Problem 42
Question
Graph each polar equation for \(\theta\) in \(\left[0^{\circ}, 360^{\circ}\right)\). In Exercises \(39-48\), identify the rype of polar graph. $$r=2-\cos \theta$$
Step-by-Step Solution
Verified Answer
The graph is a limaçon with a dimple, described by \( r = 2 - \cos \theta \).
1Step 1: Understand the Equation
The given polar equation is \( r = 2 - \cos \theta \). This is a type of limaçon equation, a general form of \( r = a - b \cos \theta \). This specific form, where \( a > b \), typically results in a limaçon with an inner loop.
2Step 2: Determine Key Points
Determine some key points by substituting values for \( \theta \):ewline- When \( \theta = 0^{\circ} \), \( r = 2 - \cos 0^{\circ} = 1 \).ewline- When \( \theta = 90^{\circ} \), \( r = 2 - \cos 90^{\circ} = 2 \).ewline- When \( \theta = 180^{\circ} \), \( r = 2 - \cos 180^{\circ} = 3 \).ewline- When \( \theta = 270^{\circ} \), \( r = 2 - \cos 270^{\circ} = 2 \).ewline- When \( \theta = 360^{\circ} \), \( r = 2 - \cos 360^{\circ} = 1 \).
3Step 3: Analyze the Graph Shape
Since \( r = 2 - \cos \theta \) is of the form \( r = a - b \cos \theta \) with \( a = 2 \) and \( b = 1 \), the graph will be a limaçon without an inner loop but rather a dimple, since \( a > b \).
4Step 4: Draft the Polar Graph
1. Start at the initial point where \( \theta = 0^{\circ} \) and \( r = 1 \).2. At \( \theta = 90^{\circ} \), the point \( r = 2 \) lies further out from the pole.3. The maximum value occurs at \( \theta = 180^{\circ} \) with \( r = 3 \).4. At \( \theta = 270^{\circ} \), \( r \) returns to 2.5. Complete the cycle as \( \theta \) approaches \( 360^{\circ} \), going back to \( r = 1 \).Join these points in a continuous curve, reflecting the shape of a dimpled limaçon.
5Step 5: Confirm Type of Polar Graph
By observing the points and continuous path, it's clear that the graph is a limaçon with a dimple, which is typical for the cases where \( a > b \) in the equation \( r = a - b \cos \theta \).
Key Concepts
Understanding LimaçonsRole of Trigonometric FunctionsGraphing on the Polar Coordinate System
Understanding Limaçons
Limaçons are intriguing shapes formed by certain polar equations. A polar equation like \( r = 2 - \cos \theta \) creates a limaçon. These curves can take various forms depending on the relation between the constants \( a \) and \( b \) in the general equation \( r = a - b \cos \theta \) or \( r = a - b \sin \theta \).
One common feature of limaçons is that they can appear as a dimpled shape, have an inner loop, or be convex.
One common feature of limaçons is that they can appear as a dimpled shape, have an inner loop, or be convex.
- If \( a > b \), as in our equation with \( a = 2 \) and \( b = 1 \), the limaçon will have a dimple but no inner loop.
- If \( a = b \), you'll get a cardioid shape.
- If \( a < b \), the curve features an inner loop.
Role of Trigonometric Functions
Trigonometric functions like sine and cosine are foundational in polar equations. In the equation \( r = 2 - \cos \theta \), the trigonometric function \( \cos \theta \) dictates how the radius \( r \) changes as the angle \( \theta \) varies.
Cosine function is periodic, ranging from -1 to 1. This periodicity causes the radius \( r \) to vary depending on the angle \( \theta \), leading to the cyclical nature of polar graphs.
Cosine function is periodic, ranging from -1 to 1. This periodicity causes the radius \( r \) to vary depending on the angle \( \theta \), leading to the cyclical nature of polar graphs.
- When \( \theta = 0^{\circ} \), \( \cos \theta \) is at its maximum (1), so r is smaller.
- As \( \theta \) approaches \( 180^{\circ} \), \( \cos \theta \) reaches its minimum (-1), maximizing \( r \).
- when \( \theta = 90^{\circ}\) or \( 270^{\circ} \), \( \cos \theta \) is zero, reflecting the mid-range value of \( r \).
Graphing on the Polar Coordinate System
Polar graphing requires plotting points based on their angle and distance from the origin, called the pole. It's different from Cartesian graphing, which uses x and y coordinates.
For the limaçon equation \( r = 2 - \cos \theta \):
For the limaçon equation \( r = 2 - \cos \theta \):
- You start by plotting points where \( \theta \) is at key angles, such as \( 0^{\circ}, 90^{\circ}, 180^{\circ}, 270^{\circ}, \) and \( 360^{\circ} \).
- With \( \theta = 0^{\circ} \), the point is closer to the pole because \( r = 1 \).
- At \( \theta = 180^{\circ} \), the point is farthest from the pole with \( r = 3 \).
- As you map these points, draw a smooth curve connecting them to reflect the continuous nature of the limaçon.
Other exercises in this chapter
Problem 41
Refer to the guidelines to solve oblique triangles to decide on the procedure to use to solve each triangle. Then solve the triangle. \(a=51.41, b=37.29, c=65.8
View solution Problem 42
Graph each pair of parametric equations for \(0 \leq t \leq 2 \pi\) in the window \([0,6.6]\) by \([0,4.1] .\) Identify the letter of the alphabet that is being
View solution Problem 42
Write each complex number in rectangular form. Give exact values for the real and imaginary parts. Do not use a calculator. $$6 \text { cis } \frac{3 \pi}{4}$$
View solution Problem 42
Solve triangle. There may be two, one, or no such triangle. $$B=48.2^{\circ}, a=890 \text { centimeters, } b=697 \text { centimeters }$$
View solution