Problem 42
Question
The thrust, \(T,\) in pounds, of a ship's propeller is proportional to the square of the propeller speed, \(R\), in rotations per minute, times the fourth power of the propeller diameter, \(D,\) in feet. \(^{8}\) (a) Write a formula for \(T\) in terms of \(R\) and \(D\). (b) Solve for the propeller speed \(R\) in terms of the thrust \(T\) and the diameter \(D\). Write your answer in the form \(R=C T^{n} D^{m}\) for some constants \(C\), \(n,\) and \(m\). What are the values of \(n\) and \(m\) ? (c) Solve for the propeller diameter \(D\) in terms of the thrust \(T\) and the speed \(R\). Write your answer in the form \(D=C T^{n} R^{m}\) for some constants \(C, n,\) and \(m\). What are the values of \(n\) and \(m\) ?
Step-by-Step Solution
Verified Answer
Question: The thrust (T) of a ship's propeller is proportional to the square of the propeller speed (R) in rotations per minute, times the fourth power of the propeller diameter (D) in feet. Find the values n and m in the following expressions: \(R = C*T^{n}*D^{m}\) and \(D = C'*T^{n'}*R^{m'}\).
Answer: For the expression \(R = C*T^{n}*D^{m}\), the values of n and m are \(\frac{1}{2}\) and \(-2\), respectively. For the expression \(D = C'*T^{n'}*R^{m'}\), the values of n' and m' are \(\frac{1}{4}\) and \(-\frac{1}{2}\), respectively.
1Step 1: Write the formula for thrust, T
Since the thrust T is proportional to the square of the propeller speed R and the fourth power of the propeller diameter D, we can write the formula as:
\(T=kR^{2}D^{4},\) where k is the constant of proportionality.
2Step 2: Solve for R in terms of T and D
We want to find the formula for \(R\) in terms of \(T\) and \(D\). To do this, we can isolate \(R\) in the formula we just wrote by dividing both sides by \(kD^{4}\), we get:
\(R^{2} = \frac{T}{kD^{4}}\)
Now take the square root of both sides:
\(R =\sqrt{\frac{T}{kD^{4}}}\)
We can rewrite this as:
\(R = C*T^{n}*D^{m}\)
Where \(C = \frac{1}{\sqrt{k}}\), \(n = \frac{1}{2}\) and \(m = -2\). So the values of \(n\) and \(m\) are \(\frac{1}{2}\) and \(-2\) respectively.
3Step 3: Solve for D in terms of T and R
Now we want to find the formula for propeller diameter \(D\) in terms of thrust \(T\) and speed \(R\). To do this, we can use the same equation for thrust, divide both sides by \(kR^{2}\) and take the fourth root of both sides:
\(D^{4} = \frac{T}{kR^{2}}\)
Now take the fourth root of both sides:
\(D = \sqrt[4]{\frac{T}{kR^{2}}}\)
We can rewrite this as:
\(D = C*T^{n}*R^{m}\)
Where \(C = \frac{1}{\sqrt[4]{k}}\), \(n = \frac{1}{4}\) and \(m = -\frac{1}{2}\). So the values of \(n\) and \(m\) are \(\frac{1}{4}\) and \(-\frac{1}{2}\), respectively.
Key Concepts
ProportionalityPropeller SpeedPropeller DiameterMathematical Formulation
Proportionality
Proportionality is a simple yet crucial concept in physics and math. It describes how one quantity changes with respect to another. If two quantities are proportional, this means when one changes, the other changes in a consistent way, either increasing or decreasing in a predictable manner.
In the context of thrust calculation for propellers, the thrust, denoted as \(T\), is directly proportional to specific powers of the propeller's speed \(R\) and its diameter \(D\). This means:
In the context of thrust calculation for propellers, the thrust, denoted as \(T\), is directly proportional to specific powers of the propeller's speed \(R\) and its diameter \(D\). This means:
- An increase in propeller speed \(R\) leads to an increase in thrust \(T\), assuming the diameter \(D\) remains constant.
- Similarly, increasing the diameter \(D\) while keeping the speed \(R\) constant also results in a higher thrust \(T\).
Propeller Speed
Propeller speed \(R\) is an essential component in calculating thrust. This is because the speed at which a propeller rotates impacts how much force it can exert on the water, thereby affecting the vessel's ability to move.
When solving for \(R\) in terms of \(T\) (thrust) and \(D\) (diameter), understanding the relationship through proportionality becomes critical. From our initial equation \(T=kR^2D^4\), we rearrange to solve for \(R\) and find that:
When solving for \(R\) in terms of \(T\) (thrust) and \(D\) (diameter), understanding the relationship through proportionality becomes critical. From our initial equation \(T=kR^2D^4\), we rearrange to solve for \(R\) and find that:
- \(R = \sqrt{\frac{T}{kD^4}}\).
- \(n = \frac{1}{2}\)
- \(m = -2\)
Propeller Diameter
The propeller diameter \(D\) significantly influences the thrust a propeller can produce. A larger diameter generally means a propeller can move more water, resulting in higher force and speed capabilities.
When exploring how \(D\) relates to thrust \(T\) and propeller speed \(R\), you can see this by rearranging our primary formula to solve for \(D\). From \(T=kR^2D^4\), we derive:
When exploring how \(D\) relates to thrust \(T\) and propeller speed \(R\), you can see this by rearranging our primary formula to solve for \(D\). From \(T=kR^2D^4\), we derive:
- \(D = \sqrt[4]{\frac{T}{kR^2}}\).
- \(n = \frac{1}{4}\)
- \(m = -\frac{1}{2}\)
Mathematical Formulation
Mathematical formulation is the process of translating a physical situation into a mathematical equation. This translation allows us to use math to predict, analyze, and understand the interaction. In our exercise, the problem defined the relationship between thrust, propeller speed, and diameter.
Starting from the concept of proportionality, we derived the foundational equation for thrust \(T = kR^2D^4\). This formula indicates not only the relationships but how to solve for one variable when the others are known. Through mathematical formulation:
Starting from the concept of proportionality, we derived the foundational equation for thrust \(T = kR^2D^4\). This formula indicates not only the relationships but how to solve for one variable when the others are known. Through mathematical formulation:
- We determined how to equate \(R\) and \(D\) in terms of \(T\).
- The relationships are accommodated as \(R = \sqrt{\frac{T}{kD^4}}\) and \(D = \sqrt[4]{\frac{T}{kR^2}}\).
Other exercises in this chapter
Problem 41
Without solving them, say whether the equations in Exercises \(27-42\) have (i) One positive solution (ii) One negative solution (iii) One solution at \(x=0\) (
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What is the exponent of the given power function? Which of (I)-(IV) in Figure 7.18 best fits its graph? Assume all constants are positive. The average velocity,
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Without solving them, say whether the equations in Exercises \(27-42\) have (i) One positive solution (ii) One negative solution (iii) One solution at \(x=0\) (
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What is the exponent of the given power function? Which of (I)-(IV) in Figure 7.18 best fits its graph? Assume all constants are positive. The surface area, \(S
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