Problem 42
Question
The \(\mathrm{pH}\) of the neutralization point of \(0.1 \mathrm{~N}\) ammonium hydroxide with \(0.1 \mathrm{NHCl}\) is (a) 1 (b) 6 (c) 9 (d) 7
Step-by-Step Solution
Verified Answer
The \( \text{pH} \) is approximately 6, which is option (b).
1Step 1: Understanding the Neutralization Reaction
In this problem, we are dealing with the neutralization of ammonium hydroxide (a weak base) with HCl (a strong acid). The equation for the reaction is \( \text{NH}_4\text{OH} + \text{HCl} \rightarrow \text{NH}_4\text{Cl} + \text{H}_2\text{O} \). This forms ammonium chloride, which is slightly acidic in nature.
2Step 2: Determine the Nature of the Salt
Ammonium chloride (\( \text{NH}_4\text{Cl} \)) is a salt formed by a weak base and a strong acid. The solution of \( \text{NH}_4\text{Cl} \) will be acidic. Thus, the \( \text{pH} \) of the solution will be less than 7.
3Step 3: Calculate the pH at Neutralization
Since the reaction produces ammonium chloride, the solution tends to be acidic. Knowing that it's slightly acidic, the \( \text{pH} \) value is expected to be below 7. The most typical value for such a weak base and strong acid combination would be a \( \text{pH} \) of around 6.
Key Concepts
pH calculationacid-base reactionammonium chloride
pH calculation
pH calculation is essential when analyzing the acidity or basicity of a solution. For the neutralization of ammonium hydroxide ( \(\text{NH}_4\text{OH}\)) with hydrochloric acid (HCl), we need to consider the resulting salt. Neutralization typically yields a salt and water. Let's break down the steps in pH calculation:
- Understand the nature of the reactants and products. Here, a weak base reacts with a strong acid.
- Recognize that the salt formed, ammonium chloride ( \(\text{NH}_4\text{Cl}\)), makes the solution slightly acidic.
- Use the properties of acids and bases to estimate pH, where a pH below 7 indicates acidity.
acid-base reaction
In an acid-base reaction, an acid reacts with a base to form a salt and water. This is the essence of neutralization. With ammonium hydroxide ( \(\text{NH}_4\text{OH}\)) and hydrochloric acid (HCl), an interesting interaction occurs:
- The weak base, ammonium hydroxide, provides hydroxide ions (\(\text{OH}^-\)).
- Hydrochloric acid, a strong acid, provides hydrogen ions (\(\text{H}^+\)).
- The reaction forms water and a salt, ammonium chloride ( \(\text{NH}_4\text{Cl}\)).
ammonium chloride
Ammonium chloride ( \(\text{NH}_4\text{Cl}\)) is the salt resulting from the neutralization of ammonium hydroxide and hydrochloric acid. Ammonium chloride is notable for being slightly acidic, which influences the solutions in which it is dissolved.
When ammonium chloride dissolves in water, it dissociates into ammonium ions (\(\text{NH}_4^+\)) and chloride ions (\(\text{Cl}^-\)).
When ammonium chloride dissolves in water, it dissociates into ammonium ions (\(\text{NH}_4^+\)) and chloride ions (\(\text{Cl}^-\)).
- \(\text{NH}_4^+\) acts as a weak acid and can donate protons to the water, leading to a slight increase in the acidity of the solution.
- \(\text{Cl}^-\) does not contribute significantly to the pH as it is the conjugate base of a strong acid.
Other exercises in this chapter
Problem 40
The compound that is not a Lewis acid is (a) \(\mathrm{SnCl}_{4}\) (b) \(\mathrm{BeCl}_{2}\) (c) \(\mathrm{BF}_{3}\) (d) \(\mathrm{AlCl}_{3}\)
View solution Problem 41
The conjugate acid of \(\mathrm{NH}_{2}^{-}\)is (a) \(\mathrm{NH}_{4}^{+}\) (b) \(\mathrm{NH}_{3}\) (c) \(\mathrm{NH}_{2} \mathrm{OH}\) (d) \(\mathrm{N}_{2} \ma
View solution Problem 43
The compound whose \(0.1 \mathrm{M}\) solution is basic is (a) ammonium acetate (b) ammonium sulphate (c) sodium acetate (d) ammonium chloride
View solution Problem 44
Amongst the following hydroxides, the one which has the lowest value of \(K_{s p}\) at ordinary temperature (about \(\left.25^{\circ} \mathrm{C}\right)\) is (a)
View solution