Problem 42
Question
Solve the logarithmic equation for \(x.\) \(\log _{3}(2-x)=3\)
Step-by-Step Solution
Verified Answer
The solution is \( x = -25 \).
1Step 1: Understand the Logarithmic Equation
The given equation is \( \log _{3}(2-x) = 3 \). This means that \( 2-x \) is equal to \( 3^3 \). We need to solve for \( x \).
2Step 2: Convert the Logarithmic Equation to Exponential Form
The equation \( \log _{3}(2-x) = 3 \) can be rewritten in exponential form as \( 2-x = 3^3 \).
3Step 3: Simplify the Exponential Expression
Calculate \( 3^3 \), which is \( 27 \). So, the equation becomes \( 2-x = 27 \).
4Step 4: Solve the Linear Equation for x
Rearrange the equation \( 2-x = 27 \) to find \( x \). Subtract 2 from both sides to get \( -x = 27 - 2 \). This simplifies to \( -x = 25 \).
5Step 5: Isolate x
Multiply both sides of \( -x = 25 \) by \(-1\) to solve for \( x \). This gives \( x = -25 \).
Key Concepts
Exponential FormLinear EquationSolving Equations
Exponential Form
When dealing with logarithmic equations, one of the first steps is to convert the logarithmic expression into its exponential form. The logarithmic equation given is \( \log_{3}(2-x) = 3 \). This can be read as "the power you have to raise 3 to, in order to get \(2-x\), is 3."
To switch from logarithmic to exponential form, remember that \( \log_{b}(a) = c \) is equivalent to saying \( b^c = a \). For our problem, \( b \) is 3 and \( c \) is 3, thus:
Once in exponential form, the equation is easier to manipulate and solve, as it becomes a simple matter of evaluating powers and rearranging terms.
To switch from logarithmic to exponential form, remember that \( \log_{b}(a) = c \) is equivalent to saying \( b^c = a \). For our problem, \( b \) is 3 and \( c \) is 3, thus:
- Convert \( \log_{3}(2-x) = 3 \) to \( 3^3 = 2-x \).
Once in exponential form, the equation is easier to manipulate and solve, as it becomes a simple matter of evaluating powers and rearranging terms.
Linear Equation
After converting the logarithmic equation into the exponential form, the resulting equation is \( 2-x = 27 \). This is a straightforward linear equation, which is an equation involving no exponents and resembles the standard form \( ax + b = c \).
For this problem, our task is to isolate \( x \). A helpful strategy for solving linear equations involves rearranging terms:
For this problem, our task is to isolate \( x \). A helpful strategy for solving linear equations involves rearranging terms:
- Subtract constants from both sides of the equation first. Here, subtract 2 from both sides.
- Convert \( 2 - x = 27 \) into \( -x = 27 - 2 \).
Solving Equations
The key part of solving equations is to isolate the variable. After simplifying the exponential form and rearranging the linear equation to \( -x = 25 \), the final step is to solve for \( x \).
To isolate \( x \), we need to get rid of the negative sign. This is done by multiplying or dividing each side of the equation by the factor of the variable:
To isolate \( x \), we need to get rid of the negative sign. This is done by multiplying or dividing each side of the equation by the factor of the variable:
- Multiply each side by \(-1\): \(-x \times (-1) = 25 \times (-1)\).
- This operation results in \( x = -25 \).
Other exercises in this chapter
Problem 42
Sketch the graph of the function by plotting points. $$ g(x)=\log _{4} x $$
View solution Problem 42
\(29-43\) . These exercises deal with logarithmic scales. Comparing Decibel Levels The noise from a power mower was measured at 106 \(\mathrm{dB}\) . The noise
View solution Problem 42
\(19-44\) Use the Laws of Logarithms to expand the expression. $$ \log \sqrt{x \sqrt{y} \sqrt{z}} $$
View solution Problem 42
(a) Compare the rates of growth of the functions \(f(x)=3^{x}\) and \(g(x)=x^{4}\) by drawing the graphs of both functions in the following viewing rectangles:
View solution