Problem 42
Question
In borax bead test which compound is formed (a) ortho borate (b) meta borate (c) double oxide (d) tetra borate
Step-by-Step Solution
Verified Answer
The compound formed in the borax bead test is meta borate.
1Step 1: Understanding Borax Bead Test
The borax bead test is a qualitative analysis method to identify transition metals. A metal salt is heated with borax which forms a glass-like bead. The color of the bead indicates the presence of certain metal ions.
2Step 2: Chemical Reaction
When borax \[ \text{Na}_2\text{B}_4\text{O}_7\cdot 10\text{H}_2\text{O} \] is heated, it loses water molecules and first converts to metaborate. \[ \text{Na}_2\text{B}_4\text{O}_7 \rightarrow 2\text{NaBO}_2 + \text{B}_2\text{O}_3 \] Thus forming sodium metaborate ( \( ext{NaBO}_2\)).
3Step 3: Compound Formed
The compound that is formed when borax is melted and used in the bead test is sodium metaborate. Therefore, the correct answer is (b) meta borate.
Key Concepts
Transition Metal IdentificationSodium Metaborate FormationQualitative Analysis Methods
Transition Metal Identification
The Borax Bead Test is a valuable technique used in qualitative analysis, particularly for identifying transition metals. This test involves exposing a small amount of borax, typically in the form of a bead, to a sample of metal salt. Upon heating in a flame, the borax fuses to form a glassy bead. The color relationship between the bead and the transition metals reveals their presence.
Transition metals are known for their striking colors and varied oxidation states, which is why the Borax Bead Test is so effective. Different metals will impart different colors to the bead, such as:
Transition metals are known for their striking colors and varied oxidation states, which is why the Borax Bead Test is so effective. Different metals will impart different colors to the bead, such as:
- Cobalt gives a blue bead.
- Chromium results in a green bead.
- Iron produces a yellow to brown bead.
Sodium Metaborate Formation
The transition of borax to sodium metaborate during the bead test is central to the chemical process. Borax itself, known chemically as \\( \text{Na}_2\text{B}_4\text{O}_7\cdot 10\text{H}_2\text{O} \), is a hydrated compound. Upon heating, it undergoes dehydration and subsequently breaks down.
This reaction can be represented as:
The sodium metaborate forms a viscous, glassy bead that will react with metal ions to display specific colors, assisting in the identification process.
This reaction can be represented as:
- Water molecules are driven off as it is heated.
- The remaining \\( \text{Na}_2\text{B}_4\text{O}_7 \) converts into \\( 2\text{NaBO}_2 + \text{B}_2\text{O}_3 \).
The sodium metaborate forms a viscous, glassy bead that will react with metal ions to display specific colors, assisting in the identification process.
Qualitative Analysis Methods
Qualitative analysis methods focus on identifying the components of a substance without quantifying them. The Borax Bead Test is a fine example of such a method, providing insights into the composition of metal ions based on visual cues.
These methods are invaluable in analytical chemistry for:
These methods are invaluable in analytical chemistry for:
- Identifying the presence of transition metals due to their unique color properties.
- Allowing quick testing, usually requiring minimal equipment beyond a simple flame and a support wire.
- Providing a relatively straightforward technique that doesn’t rely heavily on complex instrumentation.
Other exercises in this chapter
Problem 39
The gas that turns lime water milky is (a) \(\mathrm{SO}_{2}\) (b) \(\mathrm{CO}_{2}\) (c) both of these (d) none of these
View solution Problem 40
Which of the following is not a preliminary test used to detect ions (a) brown ring test (b) borax bead test (c) flame test (d) permanganate test
View solution Problem 43
\(\mathrm{Na}_{2} \mathrm{CO}_{3}\) cannot be used for identification of (a) \(\mathrm{S}^{2-}\) (b) \(\mathrm{SO}_{3}^{2-}\) (c) \(\mathrm{BO}_{3}^{3-}\) (d) \
View solution Problem 44
The \(\mathrm{Na}^{+}\)present in \(\mathrm{NaCl}\) is (a) acidic radical (b) basic radical (c) neutral radical (d) none of these
View solution