Problem 42
Question
If \(\alpha, \beta, \gamma\) are the roots of \(x^{3}+p x^{2}+2 x+p=0\), the general value of \(\tan ^{-1} \alpha+\tan ^{-1} \beta+\tan ^{-1} \gamma\) is (a) \(n \pi\) (b) \(n \pi / 2\) (c) \((2 n+1) \pi / 2\) (d) depend on \(p\).
Step-by-Step Solution
Verified Answer
The general value of \(\tan^{-1} \alpha + \tan^{-1} \beta + \tan^{-1} \gamma\) will depend on \( p \), therefore option (d) is correct.
1Step 1: Rearrangement and applying the formula of the sum of roots
The sum of the roots of the given cubic equation is \(-p\). So we have \(\alpha + \beta + \gamma = -p\). Taking arctangent on both sides we can write \(\tan^{-1} \alpha + \tan^{-1} \beta + \tan^{-1} \gamma = \tan^{-1}(-p)\).
2Step 2: Simplifying using the arctangent sum formula
From the beginners guide to trigonometry, the sum formula for the arctangent function of two angles \(a\) and \(b\) is given as: \(\tan^{-1} a + \tan^{-1} b = \tan^{-1} ((a + b) / (1 - a*b))\) unless \(a*b > 1\). In which case the sum is given by \(\tan^{-1} ((a + b) / (1 - a*b)) + \pi\). Simultaneously applying this formula for \(\tan^{-1} \alpha + \tan^{-1} \beta + \tan^{-1} \gamma\), the goal would be to simplify to \(\tan^{-1} (-p)\).
3Step 3: Determine the conditions under which the equation is true
In order to determine the relation between \( n \pi \), \( n \pi / 2 \), \( (2 n + 1) \pi / 2 \) and \( p \), we will substitute each of the values for each option to find the one that makes our equation true.
Key Concepts
Sum of RootsArctangent FunctionTrigonometric Identities
Sum of Roots
In a cubic equation like \(x^3 + px^2 + 2x + p = 0\), the sum of the roots \(\alpha, \beta,\) and \(\gamma\) can be calculated using Vieta’s formulas. Let's break this down! Vieta’s formulas state that the sum of the roots, for a polynomial equation of the form \(ax^3 + bx^2 + cx + d = 0\), is given by \(-\frac{b}{a}\). Here, since \(a = 1\) and \(b = p\), the sum of the roots becomes \(-p\). This means that:
Remember, this can be a powerful tool when you tackle quadratic, cubic, or any polynomial equation, allowing you to grasp more complex algebraic sums and relations easily.
- \(\alpha + \beta + \gamma = -p\)
Remember, this can be a powerful tool when you tackle quadratic, cubic, or any polynomial equation, allowing you to grasp more complex algebraic sums and relations easily.
Arctangent Function
The arctangent function, also known as the inverse tangent function, is denoted by \(\tan^{-1} x\). This function is crucial when dealing with trigonometric identities involving angles. The expression \(\tan^{-1} \alpha + \tan^{-1} \beta + \tan^{-1} \gamma\) refers to the combined angle of the roots taken in inverse tangent form.
To simplify expressions of this type, we often use the arctangent sum formula:
Understanding this function's role and manipulation is fundamental in problems where trigonometric identities are used to simplify angles and expressions.
To simplify expressions of this type, we often use the arctangent sum formula:
- \( \tan^{-1} a + \tan^{-1} b = \tan^{-1} \left( \frac{a + b}{1 - ab} \right) \)\
- If \(ab > 1\), then we add \( \pi \) to the result.
Understanding this function's role and manipulation is fundamental in problems where trigonometric identities are used to simplify angles and expressions.
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are universally true. When dealing with the sum of inverse tangent expressions like \(\tan^{-1} \alpha + \tan^{-1} \beta + \tan^{-1} \gamma\), these identities become powerful tools to simplify complex expressions.
One commonly used identity is the arctangent sum formula. This identity helps you transform a complex angle sum into a simpler form:
In practical applications, especially in exams or problem-solving, mastering these identities provides a quick path to solutions that might otherwise take much longer to compute or guess.
One commonly used identity is the arctangent sum formula. This identity helps you transform a complex angle sum into a simpler form:
- \(\tan^{-1} a + \tan^{-1} b = \tan^{-1} \left( \frac{a + b}{1 - ab} \right)\),
- possibly adding \(\pi\) if \(ab > 1\).
In practical applications, especially in exams or problem-solving, mastering these identities provides a quick path to solutions that might otherwise take much longer to compute or guess.
Other exercises in this chapter
Problem 41
If \(\alpha\) is the only real root of the equation \(x^{3}+b x^{2}+c x+1=0(b
View solution Problem 42
If \(A=2 \tan ^{-1}(2 \sqrt{2}-1)\) and \(B=3 \sin ^{-1}\left(\frac{1}{3}\right)+\sin ^{-1}\left(\frac{3}{5}\right)\), then prove that \(A>B\).
View solution Problem 45
If \(\sin ^{-1}\left(\frac{\sqrt{x}}{2}\right)+\sin ^{-1}\left(\sqrt{1-\frac{y}{4}}\right)+\tan ^{-1} y=\frac{2 \pi}{3}\) then find the maximum value of \(\left
View solution Problem 46
Find the number of integral ordered pairs \((x, y)\) satisfying the equation \(\tan ^{-1}\left(\frac{1}{x}\right)+\tan ^{-1}\left(\frac{1}{y}\right)=\tan ^{-1}\
View solution