Problem 42
Question
If you have a parametric equation grapher, graph the equations over the given intervals. Hyperbola branch \(x=\sec t\) (enter as \(1 / \cos (t) ), y=\tan t\) (enter as \(\sin (t) / \cos (t) ),\) over $$\begin{array}{l}{\text { a. }-1.5 \leq t \leq 1.5} \\ {\text { b. }-0.5 \leq t \leq 0.5} \\ {\text { c. }-0.1 \leq t \leq 0.1}\end{array}$$
Step-by-Step Solution
Verified Answer
Graph each interval separately; they show segments of hyperbola with increasing detail.
1Step 1: Understand the given parametric equations
We're given parametric equations for a branch of a hyperbola: \( x = \sec t \) and \( y = \tan t \). In terms of sine and cosine functions, these equations can be expressed as \( x = \frac{1}{\cos t} \) and \( y = \frac{\sin t}{\cos t} \).
2Step 2: Identify the intervals
We are asked to graph the equations over three intervals for the parameter \( t \): a) \(-1.5 \leq t \leq 1.5\), b) \(-0.5 \leq t \leq 0.5\), c) \(-0.1 \leq t \leq 0.1\).
3Step 3: Graphing over Interval a
For \(-1.5 \leq t \leq 1.5\), plug in values of \( t \) within this range into the parametric equations. Note any restrictions where \( \cos t = 0 \) as these cause the equations to be undefined (e.g., the asymptotes of the hyperbola). Graph the resulting \( x, y \) values, more particularly, note the behavior of \( y \rightarrow \infty \) as \( \cos t \rightarrow 0 \).
4Step 4: Graphing over Interval b
For \(-0.5 \leq t \leq 0.5\), repeat the process, substitute values within this smaller interval into the parametric equations. Plot these on the graph and note that the curve is less spread out and closer to the center than in Step 3.
5Step 5: Graphing over Interval c
For \(-0.1 \leq t \leq 0.1\), this is an even smaller interval around zero. Evaluate the expressions for points in this interval and plot these coordinates. The resulting graph will show a segment of the hyperbola very close about the origin.
Key Concepts
HyperbolaInterval NotationGraphing
Hyperbola
A hyperbola is a type of conic section, distinguished by its two separate branches. It is defined as the set of all points for which the difference of the distances to two fixed points, called the foci, is constant. In our exercise, the parametric equations are given by \( x = \frac{1}{\cos t} \) and \( y = \frac{\sin t}{\cos t} \), corresponding to a hyperbolic curve. These equations use trigonometric identities to redefine standard hyperbolic functions:
- \( x = \sec t \) represents the reciprocal of cosine.
- \( y = \tan t \) is the ratio of sine and cosine.
Interval Notation
Interval notation is a mathematical notation used to describe a set of numbers lying between two endpoints. It effectively simplifies the expression of ranges or domains of variables involved in calculus and algebra problems. With interval notation:
- Brackets \([ ]\) indicate that an endpoint is included (closed interval).
- Parentheses \(( )\) mean an endpoint is not included (open interval).
Graphing
Graphing parametric equations such as \( x = \sec t \) and \( y = \tan t \) involves plotting points derived from these formulas over specified intervals. During graphing:
- Substitute values of \( t \) into the parametric equations to find corresponding \( x \) and \( y \) coordinates.
- Identify points where \( \cos t = 0 \), as these are where the hyperbola's graph is undefined (the asymptotes).
- Note how the graph becomes narrower and closer to the origin when the interval is smaller.
Other exercises in this chapter
Problem 41
You may wish to review Section 1.2 before solving Exercises \(39-56\) The ellipse \(\left(x^{2} / 16\right)+\left(y^{2} / 9\right)=1\) is shifted 4 units to the
View solution Problem 41
Replace the polar equations in Exercises \(27-52\) with equivalent Cartesian Replace the polar equations in Exercises \(27-52\) with equivalent Cartesian equati
View solution Problem 42
You may wish to review Section 1.2 before solving Exercises \(39-56\) The ellipse \(\left(x^{2} / 9\right)+\left(y^{2} / 25\right)=1\) is shifted 3 units to the
View solution Problem 42
$$ \text {a. Show that the Cartesian formula} $$ $$ L=\int_{c}^{d} \sqrt{1+\left(\frac{d x}{d y}\right)^{2}} d y $$ for the length of the curve \(x=g(y), c \leq
View solution