Problem 42
Question
Use a rotation matrix to rotate the vector \(\left[\begin{array}{r}4 \\\ -1\end{array}\right]\) counterclockwise by the angle \(\pi / 3\).
Step-by-Step Solution
Verified Answer
The rotated vector is approximately \( \begin{bmatrix} 2.866 \\ 2.964 \end{bmatrix} \).
1Step 1: Understand the Rotation Matrix
A rotation matrix for rotating a vector in 2D space counterclockwise by an angle \( \theta \) is given by:\[R(\theta) = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \ \sin(\theta) & \cos(\theta) \end{bmatrix}\]For our problem, \( \theta = \pi/3 \).
2Step 2: Calculate the Values of Trigonometric Functions
For \( \theta = \pi/3 \), we calculate \( \cos(\pi/3) \) and \( \sin(\pi/3) \):\[\cos(\pi/3) = \frac{1}{2}, \quad \sin(\pi/3) = \frac{\sqrt{3}}{2}\]These values will be used to construct the rotation matrix.
3Step 3: Construct the Rotation Matrix
Substitute \( \cos(\pi/3) \) and \( \sin(\pi/3) \) into the rotation matrix:\[R(\pi/3) = \begin{bmatrix} \frac{1}{2} & -\frac{\sqrt{3}}{2} \ \frac{\sqrt{3}}{2} & \frac{1}{2} \end{bmatrix}\]This matrix will rotate any 2D vector by \( \pi/3 \) radians.
4Step 4: Multiply the Rotation Matrix by the Vector
Multiply the rotation matrix \( R(\pi/3) \) by the vector \( \begin{bmatrix} 4 \ -1 \end{bmatrix} \):\[\begin{bmatrix} \frac{1}{2} & -\frac{\sqrt{3}}{2} \ \frac{\sqrt{3}}{2} & \frac{1}{2} \end{bmatrix} \begin{bmatrix} 4 \ -1 \end{bmatrix} = \begin{bmatrix} \frac{1}{2} \times 4 + \left(-\frac{\sqrt{3}}{2}\right) \times (-1) \ \frac{\sqrt{3}}{2} \times 4 + \frac{1}{2} \times (-1) \end{bmatrix}\]Calculate the result for both entries.
5Step 5: Perform the Matrix Multiplication
Compute each element of the resulting vector:\[\begin{align*}x' &= \frac{1}{2} \times 4 + (-\frac{\sqrt{3}}{2}) \times (-1) = 2 + \frac{\sqrt{3}}{2} = 2 + 0.866 \approx 2.866,\y' &= \frac{\sqrt{3}}{2} \times 4 + \frac{1}{2} \times (-1) = 2\sqrt{3} - \frac{1}{2} = 3.464 - 0.5 \approx 2.964.\end{align*}\]So, the rotated vector is \( \begin{bmatrix} 2.866 \ 2.964 \end{bmatrix} \).
Key Concepts
Trigonometric FunctionsVector Rotation2D Vectors
Trigonometric Functions
Trigonometric functions play a crucial role in understanding rotations in mathematics, especially when dealing with vectors. They help us describe how angles and distances relate on a unit circle. When rotating vectors, the two primary trigonometric functions we use are cosine and sine. These functions provide the components needed to create a rotation matrix.
- Cosine Function: In a right triangle, the cosine of an angle \( \theta \) is the ratio of the length of the adjacent side to the hypotenuse. Cosine values range from -1 to 1 and are periodic with period \( 2\pi \).
- Sine Function: Similarly, the sine of an angle \( \theta \) is the ratio of the length of the opposite side to the hypotenuse. Sine values also range from -1 to 1, having the same periodic nature as cosine.
Vector Rotation
Vector rotation is a method of altering the direction of a vector while maintaining its magnitude. In 2D, this process uses the rotation matrix. This matrix acts like a tool to pivot vectors around the origin, depending on the specified angle, noted as \( \theta \).
The 2D rotation matrix for counterclockwise rotation is given by:
The 2D rotation matrix for counterclockwise rotation is given by:
- \( \begin{bmatrix} \cos(\theta) & -\sin(\theta) \ \sin(\theta) & \cos(\theta) \end{bmatrix} \)
- \( \begin{bmatrix} \frac{1}{2} & -\frac{\sqrt{3}}{2} \ \frac{\sqrt{3}}{2} & \frac{1}{2} \end{bmatrix} \)
2D Vectors
2D vectors are fundamental elements in mathematics and physics, representing quantities with both magnitude and direction in a two-dimensional plane. Understanding vectors is essential for numerous practical applications, like physics simulations and computer graphics.
A 2D vector can be denoted in the form \( \begin{bmatrix} x \ y \end{bmatrix} \), where \( x \) and \( y \) are the components along the horizontal and vertical axes respectively.
When it comes to rotation, applying mathematical operations like matrix multiplication helps in manipulating these vectors. Let's consider a 2D vector \( \begin{bmatrix} 4 \ -1 \end{bmatrix} \) from the problem. By executing matrix multiplication with the rotation matrix derived, we effectively alter its direction from the original orientation to a new one by the angle \( \pi/3 \). The new vector becomes \( \begin{bmatrix} 2.866 \ 2.964 \end{bmatrix} \). This transformation maintains the original vector's magnitude while modifying its direction within the 2D plane. By mastering the manipulation of 2D vectors, one gains insights into the dynamics of movement and the effects of directional changes in various scientific fields.
A 2D vector can be denoted in the form \( \begin{bmatrix} x \ y \end{bmatrix} \), where \( x \) and \( y \) are the components along the horizontal and vertical axes respectively.
When it comes to rotation, applying mathematical operations like matrix multiplication helps in manipulating these vectors. Let's consider a 2D vector \( \begin{bmatrix} 4 \ -1 \end{bmatrix} \) from the problem. By executing matrix multiplication with the rotation matrix derived, we effectively alter its direction from the original orientation to a new one by the angle \( \pi/3 \). The new vector becomes \( \begin{bmatrix} 2.866 \ 2.964 \end{bmatrix} \). This transformation maintains the original vector's magnitude while modifying its direction within the 2D plane. By mastering the manipulation of 2D vectors, one gains insights into the dynamics of movement and the effects of directional changes in various scientific fields.
Other exercises in this chapter
Problem 42
Write each system in matrix form. $$ \begin{array}{r} x_{1}-2 x_{2}+x_{3}=1 \\ -2 x_{1}+x_{2}-3 x_{3}=0 \end{array} $$
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Find the equation of the plane through \((3,-1,2)\) and perpendicular to \([-1,1,2]^{\prime} .\)
View solution Problem 43
Show that the inverse of $$ A=\left[\begin{array}{ll} 2 & 1 \\ 1 & 1 \end{array}\right] $$ is $$ B=\left[\begin{array}{rr} 1 & -1 \\ -1 & 2 \end{array}\right] $
View solution Problem 43
In Problems \(43-46\), find the parametric equation of the line in the \(x-y\) plane that goes through the indicated point in the direction of the indicated vec
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