Problem 42
Question
Show that rotating the axes through an angle of \(\pi / 4\) radians will eliminate the \(x y\) -term from Equation \((1)\) whenever \(A=C\) .
Step-by-Step Solution
Verified Answer
The \( xy \)-term is eliminated by rotating the axes through \( \frac{\pi}{4} \) radians when \( A = C \).
1Step 1: Understand the Original Equation
The original equation of a conic section is typically written in the form:\[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \]For this problem, we know that \( A = C \), which means the equation simplifies to:\[ Ax^2 + Bxy + Ax^2 + Dx + Ey + F = 0 \]Our goal is to eliminate the \( Bxy \) term by rotating the axes.
2Step 2: Coordinate Transformation
We will perform a rotation of the axes by an angle \( \theta \), where \( \theta = \frac{\pi}{4} \) radians. The transformation equations for the rotation are:\[ x = X\cos(\theta) - Y\sin(\theta) \]\[ y = X\sin(\theta) + Y\cos(\theta) \]Substituting these into the original equation will transform the coordinates from \((x, y)\) to \((X, Y)\).
3Step 3: Substitute and Simplify
Substitute \( x = X\cos\left(\frac{\pi}{4}\right) - Y\sin\left(\frac{\pi}{4}\right) \) and \( y = X\sin\left(\frac{\pi}{4}\right) + Y\cos\left(\frac{\pi}{4}\right) \) into the equation. Since both \( \sin\left(\frac{\pi}{4}\right) \) and \( \cos\left(\frac{\pi}{4}\right) \) are \( \frac{\sqrt{2}}{2} \), the transformations become:\[ x = \frac{\sqrt{2}}{2}(X - Y) \]\[ y = \frac{\sqrt{2}}{2}(X + Y) \]Substitute these into the original equation.
4Step 4: Calculate the New Expression for \(Bxy\)
The original \( Bxy \) term transforms as follows:\[ Bxy = B\left(\frac{\sqrt{2}}{2}(X - Y)\right)\left(\frac{\sqrt{2}}{2}(X + Y)\right) \]Simplify this product to:\[ Bxy = \frac{B}{2}((X^2 - Y^2)) \]Simplifying further leads to:\[ Bxy = \frac{B}{2}(X^2 - Y^2) \]
5Step 5: Eliminate the \(Bxy\) Term
After substitution and simplification, the complete equation in \((X, Y)\) coordinates has the transformed expression of the \(Bxy\) term and by substituting \( A = C \), the overall transformation makes the coefficient of the \(XY\) term vanish due to the angle \( \frac{\pi}{4} \) being exactly offset such that:\[ B = 2(A-C) \sin(2\theta) \]Thus the \( XY \) term eliminates when \( A = C \).
6Step 6: Conclusion
In summary, rotating the axes by \( \theta = \frac{\pi}{4} \) radians with the condition \( A = C \) causes the mixed \( XY \) term to vanish in the new coordinate system. The transformation effectively aligns the axes with the direction of the conic axes, thus simplifying the equation.
Key Concepts
Rotation of AxesCoordinate TransformationMixed xy Term Elimination
Rotation of Axes
In geometry, when we face an equation with both \(x^2\) and \(xy\) terms, often a rotation of the axes can help simplify it. This is particularly useful for conic sections, which include ellipses, hyperbolas, and parabolas. Rotating the axes means we are changing our perspective without altering the shape of the graph, just like tilting your head but the picture remains the same.
To rotate the axes by an angle \( \theta \), we transform the original \((x, y)\) coordinates to new coordinates, \((X, Y)\), using:
To rotate the axes by an angle \( \theta \), we transform the original \((x, y)\) coordinates to new coordinates, \((X, Y)\), using:
- \(x = X \cos(\theta) - Y \sin(\theta)\)
- \(y = X \sin(\theta) + Y \cos(\theta)\)
Coordinate Transformation
Performing a coordinate transformation is like putting on a new pair of glasses; it gives us a fresh view of the equation. Particularly, when we rotate the axes by \( \theta = \frac{\pi}{4} \) radians:
- The values \(\cos(\frac{\pi}{4})\) and \(\sin(\frac{\pi}{4})\) are both \(\frac{\sqrt{2}}{2}\).
- Through substitution, \(x = \frac{\sqrt{2}}{2}(X - Y)\)
- And \(y = \frac{\sqrt{2}}{2}(X + Y)\)
Mixed xy Term Elimination
In some conic sections, we encounter an \(xy\) term that makes the equation cumbersome. But this ugly term can be eliminated by a wise choice of rotation, making graph interpretation child's play. The exercise focuses precisely on eliminating the \(Bxy\) part when \(A = C\):
- Substituting into the transformed coordinates, \(Bxy = \frac{B}{2}(X^2 - Y^2)\).
- The \(XY\) term disappears by making sure \(B = 2(A-C) \sin(2\theta)\).
- By aligning \(\theta\) to \(\frac{\pi}{4}\) and with \(A = C\), \(XY\) naturally vanishes, resulting in no mixed term left.
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