Problem 42
Question
Given that \( \displaystyle \int^{\pi}_0 \sin ^4x \, dx = \frac{3}{8} \pi \), what is \( \displaystyle \int^0_{\pi} \sin ^4\theta \, d\theta \)?
Step-by-Step Solution
Verified Answer
The value of \( \int^0_{\pi} \sin^4 \theta \, d\theta \) is \( -\frac{3}{8} \pi \).
1Step 1: Understanding the Problem
We are given the integral \( \int^{\pi}_0 \sin ^4x \, dx = \frac{3}{8} \pi \). We need to find the value of the integral \( \int^0_{\pi} \sin ^4\theta \, d\theta \). Notice the order of integration limits is reversed.
2Step 2: Reversing the Integration Limits
In general, reversing the limits of an integral changes the sign of the integral. Therefore, we use the property: \( \int^b_a f(x) \, dx = -\int^a_b f(x) \, dx \). Applying this property to our integral: \( \int^0_{\pi} \sin^4 \theta \, d\theta = -\int^{\pi}_0 \sin^4 x \, dx \).
3Step 3: Substituting the Given Integral Value
We can substitute the known value of the integral: \( -\int^{\pi}_0 \sin^4 x \, dx = -\frac{3}{8} \pi \).
4Step 4: Conclusion of the Calculation
The integral \( \int^0_{\pi} \sin^4 \theta \, d\theta \) is equal to \( -\frac{3}{8} \pi \).
Key Concepts
Integration LimitsIntegral PropertiesTrigonometric Integrals
Integration Limits
When you're dealing with definite integrals, the integration limits are crucial. They define the range over which the function is integrated.
It’s like setting the start and end points for a journey along the curve of the function.Let's consider how they work:
This rule is handy when you encounter reversed limits in a problem. Just remember that flipping the limits flips the sign of the integral.
It’s like setting the start and end points for a journey along the curve of the function.Let's consider how they work:
- If you have limits from \(a\) to \(b\), you're integrating from \(a\) to \(b\).
- Reversing these limits, from \(b\) to \(a\), flips the direction. This affects the integral's sign.
This rule is handy when you encounter reversed limits in a problem. Just remember that flipping the limits flips the sign of the integral.
Integral Properties
Understanding the properties of integrals can make solving problems much easier. Integrals come with a handy set of rules that can simplify calculations.
Here are a few key properties:
Here are a few key properties:
- Linearity: You can split integrals across the addition or subtraction of functions. For example, \( \int (f(x) + g(x)) \, dx = \int f(x) \, dx + \int g(x) \, dx \).
- Scalar Multiplication: A constant factor can be moved outside the integral. For example, \( \int a\cdot f(x) \, dx = a\int f(x) \, dx \).
- Reversed Limits: Flipping the integration limits changes the sign of the integral, as seen in our problem.
Trigonometric Integrals
Trigonometric integrals involve trigonometric functions such as sine or cosine. These types of integrals are common in calculus, and solving them often requires specific strategies.
Here are some key points to note:
Mastering these techniques and understanding the behavior of trigonometric functions can make solving such integrals straightforward.
Here are some key points to note:
- Trigonometric functions are periodic, meaning they repeat values in a regular pattern. This can influence the limits you choose.
- Use identities like \( \sin^2(x) + \cos^2(x) = 1 \) to simplify the integrals when possible.
- Common techniques for solving trigonometric integrals include substitution and using specific integral formulas.
Mastering these techniques and understanding the behavior of trigonometric functions can make solving such integrals straightforward.
Other exercises in this chapter
Problem 42
Evaluate the integral. \( \displaystyle \int^{2}_{1} \frac{(x - 1)^3}{x^2} \,dx \)
View solution Problem 42
Evaluate the integral. \( \displaystyle \int^{1/\sqrt{2}}_{1/2} \frac{4}{\sqrt{1 - x^2}} \,dx \)
View solution Problem 43
Evaluate the indefinite integral. \( \displaystyle \int \frac{dx}{\sqrt{1 - x^2} \sin^{-1} x} \)
View solution Problem 43
Evaluate the integral. \( \displaystyle \int^{1/\sqrt{3}}_{0} \frac{t^2 - 1}{t^4 - 1} \,dt \)
View solution