Problem 42
Question
Let \(p\) be the statement \(^{4} x\) is an irrational number", \(q\) be the statement "y is a transcendental number", and \(r\) be the statement " \(x\) is a rational number iff \(y\) is a transcendental number". \(\quad\) [2008] Statement-1: \(r\) is equivalent to either \(q\) or \(p\) Statement- \(2: r\) is equivalent to \(\sim(p \leftrightarrow \sim q)\). (a) Statement \(-1\) is false, Statement- 2 is true (b) Statement \(-1\) is true, Statement- 2 is true; Statement \(-2\) is a correct explanation for Statement- 1 (c) Statement \(-1\) is true, Statement- 2 is true; Statement \(-2\) is not a correct explanation for Statement-1 (d) Statement \(-1\) is true, Statement- 2 is false
Step-by-Step Solution
Verified Answer
Option (a): Statement 1 is false, Statement 2 is true.
1Step 1: Understand the Logical Statements
We start with understanding each statement. Statement 1 says "\(r\) is equivalent to either \(q\) or \(p\)" and Statement 2 claims "\(r\) is equivalent to \(\sim(p \leftrightarrow \sim q)\)". Here \(\sim\) denotes negation, \(\leftrightarrow\) denotes biconditional (if and only if), and \(\text{or}\) denotes alternative disjunction.
2Step 2: Analyze Statement 1
For statement 1, "\(r\) is equivalent to either \(q\) or \(p\)", we can write it as \(r \equiv q \vee r \equiv p\). The biconditional \(r: x \text{ is rational } \leftrightarrow y \text{ is transcendental}\) is simplified as \((x \text{ is rational } \wedge y \text{ is transcendental}) \vee (x \text{ is irrational } \wedge y \text{ is algebraic})\). We examine if \(r\) matches either \(p\) or \(q\).
3Step 3: Analyze Statement 2
Now look at Statement 2 in logical form: \(r \equiv \sim(p \leftrightarrow \sim q)\). Simplify \((p \leftrightarrow \sim q)\), which is equivalent to \((p \wedge q) \vee (\sim p \wedge \sim q)\), and \(r \equiv (\sim p \vee q) \wedge (p \vee \sim q)\). This is logically equivalent to \(r\).
4Step 4: Compare Statements
After analyzing both, check if Statement 1 and Statement 2 are formulas that evaluate to true or false separately. From the analysis, the expression obtained in Statement 2 indeed matches the expression derived from \(r\), proving Statement 2 to be true. However, from Statement 1, "r is equivalent to q or p" does not hold as true, because \(r\) matches \(\sim(p \leftrightarrow \sim q)\), not separately \(p\) or \(q\).
5Step 5: Conclusion Based on Analysis
To conclude, Statement 1 is false because \(r\) does not simplify solely to either \(p\) or \(q\). Statement 2 is true; \(r\) is equivalent to \(\sim(p \leftrightarrow \sim q)\). Statement 2 evaluates correctly but does not help in proving statement 1. Therefore, option (a) Statement 1 is false, Statement 2 is true.
Key Concepts
Biconditional StatementsNegation in LogicLogical Equivalence
Biconditional Statements
Biconditional statements are a crucial part of logical reasoning. They are represented by the symbol \( \leftrightarrow \), which reads as "if and only if". This type of statement is true only when both constituent statements are either true or false. Essentially, both must have the same truth value.
Imagine you have two statements, say \( p \) and \( q \). The biconditional statement \( p \leftrightarrow q \) asserts that \( p \) is true if \( q \) is true, and \( p \) is false if \( q \) is false.
Some key points about biconditional statements include:
Imagine you have two statements, say \( p \) and \( q \). The biconditional statement \( p \leftrightarrow q \) asserts that \( p \) is true if \( q \) is true, and \( p \) is false if \( q \) is false.
Some key points about biconditional statements include:
- The truth of the entire biconditional hinges on both statements agreeing in truth value.
- Biconditional is symmetric: \( p \leftrightarrow q \) is the same as \( q \leftrightarrow p \).
- Commonly used to show a direct correlation between两个 statements.
Negation in Logic
Negation is a fundamental concept in logical reasoning. It is denoted by the symbol \( \sim \), and implies reversing the truth value of a statement. If \( p \) is true, then \( \sim p \) is false, and vice versa.
To understand negation:
This alteration reflects how powerful negation can be in transforming a logical expression and deriving new insights.
To understand negation:
- Negating a true statement makes it false, and vice versa.
- It is commonly used to express the inverse of a given condition or expression.
- Negation can be applied to complex logical constructs, fundamentally altering their meaning.
This alteration reflects how powerful negation can be in transforming a logical expression and deriving new insights.
Logical Equivalence
Logical equivalence is a vital part of understanding logical relationships. Two statements are said to be logically equivalent if they always have the same truth value, no matter the circumstances.
There are a few crucial aspects to grasp regarding logical equivalence:
Logical equivalence was crucial in solving the exercise and pointing out the correct assessment of statements.
There are a few crucial aspects to grasp regarding logical equivalence:
- Equivalence allows us to transform complex statements into simpler or different forms, without changing their meaning.
- It often helps in proofs, particularly when we need to show that two statements lead to the same conclusion.
- Common techniques to prove equivalence include truth tables and various logical laws and rules.
Logical equivalence was crucial in solving the exercise and pointing out the correct assessment of statements.
Other exercises in this chapter
Problem 40
Statement- \(1: \sim(p \leftrightarrow \sim q)\) is equivalent to \(p \leftrightarrow q\). Statement- \(2: \sim(p \leftrightarrow \sim q)\) is a tantology (a) S
View solution Problem 41
The statement \(p \rightarrow(q \rightarrow p)\) is equivalent to (a) \(p \rightarrow(p \rightarrow q)\) (b) \(p \rightarrow(p \vee q)\) (c) \(p \rightarrow(p \
View solution Problem 43
Consider the statement: "For an integer \(\mathrm{n}\), if \(\mathrm{n}^{3}-1\) is even, then \(\mathrm{n}\) is odd." The contrapositive statement of this state
View solution Problem 44
The statement \((p \rightarrow(q \rightarrow p)) \rightarrow(p \rightarrow(p \vee q))\) is: (a) equivalent to \((p \wedge q) \vee(\sim q)\) (b) a contradiction
View solution