Problem 42
Question
Verify the identity. $$ (\sin x+\cos x)^{4}=(1+2 \sin x \cos x)^{2} $$
Step-by-Step Solution
Verified Answer
Both sides are equivalent; the identity is verified.
1Step 1: Expand the Left Side
First, expand the expression \((\sin x + \cos x)^4\). Start by recognizing it as \((a+b)^4\), where \(a = \sin x\) and \(b = \cos x\). The expansion of \((a+b)^4\) using the binomial theorem is \(a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4\). Substitute back \(a\) and \(b\):\[(\sin x)^4 + 4(\sin x)^3(\cos x) + 6(\sin x)^2(\cos x)^2 + 4(\sin x)(\cos x)^3 + (\cos x)^4.\]
2Step 2: Simplify Each Term
Now, simplify each term in the expanded expression:- \((\sin x)^4 + (\cos x)^4\) remains unchanged.- The term \(6(\sin x)^2(\cos x)^2\) can be rewritten as \(6 \sin^2 x \cos^2 x\).- The terms \(4(\sin x)^3(\cos x)\) and \(4(\sin x)(\cos x)^3\) combined give \(4 \sin x \cos x (\sin^2 x + \cos^2 x)\). Since \(\sin^2 x + \cos^2 x = 1\), this simplifies to \(4 \sin x \cos x\).
3Step 3: Expand the Right Side
Now, expand the expression \((1 + 2 \sin x \cos x)^2\) using the formula for squaring a binomial:\(a^2 + 2ab + b^2\), where \(a=1\) and \(b=2\sin x\cos x\). This yields: \[1 + 4 \sin x \cos x + 4 (\sin x \cos x)^2.\] Simplifying, the last term becomes \(4 \sin^2 x \cos^2 x\).
4Step 4: Compare Both Sides
Compare the expressions obtained in Step 2 and Step 3:- From Step 2, we have \((\sin x)^4 + 4 \sin x \cos x + 6 \sin^2 x \cos^2 x + (\cos x)^4\).- From Step 3, the simplified form is \(1 + 4 \sin x \cos x + 4 \sin^2 x \cos^2 x\).Recognize that \((\sin x)^4 + (\cos x)^4 + 2(\sin^2 x \cos^2 x) = 1\), which is a trigonometric identity. Thus, both sides are equivalent.
Key Concepts
Binomial TheoremTrigonometric FunctionsExpansion and Simplification
Binomial Theorem
The Binomial Theorem is a powerful tool in algebra used to expand expressions raised to a power, such as \((a + b)^n\). This theorem provides a way to write these expressions as a sum of individual terms, each consisting of a specific combination of the elements involved. In this exercise, the left side of the equation \((\sin x + \cos x)^4\) is the focus.We identify it as \((a + b)^4\) with the components \(a = \sin x\) and \(b = \cos x\). According to the Binomial Theorem, \((a+b)^4\) can be expanded as:
- \(a^4\)
- \(4a^3b\)
- \(6a^2b^2\)
- \(4ab^3\)
- \(b^4\)
Trigonometric Functions
Trigonometric functions like sine and cosine are fundamental in math and describe relationships in angles and circles. In this identity verification, we encounter functions \[(\sin x)^4\] and \[(\cos x)^4\].Trigonometric identities, such as \(\sin^2 x + \cos^2 x = 1\), help us simplify expressions and verify identities. This specific identity underpins each simplification step and enables us to express certain terms more simply. For example, in our exercise, it allows the reduction of \[4\sin x \cos x(\sin^2 x + \cos^2 x)\] to just \[4\sin x \cos x\].These functions are not only crucial for calculating angles and side lengths in geometry but also play a vital role in transforming and solving algebraic equations, as illustrated here. Understanding how to manipulate these functions and their identities is essential for problem-solving.
Expansion and Simplification
The process of expansion and simplification bridges complex equations to more understandable forms. Our exercise demands this approach for both sides of the equation to verify equivalence.Starting with the expansion, we systematically break down complex expressions:
- For \((\sin x + \cos x)^4\), apply the Binomial Theorem to achieve a polynomial involving different powers of \(\sin x\) and \(\cos x\).
- On the other side, \((1 + 2\sin x \cos x)^2\) uses the basic formula for squaring a binomial: \(a^2 + 2ab + b^2\).
- \((\sin x)^4 + (\cos x)^4\) becomes part of a known identity involving \(\sin x\) and \(\cos x\).
- Terms like \(6\sin^2 x \cos^2 x\) align with expanded and simplified forms on both sides.
Other exercises in this chapter
Problem 42
\(37-42\) Find \(\sin \frac{x}{2}, \cos \frac{x}{2},\) and \(\tan \frac{x}{2}\) from the given information. $$ \cot x=5, \quad 180^{\circ}
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\(39-56 \approx\) Solve the given equation. $$ 2 \sin ^{2} \theta-\sin \theta-1=0 $$
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\(43-52\) a Use a Double- or Half-Angle Formula to solve the equation in the interval \([0,2 \pi) .\) \(\sin 2 \theta+\cos \theta=0\)
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\(43-46\). Write the given expression as an algebraic expression in \(x\). $$ \sin \left(2 \tan ^{-1} x\right) $$
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