Problem 42
Question
If adj \(B=A\) and \(P, Q\) are two unimodular matrices, i.e., \(|P|=1=|Q|\), then \(\left(Q^{-1} B P^{-1}\right)^{-1}\) is equal to (A) \(P A Q\) (B) \(P B Q\) (C) \(Q A P\) (D) \(Q B P\)
Step-by-Step Solution
Verified Answer
(A) \(P A Q\)
1Step 1: Understand the Given Information
We are given that \( \text{adj} \, B = A \) and \( P \text{ and } Q \) are unimodular matrices, meaning \( |P| = 1 \) and \( |Q| = 1 \). We have to find the expression for \( \left(Q^{-1} B P^{-1}\right)^{-1} \).
2Step 2: Work with Matrix Inverses
Recall that the inverse of a product of matrices can be expressed by reversing their order and taking the inverse of each. Therefore, \( \left(Q^{-1} B P^{-1}\right)^{-1} = P B^{-1} Q \).
3Step 3: Substitute \( \text{adj} \, B = A \)
Since \( \text{adj} \, B = A \), we know that \( B^{-1} = \frac{1}{\det(B)}A \), given that \( B \cdot \text{adj} \, B = \det(B)I \). However, \( B \) should be invertible, implying \( B^{-1} \cdot B = I \). Thus, we conclude \( B^{-1} = A \), since \( \det(B)=1 \) for \( \text{adj}\, B = A \).
4Step 4: Substituting into the Matrix Expression
Substitute \( B^{-1} = A \) (considering \( \det(B)=1 \)) and substitute back into the expression: \( \left(Q^{-1} B P^{-1}\right)^{-1} = P A Q\).
5Step 5: Conclusion
The simplified expression \( P A Q \) corresponds to option (A) in the given answer choices.
Key Concepts
Unimodular MatrixAdjugate MatrixMatrix Inverse
Unimodular Matrix
A unimodular matrix is a fascinating concept in the world of matrix algebra. Essentially, a matrix is considered unimodular if its determinant is either +1 or -1.
- Property of Inverses: Unimodular matrices have a unique feature: they are invertible, and their inverses are also unimodular matrices.
- Determinant: The determinant of a unimodular matrix remains constant under multiplication with another unimodular matrix, specifically being either +1 or -1.
- Effect on Volume: In a geometrical sense, the transformation represented by a unimodular matrix does not alter the volume of the space it acts upon.
Adjugate Matrix
The adjugate matrix, often symbolized as \( \text{adj} \, B \), plays an important role in finding inverses of matrices. It is essentially the transpose of the cofactor matrix of \(B\).
- Role in Inversion: If \( \det(B) eq 0\), the inverse of a matrix \(B\) can be calculated using its adjugate with the formula: \( B^{-1} = \frac{1}{\det(B)} \text{adj} \, B \).
- Connection to Determinant: The adjugate matrix provides a pivotal relationship between a matrix and its determinant, being a core component in expressing the inverse.
- Exercise Example: Given \( \text{adj} \, B = A \), we derive that \( B^{-1} = A \) because for \( \text{adj} \, B = A \), the assumption here is \( \det(B) = 1 \).
Matrix Inverse
Finding a matrix inverse is a foundational operation in linear algebra. A matrix \(B\) is invertible if there exists another matrix, \(B^{-1}\), such that the product \(B B^{-1} = I\), where \(I\) is the identity matrix.
- Calculation: As previously mentioned, if \( \det(B) eq 0\), the inverse of \(B\) can be neatly found as \( B^{-1} = \frac{1}{\det(B)} \text{adj} \, B \).
- Properties: Matrix inverses exhibit properties like \( (AB)^{-1} = B^{-1}A^{-1} \), crucial for simplifying expressions involving multiple matrices.
- Exercise Insight: The exercise leverages the property of inverses to transform \( \left(Q^{-1} B P^{-1}\right)^{-1} \) into \( P A Q \), utilizing the traits of the given matrices and known relationships, simplifying it further to match the option (A).
Other exercises in this chapter
Problem 40
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