Problem 42
Question
The reaction of Problem \(13.40\) is run in the reverse direction \((\mathrm{P} \rightarrow \mathrm{R})\). (a) Is it exothermic or endothermic? (b) Calculate \(\Delta E_{\mathrm{rxn}} .\) (c) Is what you just said and calculated for (a) and (b) consistent with the definition of \(\Delta\) (any quantity) given in Problem \(13.41\) ? Explain.
Step-by-Step Solution
Verified Answer
We cannot determine if the reverse reaction (P → R) is exothermic or endothermic due to the lack of information about the forward reaction's enthalpy change, ΔH. Similarly, we cannot calculate ΔE_rxn for the reverse reaction without the values of ΔH and ΔS for the forward reaction. Consequently, we cannot verify if our solutions are consistent with the definition of Δ given in Problem 13.41.
1Step 1: (a) Identifying the Nature of the Reaction
To identify whether the reaction is exothermic or endothermic in the reverse direction (P → R), we need to look at the change in enthalpy (ΔH) of the forward reaction (R → P). If the forward reaction is exothermic (ΔH < 0), the reverse reaction will be endothermic (ΔH > 0) because the heat flows in the opposite direction. If the forward reaction is endothermic (ΔH > 0), the reverse reaction will be exothermic (ΔH < 0).
Since Problem 13.40 does not provide the ΔH value, we cannot determine if the reaction is exothermic or endothermic in the reverse direction.
2Step 2: (b) Calculating ΔErxn
In order to calculate ΔErxn for the reverse reaction (P → R), we need to know the enthalpy change (ΔH) and the entropy change (ΔS) for the forward reaction (R → P). Unfortunately, the problem statement does not provide these values, so we are unable to calculate ΔErxn for the reverse reaction.
3Step 3: (c) Verifying Consistency with Definition of Δ
Problem 13.41 provides the definition of Δ (any quantity) as the difference between the final state and the initial state. In parts (a) and (b), we were asked to identify the nature of the reverse reaction and to calculate ΔErxn. Since we did not have sufficient information to determine the reaction's nature or to calculate ΔErxn, we cannot verify whether our solutions are consistent with the definition of Δ given in Problem 13.41.
In summary, we were unable to identify if the reverse reaction is exothermic or endothermic, and we could not calculate ΔErxn due to the lack of provided information. Therefore, we cannot verify whether our solutions are consistent with the definition of Δ given in Problem 13.41.
Key Concepts
Understanding Exothermic ReactionsExploring Endothermic ReactionsEnthalpy Change: The Energy Signature of Reactions
Understanding Exothermic Reactions
Exothermic reactions are chemical processes that release energy to their surroundings. This energy is usually released in the form of heat. Such reactions result in a temperature increase in the environment. The enthalpy change, represented by \( \Delta H \), is negative for an exothermic process because the system loses heat as it progresses.
When considering a chemical equation, the reactants have more potential energy than the products. This excess energy is released, causing the environment to warm up.
When considering a chemical equation, the reactants have more potential energy than the products. This excess energy is released, causing the environment to warm up.
- Common examples include combustion reactions, like burning wood or fossil fuels.
- These reactions are often used in applications where heat generation is required, such as heaters and engines.
Exploring Endothermic Reactions
Endothermic reactions absorb energy from their surroundings, often in the form of heat. This absorption leads to a decrease in temperature in the immediate environment, making these reactions feel cool to the touch. In these reactions, the enthalpy change \( \Delta H \) is positive, indicating that the system has gained energy.
In endothermic reactions, the products have higher potential energy than the reactants. Energy must be supplied for these reactions to occur, typically making them non-spontaneous under normal conditions.
In endothermic reactions, the products have higher potential energy than the reactants. Energy must be supplied for these reactions to occur, typically making them non-spontaneous under normal conditions.
- Examples include photosynthesis, where plants absorb sunlight to convert carbon dioxide and water into glucose and oxygen.
- Other examples are the melting of ice and the cooking process where heat input is essential for food transformation.
Enthalpy Change: The Energy Signature of Reactions
Enthalpy change, \( \Delta H \), is a key concept in thermochemistry. It represents the heat content change during a chemical reaction at constant pressure. This change indicates whether a reaction is endothermic or exothermic.
Calculating enthalpy involves determining the energy stored in chemical bonds. When bonds break and form during a reaction, energy is either absorbed or released.
Overall, the concept of enthalpy change is central to designing processes in both laboratories and industrial scales, ensuring energy is effectively managed and utilized.
Calculating enthalpy involves determining the energy stored in chemical bonds. When bonds break and form during a reaction, energy is either absorbed or released.
- For an exothermic reaction, \( \Delta H \) is negative, meaning energy is released.
- For an endothermic reaction, \( \Delta H \) is positive as energy is absorbed.
Overall, the concept of enthalpy change is central to designing processes in both laboratories and industrial scales, ensuring energy is effectively managed and utilized.
Other exercises in this chapter
Problem 40
A reaction occurs in which 1 mole of \(\mathrm{A}\) is converted to 1 mole of \(B\). If 1 mole of \(A\) has an energy content of \(20 \mathrm{~kJ}\) and 1 mole
View solution Problem 41
\(\Delta\) (Any quantity) is always defined as (final value of quantity) - (initial value of quantity). Now consider the quantity \(\Delta E_{\mathrm{rxn}}\). (
View solution Problem 46
The value of \(\Delta E_{\mathrm{ryn}}\) for an exothermic reaction is always negative. (a) Why is this so in terms of \(E_{\text {reactants }}\) versus \(E_{\t
View solution Problem 47
For a particular chemical reaction, the absorbed energy is \(800 \mathrm{~kJ}\) to break old bonds, and \(400 \mathrm{~kJ}\) is released on forming new bonds. C
View solution