Problem 42
Question
Solve using the square root property. Simplify all radicals. $$ 3 x^{2}+8=80 $$
Step-by-Step Solution
Verified Answer
x = \pm 2\sqrt{6}
1Step 1: Isolate the quadratic term
First, move the constant term to the other side by subtracting 8 from both sides of the equation: 3x^2 + 8 - 8 = 80 - 8 This simplifies to: 3x^2 = 72
2Step 2: Divide by the coefficient of the quadratic term
Next, divide both sides by 3 to isolate the squared term: \( \frac{3x^2}{3} = \frac{72}{3} \) This simplifies to: x^2 = 24
3Step 3: Apply the square root property
Now, apply the square root property, which states that if \(x^2 = a\), then \(x = \pm \sqrt{a}\): x = \pm\sqrt{24}
4Step 4: Simplify the radical
Finally, simplify \( \sqrt{24} \). Notice that 24 can be factored into 4 and 6, where 4 is a perfect square: x = \pm \sqrt{4 \cdot 6} x = \pm \sqrt{4} \cdot \sqrt{6} Since \( \sqrt{4} = 2 \), the simplified form is: x = \pm 2\sqrt{6}
Key Concepts
Square Root PropertySimplifying RadicalsIsolating the Quadratic Term
Square Root Property
The square root property is a powerful tool in solving quadratic equations.
It helps us deal directly with quadratic terms like \(x^2\).
When you have an equation of the form \(x^2 = a\), you can apply the square root to both sides of the equation.
This gives you two possible solutions because both the positive and negative roots of the term \(\text{square root of } a\) are valid.
In mathematical terms, if \(x^2 = a\), then \(x = \pm \sqrt{a}\).
This is very handy because it allows us to break down quadratic terms without having to expand or use more complicated methods.
It helps us deal directly with quadratic terms like \(x^2\).
When you have an equation of the form \(x^2 = a\), you can apply the square root to both sides of the equation.
This gives you two possible solutions because both the positive and negative roots of the term \(\text{square root of } a\) are valid.
In mathematical terms, if \(x^2 = a\), then \(x = \pm \sqrt{a}\).
This is very handy because it allows us to break down quadratic terms without having to expand or use more complicated methods.
Simplifying Radicals
Simplifying radicals is about breaking down square roots into their simplest form.
When you have a number under the square root sign that is not a perfect square, you can often simplify it by factoring.
For example, let's say you have \( \sqrt{24} \). At first, this may look unsimplifiable, but notice that 24 can be factored into 4 and 6.
Since 4 is a perfect square (\( 4 = 2^2 \)), we can write: \( \sqrt{24} = \sqrt{4 \cdot 6} \).
Further, since \( \sqrt{4} = 2 \), we simplify this to \( 2 \sqrt{6} \).
It's important to break down the number inside the square root into its prime factors and look for pairs of numbers to simplify.
When you have a number under the square root sign that is not a perfect square, you can often simplify it by factoring.
For example, let's say you have \( \sqrt{24} \). At first, this may look unsimplifiable, but notice that 24 can be factored into 4 and 6.
Since 4 is a perfect square (\( 4 = 2^2 \)), we can write: \( \sqrt{24} = \sqrt{4 \cdot 6} \).
Further, since \( \sqrt{4} = 2 \), we simplify this to \( 2 \sqrt{6} \).
It's important to break down the number inside the square root into its prime factors and look for pairs of numbers to simplify.
Isolating the Quadratic Term
To solve a quadratic equation, you often need to isolate the quadratic term first.
This means moving all other terms to one side of the equation so that you have your quadratic term alone on the other side.
For instance, in the equation \( 3x^2 + 8 = 80 \), we start by subtracting 8 from both sides to move the constant term:
\( 3x^2 = 72 \).
Next, you want to isolate \( x^2 \) by dividing both sides by the coefficient of \( x^2 \): \( \frac{{3x^2}}{{3}} = \frac{{72}}{{3}} \).
This simplifies to \( x^2 = 24 \).
By isolating the quadratic term, you simplify the equation, making it easier to apply the square root property and find your solution.
This means moving all other terms to one side of the equation so that you have your quadratic term alone on the other side.
For instance, in the equation \( 3x^2 + 8 = 80 \), we start by subtracting 8 from both sides to move the constant term:
\( 3x^2 = 72 \).
Next, you want to isolate \( x^2 \) by dividing both sides by the coefficient of \( x^2 \): \( \frac{{3x^2}}{{3}} = \frac{{72}}{{3}} \).
This simplifies to \( x^2 = 24 \).
By isolating the quadratic term, you simplify the equation, making it easier to apply the square root property and find your solution.
Other exercises in this chapter
Problem 41
Solve each equation. Check the solutions. \(2 x=\sqrt{11 x+3}\)
View solution Problem 42
Use the quadratic formula to solve each equation. (All solutions for these equations are non real complex numbers.) $$ z(2 z+3)=-2 $$
View solution Problem 42
Graph each parabola. Give the vertex, axis of symmetry, domain, and range. $$ f(x)=-2(x-2)^{2}-3 $$
View solution Problem 42
Solve each inequality, and graph the solution set. $$ \frac{20}{x-1} \geq 1 $$
View solution