer.
3Step 3: Simplify the expression C.
Now, let's simplify \(\frac{x^{2}-3 x-4}{x^{2}-7 x+12}\). This simplifies to \(\frac{(x-4)(x+1)}{(x-3)(x-4)}\). By cancelling out (x-4) from both the numerator and the denominator, we get \(\frac{x-1}{x-3}\). This matches perfectly with our required expression.
4Step 4: Verification with expression D.
Though we've found our answer, for completeness, let's simplify expression D as well. Simplifying \(\frac{x^{2}-4 x+3}{x^{2}-6 x+9}\) gives us \(\frac{(x-1)(x-3)}{(x-3)^{2}}\). Hence, this is not equal to \(\frac{x-1}{x-3}\).
Key Concepts
Factoring PolynomialsSimplificationAlgebraic Fractions
Factoring Polynomials
Factoring polynomials is an essential skill in algebra, especially when working with rational expressions. A polynomial can be factored by finding its roots or zeros, essentially breaking it down into the product of its simpler polynomials. For instance, consider the quadratic polynomial format \(ax^2 + bx + c\). Depending on the values of \(a, b,\) and \(c\), it can usually be factored into two binomials of the form \((px + q)(rx + s)\).
Here's a basic approach to start factoring:
Here's a basic approach to start factoring:
- Look for the greatest common factor (GCF) across all terms; factor it out if possible.
- For quadratic polynomials, check if they can be expressed in the form \((x + m)(x + n)\) where \(m\) and \(n\) are numbers that add to \(b\) and multiply to \(c\).
- Use special patterns, such as the difference of squares: \(a^2 - b^2 = (a + b)(a - b)\).
Simplification
Simplification in algebra typically involves reducing expressions to their simplest form while maintaining equivalence with the original expression. When working with rational expressions, which are fractions where both the numerator and denominator are polynomials, we aim to cancel out common factors.
Consider a common process:
Consider a common process:
- Factor both the numerator and the denominator, as seen in our example where \(x^2 - 3x - 4\) becomes \((x-4)(x+1)\).
- Identify and cancel any matching factors present in both the numerator and the denominator. In the exercise solution, the factor \(x-4\) is present in both parts and therefore gets canceled, leaving us with the simplified expression \(\frac{x-1}{x-3}\).
Algebraic Fractions
Algebraic fractions involve expressions with polynomials in their numerators, denominators, or both. Simplifying these requires skills in both factoring and the laws of fractions. Recognizing these expressions' characteristics can make the task far less daunting.
Key points to note when working with algebraic fractions:
Key points to note when working with algebraic fractions:
- Always begin by factoring. The goal is to identify factors in both the numerator and the denominator that can be canceled.
- Ensure the denominator is never zero. An expression is undefined when its denominator equals zero.
- The principles of fractions still hold. For example, when dividing fractions, you "invert and multiply." When adding or subtracting, ensure like terms (common denominators) are used.
Other exercises in this chapter
Problem 41
Graph each pair of functions. Find the approximate point(s) of intersection. \(y=\frac{6}{x-2}, y=6\)
View solution Problem 41
Each pair of values is from a direct variation. Find the missing value. $$ (8.3,7.1),(5, y) $$
View solution Problem 42
Solve each equation. Check each solution. $$ c-\frac{c}{3}+\frac{c}{5}=26 $$
View solution Problem 42
Explain how factoring is used when adding or subtracting rational expressions. Include an example in your explanation.
View solution