Problem 42
Question
Use Kepler's third law to calculate the orbital periods of two hypothetical planets that are 1.2 and \(2.5 \mathrm{AU}\), respectively, from the Sun.
Step-by-Step Solution
Verified Answer
Planet 1 has an orbital period of 1.315 years, and Planet 2 has an orbital period of 3.952 years.
1Step 1: Understand Kepler's Third Law
Kepler's third law states that the square of the orbital period \(T\) of a planet is directly proportional to the cube of the semi-major axis of its orbit \(a\). This means \(T^2 \propto a^3\). For planets orbiting the Sun, \(a\) is measured in astronomical units (AU) and \(T\) in Earth years.
2Step 2: Set Up the Equation
According to Kepler's third law, we use the simplified equation for planets around the Sun: \(T^2 = a^3\). This allows us to solve directly for \(T\) by taking the square root: \(T = \sqrt{a^3}\).
3Step 3: Calculate the Orbital Period for Planet 1
For a planet at a distance of \(1.2\) AU from the Sun, apply the formula: \(T_1 = \sqrt{(1.2)^3}\). Calculate \((1.2)^3 = 1.728\). Then take the square root: \(T_1 = \sqrt{1.728} \approx 1.315\text{ years}\).
4Step 4: Calculate the Orbital Period for Planet 2
For a planet at a distance of \(2.5\) AU from the Sun, apply the same formula: \(T_2 = \sqrt{(2.5)^3}\). Calculate \((2.5)^3 = 15.625\). Then take the square root: \(T_2 = \sqrt{15.625} \approx 3.952\text{ years}\).
5Step 5: Conclusion
We have calculated the orbital periods for the two planets using their distances in AU. Planet 1, at \(1.2\) AU, orbits in approximately \(1.315\) years. Planet 2, at \(2.5\) AU, orbits in approximately \(3.952\) years.
Key Concepts
Orbital Period CalculationSemi-Major AxisAstronomical Units (AU)Orbital Mechanics
Orbital Period Calculation
In astronomy, the orbital period is the time a celestial body takes to complete one full orbit around another object, like a planet orbiting the Sun. Calculating this period is essential to understand the dynamics of the solar system and the movement of planets. Kepler's Third Law provides a straightforward way to find the orbital period if we know the semi-major axis of the orbit. According to this law, for planets or celestial bodies orbiting the Sun, the square of the orbital period \(T\) is proportional to the cube of the semi-major axis \(a\). The relationship is formulated as:
- \(T^2 = a^3\)
Semi-Major Axis
The semi-major axis is a critical component in the structure of an orbit. An orbit is typically elliptical, with one focus at the center of mass of the system. The semi-major axis is half of the longest diameter of this ellipse, extending from the center to the edge along the longest line possible within it. Measuring the semi-major axis helps in understanding the scale of the orbit. For planets orbiting the Sun, the distance of this axis is conveniently measured in astronomical units (AU):
- One AU is nearly equal to the average distance from the Earth to the Sun, approximately 149.6 million kilometers.
Astronomical Units (AU)
Astronomical units (AU) are a standardized way to express distances within our solar system. It represents the average distance from the Earth to the Sun, about 93 million miles or 149.6 million kilometers. Using AU makes it easier to compare and understand distances between celestial objects without resorting to vast numbers:
- This unit simplifies working with astronomical equations, such as those from Kepler’s laws.
- Since Earth is 1 AU from the Sun, a planet at 1.2 AU means it is 20% farther from the Sun than Earth.
- Likewise, a planet 2.5 AU from the Sun is 2.5 times farther than the Earth from the Sun.
Orbital Mechanics
Orbital mechanics is the branch of physics and astronomy that examines the motions of objects in space under the influence of gravity. It involves applying Newton's law of universal gravitation alongside mathematician Johannes Kepler’s empirical laws of planetary motion. In orbit mechanics, Kepler's Laws are particularly influential:
- Kepler's First Law states that the path of each planet around the Sun is an ellipse, with the Sun as one of the focal points.
- Kepler’s Second Law, or the law of areas, reveals that a line segment joining a planet and the Sun sweeps out equal areas during equal time intervals, implying a variable speed depending on proximity to the Sun.
- Kepler’s Third Law allows us to understand the relationship between the distance of the planets from the Sun (semi-major axis) and their orbital periods.
Other exercises in this chapter
Problem 36
How many times greater would Venus's escape velocity be if it had the radius it does but mass equal to Earth's?
View solution Problem 37
Calculate the escape velocity, in kilometers per second, for a planet with mass equal to Mars's and radius equal to Mercury's.
View solution Problem 44
Find the stable temperature of an airless world with albedo 0.220 orbiting \(7.8 \times 10^{11}\) meters from a star with radius of \(1.7 \times 10^{9}\) meters
View solution Problem 45
A planet with no atmosphere and an albedo of 0.550 orbits a star with temperature of \(8,700 \mathrm{K}\) and radius of \(4.5 \times 10^{10}\) meters. The plane
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