Problem 42
Question
Sketch the graph of the given equation. Label the intercepts. $$y=0.3 x-2.1$$
Step-by-Step Solution
Verified Answer
Plot the y-intercept -2.1, use the slope 0.3 to plot another point, draw the line, and label intercepts at (0, -2.1) and (7, 0).
1Step 1: Understand the Equation
The given equation is in slope-intercept form: \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
2Step 2: Identify the Slope and Intercept
In the equation \( y = 0.3x - 2.1 \), the slope \( m \) is 0.3 and the y-intercept \( b \) is -2.1.
3Step 3: Plot the Y-Intercept
Start by plotting the y-intercept. Locate -2.1 on the y-axis and place a point there. This is the point (0, -2.1).
4Step 4: Use the Slope to Find Another Point
The slope of 0.3 means that for every 1 unit increase in \( x \), \( y \) increases by 0.3. Starting from (0, -2.1), move 1 unit to the right and 0.3 units up to plot the point (1, -1.8).
5Step 5: Draw the Line
Using a ruler, draw a straight line through the points (0, -2.1) and (1, -1.8). This line represents the graph of \( y = 0.3x - 2.1 \).
6Step 6: Find the X-Intercept
To find the x-intercept, set \( y = 0 \) and solve for \( x \). Solve \( 0 = 0.3x - 2.1 \) by isolating \( x \):\[0.3x = 2.1\] \[x = \frac{2.1}{0.3} \approx 7\]. The x-intercept is (7, 0).
7Step 7: Label the Intercepts
Label the points (0, -2.1) and (7, 0) as the y-intercept and x-intercept, respectively, on the graph.
Key Concepts
Slope-Intercept FormY-InterceptX-InterceptPlotting Points
Slope-Intercept Form
Slope-intercept form is a way of writing linear equations that makes it easy to graph them. The general form is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. This format allows us to quickly identify how steep a line is (slope) and where it crosses the y-axis (y-intercept). Understanding this form is crucial for graphing linear equations.
Y-Intercept
The y-intercept is the point where the line crosses the y-axis. In the equation \( y = 0.3x - 2.1 \), the y-intercept is -2.1, meaning the line crosses the y-axis at the point (0, -2.1). This point is significant because it serves as a starting point for plotting the line.
To plot the y-intercept, simply locate -2.1 on the y-axis and place a point there. This helps you anchor the graph and serves as a reference for drawing the rest of the line.
To plot the y-intercept, simply locate -2.1 on the y-axis and place a point there. This helps you anchor the graph and serves as a reference for drawing the rest of the line.
X-Intercept
The x-intercept is the point where the line crosses the x-axis. To find it, set \( y \) to 0 and solve for \( x \). In our example, we start with the equation \( 0 = 0.3x - 2.1 \). Solving for \( x \), we get:
\[ 0.3x = 2.1 \]
\[ x = \frac{2.1}{0.3} \ x \approx 7 \]
The x-intercept is (7, 0). This tells us that the line touches the x-axis at (7, 0). Label this point on your graph to make understanding easier.
\[ 0.3x = 2.1 \]
\[ x = \frac{2.1}{0.3} \ x \approx 7 \]
The x-intercept is (7, 0). This tells us that the line touches the x-axis at (7, 0). Label this point on your graph to make understanding easier.
Plotting Points
Plotting points is the process of graphing points on a coordinate plane to visualize a linear equation. Start by identifying key points like the intercepts. First, plot the y-intercept. In the equation \( y = 0.3x - 2.1 \), plot the point (0, -2.1).
Next, use the slope to find other points. The slope of 0.3 means for every 1 unit right, move 0.3 units up. From (0, -2.1), go 1 unit right and 0.3 units up to plot (1, -1.8).
Connect the points with a straight line. Repeat this for other points if needed. This visual representation aids in understanding the equation.
Next, use the slope to find other points. The slope of 0.3 means for every 1 unit right, move 0.3 units up. From (0, -2.1), go 1 unit right and 0.3 units up to plot (1, -1.8).
Connect the points with a straight line. Repeat this for other points if needed. This visual representation aids in understanding the equation.
Other exercises in this chapter
Problem 42
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