Problem 42
Question
Two points charges \(+q_{1}\) and \(+q_{2}\) are placed at a certain distance apart, then: (a) they produce the same electric field on each other (b) they exert same forces on each other (c) for minimum force between them, the magnitude of each charge must be equal to \(1.6 \times 10^{-19} \mathrm{C}\) (d) all of the above
Step-by-Step Solution
Verified Answer
The correct answer is (b).
1Step 1: Understand the Context
We are given two positive point charges, \(+q_1\) and \(+q_2\), placed at a certain distance apart. The options suggest examining the electric field and forces between these charges.
2Step 2: Analyze Electric Fields
For option (a), consider the electric field. The electric field produced by a point charge \(q\) at a distance \(r\) is given by \(E = \frac{kq}{r^2}\) where \(k\) is Coulomb's constant. While \(+q_1\) and \(+q_2\) produce their respective electric fields, they do not produce the same field on each other unless \(q_1 = q_2\).
3Step 3: Evaluate the Forces Between Charges
For option (b), use Coulomb's Law: \(F = \frac{k |q_1 q_2|}{r^2}\). The force exerted by \(q_1\) on \(q_2\) and vice versa are equal in magnitude and opposite in direction according to Newton's third law, regardless of their values, thus option (b) is true.
4Step 4: Consider Conditions for Minimum Force
For option (c), according to Coulomb's Law, the force \(F\) decreases with decreasing values of the charges \(|q_1|\) and \(|q_2|\) or increasing distance \(r\). The statement about specific charge values \(1.6 \times 10^{-19} \mathrm{C}\) doesn't inherently minimize the force without context around distance \(r\).
5Step 5: Conclusion on the Correct Option
Option (b) is the only true statement here: the forces are always equal and opposite as per Newton's third law. Both other options involve conditions not always applicable.
Key Concepts
The Concept of Electric FieldNewton's Third Law and its ApplicationUnderstanding Point ChargesForces Between Charges and Coulomb's Law
The Concept of Electric Field
An electric field is a region around a charged object where a force would be exerted on other charged objects. For a point charge, the electric field is given by the formula: \[ E = \frac{kq}{r^2} \] where:
- \( E \) is the electric field,
- \( k \) is Coulomb's constant (approximately \( 8.988 \times 10^9 \, \text{Nm}^2/\text{C}^2 \)),
- \( q \) is the charge producing the field,
- \( r \) is the distance from the charge.
Newton's Third Law and its Application
Newton's third law is a fundamental principle that states: "For every action, there is an equal and opposite reaction." In the context of electrostatics, when a charge \( q_1 \) exerts a force \( F \) on charge \( q_2 \), \( q_2 \) simultaneously exerts an equal and opposite force \(-F \) on \( q_1 \).
This means:
This means:
- The magnitudes of these forces are identical.
- The directions are opposite.
Understanding Point Charges
Point charges are idealized charges that are assumed to be concentrated at a single point in space. This simplification allows us to more easily calculate electric fields and forces, as they disregard the complexities of the spatial extent of physical objects.
For two point charges like \( +q_1 \) and \( +q_2 \):
For two point charges like \( +q_1 \) and \( +q_2 \):
- They exist at specific locations.
- They generate electric fields in all directions.
- They interact with each other through these fields.
Forces Between Charges and Coulomb's Law
Forces between point charges are governed by Coulomb's Law, which is fundamental in understanding electrical interactions. Coulomb's Law is expressed as:\[ F = \frac{k |q_1 q_2|}{r^2} \]where:
- \( F \) is the force between the charges,
- \( k \) is Coulomb's constant,
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges,
- \( r \) is the separation distance between the charges.
- The magnitude of each charge — larger charges result in larger forces.
- The distance between charges — closer charges exert stronger forces.
- The sign of the charges — like charges repel, unlike charges attract.
Other exercises in this chapter
Problem 37
A particle having charge \(q\) and mass \(m\) is projected in uniform electric field \(E\) with speed \(u\) making angle \(\theta=30^{\circ}\) with electric fie
View solution Problem 40
A positive charge \(q\) is located at a point. What is the work done if an electron is carried once completely around this charge along a circle of radius \(r\)
View solution Problem 43
An electrostatic field \(E\) of magnitude \(10 \mathrm{~N} / \mathrm{C}\) is directed along positive \(x\) -axis. A point charge of \(10^{-6} \mathrm{C}\) is sh
View solution Problem 44
The electric field inside a conductor: (a) must be zero (b) may be non-zero (c) must be non-zero (d) (a) and (c) are correct
View solution